presentation source
... Notice that momentum is a vector quantity, which means that it must be specified with both a magnitude and direction. Also notice that the direction of the momentum vector is necessarily parallel to the velocity vector. ...
... Notice that momentum is a vector quantity, which means that it must be specified with both a magnitude and direction. Also notice that the direction of the momentum vector is necessarily parallel to the velocity vector. ...
Solutions from Yosumism website Problem 61 Problem 62:
... Now, recall the relation between angular momentum and torque to be above to get , and so the system starts rotating with angular momentum as in choice (A). (This approach is due to Matt Krems.) Note that one can immediately eliminate choice (D) since angular momentum is not conserved from the extern ...
... Now, recall the relation between angular momentum and torque to be above to get , and so the system starts rotating with angular momentum as in choice (A). (This approach is due to Matt Krems.) Note that one can immediately eliminate choice (D) since angular momentum is not conserved from the extern ...
Rotational Kinematics
... 1. What is Newton’s second law for rotational motion? 2. How can we define rotational inertia? 3. What affects the rotational inertia “I”? 4. What was the difference between parts “a” and “b” in the practice questions? ...
... 1. What is Newton’s second law for rotational motion? 2. How can we define rotational inertia? 3. What affects the rotational inertia “I”? 4. What was the difference between parts “a” and “b” in the practice questions? ...
2103-617: Advanced Dynamics Handout # 2: Review of Dynamic
... where P is the linear momentum defined by P = mv = mr . Note that r and v are the position vector and velocity of the particle, respectively. If the mass m is constant, then we got the familiar Newton's 2nd Law as ...
... where P is the linear momentum defined by P = mv = mr . Note that r and v are the position vector and velocity of the particle, respectively. If the mass m is constant, then we got the familiar Newton's 2nd Law as ...
Document
... instead of ½ mv2 because this time, it’s not just a pt mass, it’s a rod, it has an “I” (I is different than for a point mass) due to the fact that the distance is different PE is different. Note: They are using d/2 because that is the com for the uniform rod. What is cos 600? ...
... instead of ½ mv2 because this time, it’s not just a pt mass, it’s a rod, it has an “I” (I is different than for a point mass) due to the fact that the distance is different PE is different. Note: They are using d/2 because that is the com for the uniform rod. What is cos 600? ...
12. Tangential Newton`s 2nd Law vers_1.nb
... A. Thus far in this course we have mostly dealt with the motion of point-like masses and we have ignored the fact that most objects have some spatial extent. This not only simplified our calculation but it also is a reasonably good first approximation. However, for some kinds of problems the size of ...
... A. Thus far in this course we have mostly dealt with the motion of point-like masses and we have ignored the fact that most objects have some spatial extent. This not only simplified our calculation but it also is a reasonably good first approximation. However, for some kinds of problems the size of ...
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Dot and Cross Products Dot Product
... a) If a force F = (0, 1, 13) N acts on an object which undergoes a displacement d = (3, 2, 5) m, what work does the force do? b) If a force F = (3, 1, 7) N acts on an object which undergoes a displacement d = (5, 6, -3) m, what work does the force do? c) If a force F = (1, -2, 3) N acts on an object ...
... a) If a force F = (0, 1, 13) N acts on an object which undergoes a displacement d = (3, 2, 5) m, what work does the force do? b) If a force F = (3, 1, 7) N acts on an object which undergoes a displacement d = (5, 6, -3) m, what work does the force do? c) If a force F = (1, -2, 3) N acts on an object ...
