EXAM #3 - life.illinois.edu
... 3. (20 points) You recently discovered a new plasmid from an environmental isolate of E. coli B, which you named pCar33. It carries resistance to ampicillin. a. (2 points) What DNA sequence would be required for the plasmid to transfer by conjugation? What class of enzymes mediates this process? Ans ...
... 3. (20 points) You recently discovered a new plasmid from an environmental isolate of E. coli B, which you named pCar33. It carries resistance to ampicillin. a. (2 points) What DNA sequence would be required for the plasmid to transfer by conjugation? What class of enzymes mediates this process? Ans ...
DNA
... same type of sticky ends as the DNA to be cloned. • Vector and the digested DNA are now mixed at the right concentration and temperature – the complementary sticky ends base pair and form a new recombinant DNA molecule. • Initially, the resulting molecule is held together only by hydrogen bonds. It ...
... same type of sticky ends as the DNA to be cloned. • Vector and the digested DNA are now mixed at the right concentration and temperature – the complementary sticky ends base pair and form a new recombinant DNA molecule. • Initially, the resulting molecule is held together only by hydrogen bonds. It ...
DNA replication
... What is a replication fork and how many are there? Why are single-stranded binding (SSB) proteins required? How does synthesis differ on leading strand and lagging strand? Which is continuous and semi-discontinuous? What are Okazaki fragments? How do polymerase I and III differ? ...
... What is a replication fork and how many are there? Why are single-stranded binding (SSB) proteins required? How does synthesis differ on leading strand and lagging strand? Which is continuous and semi-discontinuous? What are Okazaki fragments? How do polymerase I and III differ? ...
Supplemental material Material and methods Murine strains
... the FVB strain background allowed us to clone the Emv66 insertion site by inverse PCR using primers in the proviral LTR. The genotype of Afg3l2+/+, Afg3l2+/Emv66 and Afg3l2Emv66/Emv66 mice could be unambiguously determined by amplifying the wild-type allele using primers R25F and R25R, and the Emv6 ...
... the FVB strain background allowed us to clone the Emv66 insertion site by inverse PCR using primers in the proviral LTR. The genotype of Afg3l2+/+, Afg3l2+/Emv66 and Afg3l2Emv66/Emv66 mice could be unambiguously determined by amplifying the wild-type allele using primers R25F and R25R, and the Emv6 ...
Genetic Transformation computer exercise v02 r01
... You will use an online program to compare the sequences of the wild-type (GeneG) and mutated (GeneB) genes; this is known as a DNA sequence alignment. An alignment uses an algorithm (a step-by-step procedure) to compare the order of nucleotide bases in the sequences and then lines them up so that th ...
... You will use an online program to compare the sequences of the wild-type (GeneG) and mutated (GeneB) genes; this is known as a DNA sequence alignment. An alignment uses an algorithm (a step-by-step procedure) to compare the order of nucleotide bases in the sequences and then lines them up so that th ...
Final Review
... Genetic information flows from a sequence of nucleotides in a gene to a sequence of amino acids in a protein. ● The enzyme RNA-polymerase reads the DNA molecule in the 3' to 5' direction and synthesizes complementary mRNA molecules that determine the order of amino acids in the polypeptide. ● In euk ...
... Genetic information flows from a sequence of nucleotides in a gene to a sequence of amino acids in a protein. ● The enzyme RNA-polymerase reads the DNA molecule in the 3' to 5' direction and synthesizes complementary mRNA molecules that determine the order of amino acids in the polypeptide. ● In euk ...
f^*Co*e -z`
... 6' Mutagenesis- the process of change in genetic material naturally or on induction ...
... 6' Mutagenesis- the process of change in genetic material naturally or on induction ...
BACTERIA TRANSFORMATION LAB (ACTIVITY)
... are small, circular pieces DNA that can be exchanged naturally between bacteria. Plasmids may contain genes, and when these genes are expressed they can provide bacteria with special traits such as antibiotic resistance. Molecular biologists have developed procedures to take advantage of the natural ...
... are small, circular pieces DNA that can be exchanged naturally between bacteria. Plasmids may contain genes, and when these genes are expressed they can provide bacteria with special traits such as antibiotic resistance. Molecular biologists have developed procedures to take advantage of the natural ...
Chapter 8 Microbial Genetics
... question once in a while. The Study Questions you have been answering for each chapter are the basis for the midterm questions, but in order to phrase a logical multiple choice question, i.e. how the question is asked, it may be worded differently – the answer will remain the same. ...
... question once in a while. The Study Questions you have been answering for each chapter are the basis for the midterm questions, but in order to phrase a logical multiple choice question, i.e. how the question is asked, it may be worded differently – the answer will remain the same. ...
Exercise 5. DNA Ligation, Selection and
... DNA fragment is obtained containing the gene sequence, and (3) the gene is introduced into a new host is called cloning. Subcloning occurs when a gene which has already been cloned is transferred from one vector to another and introduced into a host organism. pUC19 is one of many plasmids which have ...
... DNA fragment is obtained containing the gene sequence, and (3) the gene is introduced into a new host is called cloning. Subcloning occurs when a gene which has already been cloned is transferred from one vector to another and introduced into a host organism. pUC19 is one of many plasmids which have ...
4 1. agribiotechnology 2. genetically modified organisms
... 33. The biochemical property of lectins that is the basis for most of their biological effects is their ability to bind to: (A) amphipathic molecules. (B) hydrophobic molecules. (C) specific lipids. (D) specific oligosaccharides. (E) specific peptides. 34. Inhibitors against this viral enzyme have ...
... 33. The biochemical property of lectins that is the basis for most of their biological effects is their ability to bind to: (A) amphipathic molecules. (B) hydrophobic molecules. (C) specific lipids. (D) specific oligosaccharides. (E) specific peptides. 34. Inhibitors against this viral enzyme have ...
bio Chapter 11 TEST (2010)
... c. injecting DNA into the plant cells. d. all of the above ____ 29. A recombinant plasmid gets inside a bacterial cell by a. inducing mutations. b. injecting itself into the cell. c. transformation. d. recombining with the cell. ____ 30. Which of the following includes all the others? a. plasmid b. ...
... c. injecting DNA into the plant cells. d. all of the above ____ 29. A recombinant plasmid gets inside a bacterial cell by a. inducing mutations. b. injecting itself into the cell. c. transformation. d. recombining with the cell. ____ 30. Which of the following includes all the others? a. plasmid b. ...
Restriction enzyme
... Methylase Enzymes Restriction enzymes usually occur in combination with one or two modification enzymes (DNAmethyltransferases) Protect the cell’s own DNA from cleavage by the restriction enzyme. Modification enzymes recognize the same DNA sequence as the restriction enzyme that they accompany, Ins ...
... Methylase Enzymes Restriction enzymes usually occur in combination with one or two modification enzymes (DNAmethyltransferases) Protect the cell’s own DNA from cleavage by the restriction enzyme. Modification enzymes recognize the same DNA sequence as the restriction enzyme that they accompany, Ins ...
Deciphering the role of DNA methylation in multiple sclerosis
... and environmental factors Multiple sclerosis (MS) is a complex inflammatory and degenerative disease of the central nervous system (CNS) that involves several not yet fully elucidated pathophysiologic mechanisms and evidences of implication of both environmental and genetic factors [1]. Epigenetics ...
... and environmental factors Multiple sclerosis (MS) is a complex inflammatory and degenerative disease of the central nervous system (CNS) that involves several not yet fully elucidated pathophysiologic mechanisms and evidences of implication of both environmental and genetic factors [1]. Epigenetics ...
Study questions - Pre-lab
... a. Predict whether or not you will exhibit the PTC taster phenotype. b. If you are a taster of PTC, what are your possible genotypes at the TAS2R38 locus? PAV/AVI or PAV/PAV (T/t or T/T) c. In which ways can single nucleotide polymorphisms (SNPs) affect the function of a gene? Non-sense mutations (t ...
... a. Predict whether or not you will exhibit the PTC taster phenotype. b. If you are a taster of PTC, what are your possible genotypes at the TAS2R38 locus? PAV/AVI or PAV/PAV (T/t or T/T) c. In which ways can single nucleotide polymorphisms (SNPs) affect the function of a gene? Non-sense mutations (t ...
Loss of Biological Activity of Bacteriophage 2C and
... values already reported for the "light" and "heavy" strands of phage 2C D N A 2 . The behavior of the heavy strand may result from the presence of some "weak spots" which get broken during chromatography. The DNA of 1-month-old phages, when denatured and fractionated in a similar way, yielded two fr ...
... values already reported for the "light" and "heavy" strands of phage 2C D N A 2 . The behavior of the heavy strand may result from the presence of some "weak spots" which get broken during chromatography. The DNA of 1-month-old phages, when denatured and fractionated in a similar way, yielded two fr ...
ppt
... particular regions of the chromosome – the modifiers are targeted to the chromosome region ...
... particular regions of the chromosome – the modifiers are targeted to the chromosome region ...
The Polymerase Chain Reaction
... TPA-25 insertion were screened. If the TPA-25 insertion was present than the bands should be a size of 400bp. If the TPA-25 insertion was absent than it should be only 100bp long. This was why the B+H was used, because the B+H produces 493bp and 125bp. If there was only 1 band visible, as with stu ...
... TPA-25 insertion were screened. If the TPA-25 insertion was present than the bands should be a size of 400bp. If the TPA-25 insertion was absent than it should be only 100bp long. This was why the B+H was used, because the B+H produces 493bp and 125bp. If there was only 1 band visible, as with stu ...
Notes
... ◦ A) wells (depressions) in an ELISA plate can be coated with antibodies. A sample can be added and if antigens for a disease are present they will stick to the wells with the antibodies. A second round of antibodies are added; these second antibodies have a dye. If the antigen for a disease was pre ...
... ◦ A) wells (depressions) in an ELISA plate can be coated with antibodies. A sample can be added and if antigens for a disease are present they will stick to the wells with the antibodies. A second round of antibodies are added; these second antibodies have a dye. If the antigen for a disease was pre ...
DNA LABELING, HYBRIDIZATION, AND DETECTION (Non
... positions. When chemically labeled probes are used, colorimetric reactions are most often used, some relying on antibodies or other chemicals attached to enzymes that can cause a colored precipitate to form from an appropriate substrate. There are four common ways to label DNA: 1.End-labeling, eithe ...
... positions. When chemically labeled probes are used, colorimetric reactions are most often used, some relying on antibodies or other chemicals attached to enzymes that can cause a colored precipitate to form from an appropriate substrate. There are four common ways to label DNA: 1.End-labeling, eithe ...
7.1 DNA Introduction
... 1. Tobacco mosaic virus has RNA rather than DNA as its genetic material. In a hypothetical situation where RNA from a tobacco mosaic virus is mixed with proteins from a related DNA virus, the result could be a hybrid virus. If that virus were to infect a cell and reproduce, what would the resulting ...
... 1. Tobacco mosaic virus has RNA rather than DNA as its genetic material. In a hypothetical situation where RNA from a tobacco mosaic virus is mixed with proteins from a related DNA virus, the result could be a hybrid virus. If that virus were to infect a cell and reproduce, what would the resulting ...
CHNOPS Lab
... that our cells make. The sequence of nucleotides in DNA determines the sequence of amino acids in polypeptides, and thus the structure of proteins. In a process called transcription, which takes place in the nucleus of the cell, messenger RNA (mRNA) reads and copies the DNA’s nucleotide sequences in ...
... that our cells make. The sequence of nucleotides in DNA determines the sequence of amino acids in polypeptides, and thus the structure of proteins. In a process called transcription, which takes place in the nucleus of the cell, messenger RNA (mRNA) reads and copies the DNA’s nucleotide sequences in ...
Construction of a Fibrobacter succinogenes Genomic Map and
... succinogenes have the operon structure, and there are at least three such operons on the chromosome. The five genes, encoding the hydrolytic enzymes, were located on the biggest A1.1 and A1.2 fragments (Fig. 2). They were placed on the corresponding fragments arbitrarily, and the positioning does no ...
... succinogenes have the operon structure, and there are at least three such operons on the chromosome. The five genes, encoding the hydrolytic enzymes, were located on the biggest A1.1 and A1.2 fragments (Fig. 2). They were placed on the corresponding fragments arbitrarily, and the positioning does no ...
practice exam 3_answer key
... 32. Which of the following is true concerning the 3 prime end of one strand of the DNA double helix? a. The 3 prime carbon is attached to a hydroxyl group b. The 3 prime carbon is attached to a phosphate group c. During DNA replication, neither strand grows from the 3 prime end d. The 3 prime end of ...
... 32. Which of the following is true concerning the 3 prime end of one strand of the DNA double helix? a. The 3 prime carbon is attached to a hydroxyl group b. The 3 prime carbon is attached to a phosphate group c. During DNA replication, neither strand grows from the 3 prime end d. The 3 prime end of ...
Bisulfite sequencing
Bisulphite sequencing (also known as bisulfite sequencing) is the use of bisulphite treatment of DNA to determine its pattern of methylation. DNA methylation was the first discovered epigenetic mark, and remains the most studied. In animals it predominantly involves the addition of a methyl group to the carbon-5 position of cytosine residues of the dinucleotide CpG, and is implicated in repression of transcriptional activity.Treatment of DNA with bisulphite converts cytosine residues to uracil, but leaves 5-methylcytosine residues unaffected. Thus, bisulphite treatment introduces specific changes in the DNA sequence that depend on the methylation status of individual cytosine residues, yielding single- nucleotide resolution information about the methylation status of a segment of DNA. Various analyses can be performed on the altered sequence to retrieve this information. The objective of this analysis is therefore reduced to differentiating between single nucleotide polymorphisms (cytosines and thymidine) resulting from bisulphite conversion (Figure 1).