Lecture slides with notes
... Where would you put your axis? Mary is about to do a push-up. Her center of gravity lies directly above a point on the floor which is d1=1.0 m from her feet and d2=0.7 m from her hands. If her mass is 50 kg, what is the force exerted by the floor on her hands, assuming that she holds this position? ...
... Where would you put your axis? Mary is about to do a push-up. Her center of gravity lies directly above a point on the floor which is d1=1.0 m from her feet and d2=0.7 m from her hands. If her mass is 50 kg, what is the force exerted by the floor on her hands, assuming that she holds this position? ...
Chapter 11 Angular Momentum
... – Kepler’s Second Law (in text) – Zero torque analogue (in Physlets) ...
... – Kepler’s Second Law (in text) – Zero torque analogue (in Physlets) ...
0117 Lecture Notes - AP Physics 1 Equations to
... This is another Uniformly Accelerated Motion (UAM) equation you should know. ...
... This is another Uniformly Accelerated Motion (UAM) equation you should know. ...
MASSACHUSETTS INSTITUTE OF TECHNOLOGY DEPARTMENT OF PHYSICS
... force F1 counteracts the friction force on m1 and prevents m1 from moving right. You may wonder why F1 has no vertical component. This is because the statement of the problem sets N = m1g, and no other vertical forces are present. Thus, the axle of m1 can only provide horizontal forces, and can hold ...
... force F1 counteracts the friction force on m1 and prevents m1 from moving right. You may wonder why F1 has no vertical component. This is because the statement of the problem sets N = m1g, and no other vertical forces are present. Thus, the axle of m1 can only provide horizontal forces, and can hold ...
rotational equilibrium
... Figure 8: Photo of set-up for determining an unknown mass 21. In the space provided on the worksheet, sketch and carefully label a diagram of this set-up. Show all the torque-producing forces. Indicate on your diagram the directions (clockwise or counterclockwise) of each torque. 22. Calculate the ...
... Figure 8: Photo of set-up for determining an unknown mass 21. In the space provided on the worksheet, sketch and carefully label a diagram of this set-up. Show all the torque-producing forces. Indicate on your diagram the directions (clockwise or counterclockwise) of each torque. 22. Calculate the ...
Torque, Equilibrium, and Stability
... • Any slight displacement of the boject raises its center of gravity and a restoring gravitational force tends to return the object to the position of minimal potential energy (with the base flat on the surface – the equilibrium position). • The gravitational force actually produces a restoring tor ...
... • Any slight displacement of the boject raises its center of gravity and a restoring gravitational force tends to return the object to the position of minimal potential energy (with the base flat on the surface – the equilibrium position). • The gravitational force actually produces a restoring tor ...
Torque - cloudfront.net
... More complicated shapes are more difficult to find the center of mass and will not be covered in this course. In most cases, the center of mass and the center of gravity are equivalent. ...
... More complicated shapes are more difficult to find the center of mass and will not be covered in this course. In most cases, the center of mass and the center of gravity are equivalent. ...
pps
... • We are now ready to develop some more fundamental relations for the rotational dynamics of a rigid body. We are going to show that the angular acceleration of a rotating rigid body (dw/dt) is proportional to the sum of the torque components along the axis or rotation SM The constant of proport ...
... • We are now ready to develop some more fundamental relations for the rotational dynamics of a rigid body. We are going to show that the angular acceleration of a rotating rigid body (dw/dt) is proportional to the sum of the torque components along the axis or rotation SM The constant of proport ...
Lecture – 4 Torque and Levers The Mechanics of Rigid Bodies
... The parallel axis theorem (Steinerscher Satz) • The moment of inertia of a rigid body depends on the distribution of mass around the axis of rotation Problem we have infinitely many axes of rotation ! For example, I could take this mechanical linkage and have it rotate around an axis through its ...
... The parallel axis theorem (Steinerscher Satz) • The moment of inertia of a rigid body depends on the distribution of mass around the axis of rotation Problem we have infinitely many axes of rotation ! For example, I could take this mechanical linkage and have it rotate around an axis through its ...
connection
... Gravitational force depends on mass: • More massive → greater gravitational pull • Mass is to gravity like electric charge is to electrostatics. In electrostatics: the larger the electric charge something has, the greater the force it feels in an electric field. ...
... Gravitational force depends on mass: • More massive → greater gravitational pull • Mass is to gravity like electric charge is to electrostatics. In electrostatics: the larger the electric charge something has, the greater the force it feels in an electric field. ...
Work, Energy and Momentum Notes
... In Kinematics, we studied motion along a straight line and introduced such concepts as displacement, velocity, and acceleration. Two-Dimensional Kinematics dealt with motion in two dimensions. Projectile motion is a special case of two-dimensional kinematics in which the object is projected into the ...
... In Kinematics, we studied motion along a straight line and introduced such concepts as displacement, velocity, and acceleration. Two-Dimensional Kinematics dealt with motion in two dimensions. Projectile motion is a special case of two-dimensional kinematics in which the object is projected into the ...