
GCSE Grade Descriptors - School
... Use of Pythagoras’ Theorem and trigonometry Carrying out constructions, e.g. triangles in all situations Solving problems involving polygons, e.g. interior angles Understanding, using and solving problems with bearings ...
... Use of Pythagoras’ Theorem and trigonometry Carrying out constructions, e.g. triangles in all situations Solving problems involving polygons, e.g. interior angles Understanding, using and solving problems with bearings ...
Week 3. Functions: Piecewise, Even and Odd.
... Recall that a function is a rule that maps values from one set to another. In this course, we are mainly concerned with functions f : D → R, where D ⊆ R. Given the formula for a function f, we frequently have to figure out: • What is the domain of f? (The domain of f is the set of all ...
... Recall that a function is a rule that maps values from one set to another. In this course, we are mainly concerned with functions f : D → R, where D ⊆ R. Given the formula for a function f, we frequently have to figure out: • What is the domain of f? (The domain of f is the set of all ...
radii: AP , PR,PB diameter: AB chords: AB , CD, AF secant: AG or AG
... You will need to understand units, fractions and multiplication of fractions to get a grip on this section. (P.S. You’ll thank me later when you take Chemistry too!!) Concept 1: You may divide out common factors when multiplying fractions…before actually multiplying the numerators and then the denom ...
... You will need to understand units, fractions and multiplication of fractions to get a grip on this section. (P.S. You’ll thank me later when you take Chemistry too!!) Concept 1: You may divide out common factors when multiplying fractions…before actually multiplying the numerators and then the denom ...
Grade_7_Math-a-thon_Study_Guide
... in the set given more than once. Therefore, the mode is equal to 50º . Step 5: Compare the four values to determine which has the lowest value and is the most appropriate. In this case, the lowest value was 28 which was the range, but the range is not the most appropriate measure to use because it i ...
... in the set given more than once. Therefore, the mode is equal to 50º . Step 5: Compare the four values to determine which has the lowest value and is the most appropriate. In this case, the lowest value was 28 which was the range, but the range is not the most appropriate measure to use because it i ...
Revised Version 070216
... By examining the perpendicular bisectors of the sides of a polygon, one can determine conditions that are sufficient to conclude that a circle can circumscribe the polygon. If one can circumscribe a circle about a polygon, the polygon is called a cyclic polygon. Thus, since one can circumscribe a ci ...
... By examining the perpendicular bisectors of the sides of a polygon, one can determine conditions that are sufficient to conclude that a circle can circumscribe the polygon. If one can circumscribe a circle about a polygon, the polygon is called a cyclic polygon. Thus, since one can circumscribe a ci ...