
Solution - Georg Mohr
... T lie on a circle. To prove this we show that the angles ∠T P R and ∠T QR are equal. The angles ∠ADT and ∠AP T are complimentary, therefore ∠ADT = ∠T P C. But ∠T P C is also equal to ∠T BC. Therefore, ∠ADT = ∠T BC. Similarly, ∠T AD = ∠T CB. This implies that the triangles 4AT D and 4BT C are equal. ...
... T lie on a circle. To prove this we show that the angles ∠T P R and ∠T QR are equal. The angles ∠ADT and ∠AP T are complimentary, therefore ∠ADT = ∠T P C. But ∠T P C is also equal to ∠T BC. Therefore, ∠ADT = ∠T BC. Similarly, ∠T AD = ∠T CB. This implies that the triangles 4AT D and 4BT C are equal. ...
Weeks 28-30 - Homeschool Math
... The Smith family will travel between 500 and 600 miles during their trip to the Outer Banks. Their van averages 25 miles per gallon of gasoline. If the cost of gasoline ranges from $2.05 to $2.17 per gallon, how much could they expect to spend on gasoline during their ...
... The Smith family will travel between 500 and 600 miles during their trip to the Outer Banks. Their van averages 25 miles per gallon of gasoline. If the cost of gasoline ranges from $2.05 to $2.17 per gallon, how much could they expect to spend on gasoline during their ...
Weber problem

In geometry, the Weber problem, named after Alfred Weber, is one of the most famous problems in location theory. It requires finding a point in the plane that minimizes the sum of the transportation costs from this point to n destination points, where different destination points are associated with different costs per unit distance.The Weber problem generalizes the geometric median, which assumes transportation costs per unit distance are the same for all destination points, and the problem of computing the Fermat point, the geometric median of three points. For this reason it is sometimes called the Fermat–Weber problem, although the same name has also been used for the unweighted geometric median problem. The Weber problem is in turn generalized by the attraction–repulsion problem, which allows some of the costs to be negative, so that greater distance from some points is better.