PHYSICS II: Kirchhoff`s Rules
... the power supply. Also set the decade box values to R1500, & R3800 and use the ohm scale of your DVM to carefully measure R1, R2 & R3 [generally your FLUKE DVM is more accurate than the decade boxes]. Then turn off the power supply and connect the circuit as in Figure 2, carefully observing pola ...
... the power supply. Also set the decade box values to R1500, & R3800 and use the ohm scale of your DVM to carefully measure R1, R2 & R3 [generally your FLUKE DVM is more accurate than the decade boxes]. Then turn off the power supply and connect the circuit as in Figure 2, carefully observing pola ...
Resistors and DC Analysis
... dividing the total voltage source by the total resistance. The voltage drop across any resistor may then be found by multiplying that current by the resistor value (Ohm’s law). Consequently, the voltage drops in a series circuit are directly proportional to the resistance. An alternate technique to ...
... dividing the total voltage source by the total resistance. The voltage drop across any resistor may then be found by multiplying that current by the resistor value (Ohm’s law). Consequently, the voltage drops in a series circuit are directly proportional to the resistance. An alternate technique to ...
Current Sensing Relay Driver
... current. So to convert the current you want to sense to a suitable voltage you use a current-to-voltage converter. No, that's not an expensive chip! They're usually known as resistors! In this one the sensing resistor is bypassed by diodes (so the current sensed can be varied over a wide range. The ...
... current. So to convert the current you want to sense to a suitable voltage you use a current-to-voltage converter. No, that's not an expensive chip! They're usually known as resistors! In this one the sensing resistor is bypassed by diodes (so the current sensed can be varied over a wide range. The ...
multi-port networks
... Plot vI (t) and vO(t) for the following values of the amplitudes of the input signal: 10V, 1V, 0.3V.Compare and interpret the waveforms that you have obtained. What is the application of two-port DR network? Exploration: B. In order to show a new application of the circuit you will use (positive ...
... Plot vI (t) and vO(t) for the following values of the amplitudes of the input signal: 10V, 1V, 0.3V.Compare and interpret the waveforms that you have obtained. What is the application of two-port DR network? Exploration: B. In order to show a new application of the circuit you will use (positive ...
2 EXPERIMENT Kirchoff’s Laws
... move from the positive side of V1 to its negative side. If you had chosen to sum the voltage changes around the loop in a clockwise direction, the sign of each of the voltages would change. This is equivalent to multiplying the counterclockwise equation by -1. So, you get the same result regardless ...
... move from the positive side of V1 to its negative side. If you had chosen to sum the voltage changes around the loop in a clockwise direction, the sign of each of the voltages would change. This is equivalent to multiplying the counterclockwise equation by -1. So, you get the same result regardless ...
Review Topics for Final Exam
... The following is a list of topics that could appear in one form or another on the exam. Not all of these topics will be covered, and it is possible that an exam problem could cover a detail not specifically listed here. However, this list has been made as comprehensive as possible. You should be fam ...
... The following is a list of topics that could appear in one form or another on the exam. Not all of these topics will be covered, and it is possible that an exam problem could cover a detail not specifically listed here. However, this list has been made as comprehensive as possible. You should be fam ...
5: Electric Current
... because it divides up the total p.d. supplied by the cell. The voltage across one of the resistors can then be used as an output supply to an external device or circuit. E.g. ...
... because it divides up the total p.d. supplied by the cell. The voltage across one of the resistors can then be used as an output supply to an external device or circuit. E.g. ...
Lab Prep Diode Lab
... that an exponential function goes more and more rapidly for larger x values: i.e. goes faster than a polynomial function for positive x value. Then discuss the rectifying properties. Explain to the students that a diode is basically a one way valve, that will only let current flow in one direction. ...
... that an exponential function goes more and more rapidly for larger x values: i.e. goes faster than a polynomial function for positive x value. Then discuss the rectifying properties. Explain to the students that a diode is basically a one way valve, that will only let current flow in one direction. ...
Methods of Analysis and Selected Topics (dc)
... a. Convert the voltage source of Fig. 8.9(a) to a current source, and calculate the current through the 4Ω load for each source. b. Replace the 4Ω load with a 1-kΩ load, and calculate the current IL for the voltage source. c. Repeat the calculation of part (b) assuming that the voltage source is ide ...
... a. Convert the voltage source of Fig. 8.9(a) to a current source, and calculate the current through the 4Ω load for each source. b. Replace the 4Ω load with a 1-kΩ load, and calculate the current IL for the voltage source. c. Repeat the calculation of part (b) assuming that the voltage source is ide ...
Network analysis (electrical circuits)
A network, in the context of electronics, is a collection of interconnected components. Network analysis is the process of finding the voltages across, and the currents through, every component in the network. There are many different techniques for calculating these values. However, for the most part, the applied technique assumes that the components of the network are all linear.The methods described in this article are only applicable to linear network analysis, except where explicitly stated.