No Slide Title
... A 0.5 kg ball is dropped to the floor from a height of 2 m. If it bounces back to a height of 1.8 m, what is the magnitude of its change in momentum? Some energy is lost in the bounce. Just before it hits the ground, its velocity is: (use conservation of ME) mgh=1/2mv2 so v=(2gh)=(2*9.8*2)= 6.26 m ...
... A 0.5 kg ball is dropped to the floor from a height of 2 m. If it bounces back to a height of 1.8 m, what is the magnitude of its change in momentum? Some energy is lost in the bounce. Just before it hits the ground, its velocity is: (use conservation of ME) mgh=1/2mv2 so v=(2gh)=(2*9.8*2)= 6.26 m ...
Rotation
... Up until now we have been looking at the kinematics and dynamics of translational motion – that is, motion without rotation. Now we will widen our view of the natural world to include objects that both rotate and translate. ...
... Up until now we have been looking at the kinematics and dynamics of translational motion – that is, motion without rotation. Now we will widen our view of the natural world to include objects that both rotate and translate. ...
6-2 Equilibrium
... 6-7 Calculating the Rotational Inertia ★ Proof of the Parallel-Axis Theorem Let O be the center of mass of the arbitrary shaped body. Consider an axis through O perpendicular to the plane, and another axis through point P parallel to the first axis. Let dm be a mass element with the general coordin ...
... 6-7 Calculating the Rotational Inertia ★ Proof of the Parallel-Axis Theorem Let O be the center of mass of the arbitrary shaped body. Consider an axis through O perpendicular to the plane, and another axis through point P parallel to the first axis. Let dm be a mass element with the general coordin ...
Impulse and Momentum
... equal velocity. This is known as the period of deformation. Following this, the particles will either remain deformed, or return to their original shape, referred to as the period of restitution. These are demonstrated below. ...
... equal velocity. This is known as the period of deformation. Following this, the particles will either remain deformed, or return to their original shape, referred to as the period of restitution. These are demonstrated below. ...
141S13-NotesCh6a-June04
... It’s worth noting that linear momentum is often referred to simply as “momentum”. We will try to avoid this lazy terminology, since there is another type of momentum (angular momentum), which we will cover in the next chapter. We will often need to find the total linear momentum P of a system of sev ...
... It’s worth noting that linear momentum is often referred to simply as “momentum”. We will try to avoid this lazy terminology, since there is another type of momentum (angular momentum), which we will cover in the next chapter. We will often need to find the total linear momentum P of a system of sev ...
ISNS3371_012507_bw - The University of Texas at Dallas
... momentum of a system remains constant. Newton’s Third Law of Rotation Motion: For every torque that one object exerts on a second object, there is an equal but oppositely directed torque that the second object exerts on the first object. ...
... momentum of a system remains constant. Newton’s Third Law of Rotation Motion: For every torque that one object exerts on a second object, there is an equal but oppositely directed torque that the second object exerts on the first object. ...
Physics 207: Lecture 2 Notes
... x-direction: No net force so Px is conserved. y-direction: Net force, interaction with the ground so depending on the system (i.e., do you include the Earth?) Py is not conserved (system is block and cart only) ...
... x-direction: No net force so Px is conserved. y-direction: Net force, interaction with the ground so depending on the system (i.e., do you include the Earth?) Py is not conserved (system is block and cart only) ...
Today`s Powerpoint
... However, in this class, you will be time limited on midterms What can you do? • Make sure you know and understand key concepts so you can apply them quickly and correctly • Practice doing homework problems with good solutions for time => this week, take 30 minutes, next week 25 minutes, next 20 minu ...
... However, in this class, you will be time limited on midterms What can you do? • Make sure you know and understand key concepts so you can apply them quickly and correctly • Practice doing homework problems with good solutions for time => this week, take 30 minutes, next week 25 minutes, next 20 minu ...
PHYS 1443 – Section 501 Lecture #1
... 1. Hang the object by one point and draw a vertical line following a plum-bob. 2. Hang the object by another point and do the same. 3. The point where the two lines meet is the CM. Since a rigid object can be considered as collection of small masses, one can see the total gravitational force exerted ...
... 1. Hang the object by one point and draw a vertical line following a plum-bob. 2. Hang the object by another point and do the same. 3. The point where the two lines meet is the CM. Since a rigid object can be considered as collection of small masses, one can see the total gravitational force exerted ...
HW7
... As can be seen from the diagram, the component of the force of gravity that is perpendicular to the rod is mg sin . If is the length of the rod, then the torque associated with this force has magnitude mg sin (0.75)(9.8)(1.25) sin 30 4.6 N m . For the position shown, the torque is co ...
... As can be seen from the diagram, the component of the force of gravity that is perpendicular to the rod is mg sin . If is the length of the rod, then the torque associated with this force has magnitude mg sin (0.75)(9.8)(1.25) sin 30 4.6 N m . For the position shown, the torque is co ...
PHY 1114: Physics I Practice Problem Think about it
... barbell is held stationary in this position? b. What is the force exerted by the elbow on the forearm bones? ...
... barbell is held stationary in this position? b. What is the force exerted by the elbow on the forearm bones? ...
9-1 Momentum and Its Relation to Force Example 9
... 7. Solve. 8. Check units and magnitudes of result. ...
... 7. Solve. 8. Check units and magnitudes of result. ...
ISNS3371_012307_bw
... carpet, the impact time is extended as the glass sinks into the carpet - impact force reduced - glass doesn’t break. ...
... carpet, the impact time is extended as the glass sinks into the carpet - impact force reduced - glass doesn’t break. ...
Relativistic angular momentum
""Angular momentum tensor"" redirects to here.In physics, relativistic angular momentum refers to the mathematical formalisms and physical concepts that define angular momentum in special relativity (SR) and general relativity (GR). The relativistic quantity is subtly different from the three-dimensional quantity in classical mechanics.Angular momentum is a dynamical quantity derived from position and momentum, and is important; angular momentum is a measure of an object's ""amount of rotational motion"" and resistance to stop rotating. Also, in the same way momentum conservation corresponds to translational symmetry, angular momentum conservation corresponds to rotational symmetry – the connection between symmetries and conservation laws is made by Noether's theorem. While these concepts were originally discovered in classical mechanics – they are also true and significant in special and general relativity. In terms of abstract algebra; the invariance of angular momentum, four-momentum, and other symmetries in spacetime, are described by the Poincaré group and Lorentz group.Physical quantities which remain separate in classical physics are naturally combined in SR and GR by enforcing the postulates of relativity, an appealing characteristic. Most notably; space and time coordinates combine into the four-position, and energy and momentum combine into the four-momentum. These four-vectors depend on the frame of reference used, and change under Lorentz transformations to other inertial frames or accelerated frames.Relativistic angular momentum is less obvious. The classical definition of angular momentum is the cross product of position x with momentum p to obtain a pseudovector x×p, or alternatively as the exterior product to obtain a second order antisymmetric tensor x∧p. What does this combine with, if anything? There is another vector quantity not often discussed – it is the time-varying moment of mass (not the moment of inertia) related to the boost of the centre of mass of the system, and this combines with the classical angular momentum to form an antisymmetric tensor of second order. For rotating mass–energy distributions (such as gyroscopes, planets, stars, and black holes) instead of point-like particles, the angular momentum tensor is expressed in terms of the stress–energy tensor of the rotating object.In special relativity alone, in the rest frame of a spinning object; there is an intrinsic angular momentum analogous to the ""spin"" in quantum mechanics and relativistic quantum mechanics, although for an extended body rather than a point particle. In relativistic quantum mechanics, elementary particles have spin and this is an additional contribution to the orbital angular momentum operator, yielding the total angular momentum tensor operator. In any case, the intrinsic ""spin"" addition to the orbital angular momentum of an object can be expressed in terms of the Pauli–Lubanski pseudovector.