Lecture04
... Alternate statement: A body remains in uniform motion along a straight line at constant speed (or remains at rest) unless it is acted on by a net external force. Above assume an “inertial reference frame”: • Equations of physics look simplest in inertial systems. • Non-inertial frames (e.g., rotatin ...
... Alternate statement: A body remains in uniform motion along a straight line at constant speed (or remains at rest) unless it is acted on by a net external force. Above assume an “inertial reference frame”: • Equations of physics look simplest in inertial systems. • Non-inertial frames (e.g., rotatin ...
Circular Motion
... Determine the centripetal force acting upon a 40-kg child who makes 10 revolutions around the Cliffhanger in 29.3 seconds. The radius of the barrel is 2.90 meters. A 900-kg car makes a 180-degree turn with a speed of 10.0 m/s. The radius of the circle through which the car is turning is 25.0 m. Dete ...
... Determine the centripetal force acting upon a 40-kg child who makes 10 revolutions around the Cliffhanger in 29.3 seconds. The radius of the barrel is 2.90 meters. A 900-kg car makes a 180-degree turn with a speed of 10.0 m/s. The radius of the circle through which the car is turning is 25.0 m. Dete ...
Physical Science Physics Motion & Force
... 1. Newton’s Second Law of Motion – The net force on an object is equal to the product of its acceleration and its mass: 2. mass= Force / acceleration 3. acceleration = force / mass D. Friction & Gravity 1. Friction: the force of friction is the force that one surface exerts on another one when they ...
... 1. Newton’s Second Law of Motion – The net force on an object is equal to the product of its acceleration and its mass: 2. mass= Force / acceleration 3. acceleration = force / mass D. Friction & Gravity 1. Friction: the force of friction is the force that one surface exerts on another one when they ...
MS-Word format
... / T. The height h can be calculated from h = vy(0)T/8, from which the power can be calculated: P = mgvy(0)/4 = (g – max[0, g – vx2/L])mgT/4 For walking at low speed, the power is PW = vx2mgT/4L, whereas for running the power is PR = mg2T/4. At the transition speed, the power required for m = 50 kg ...
... / T. The height h can be calculated from h = vy(0)T/8, from which the power can be calculated: P = mgvy(0)/4 = (g – max[0, g – vx2/L])mgT/4 For walking at low speed, the power is PW = vx2mgT/4L, whereas for running the power is PR = mg2T/4. At the transition speed, the power required for m = 50 kg ...
Force and Circular Motion ppt
... • An object moving in a circle at a constant speed still has an acceleration due to its change in direction • Velocity is a vector so acceleration can be produced by a change in magnitude and direction • Centripetal Acceleration is acceleration caused by a change in direction, directed toward the c ...
... • An object moving in a circle at a constant speed still has an acceleration due to its change in direction • Velocity is a vector so acceleration can be produced by a change in magnitude and direction • Centripetal Acceleration is acceleration caused by a change in direction, directed toward the c ...
Rotational Dynamics
... one can find torques for each of those forces and calculate the net torque with respect to the chosen rotational axis. The body can rotate around this axis with nonzero angular acceleration if the net torque is not zero, in same way as the body moves with nonzero acceleration only if the net force a ...
... one can find torques for each of those forces and calculate the net torque with respect to the chosen rotational axis. The body can rotate around this axis with nonzero angular acceleration if the net torque is not zero, in same way as the body moves with nonzero acceleration only if the net force a ...
PPT - LSU Physics
... force. Thus, the work done by the gravitational force on a particle moving from an initial point i to a final point f is independent of the path taken between the points. The change DU in the gravitational potential energy from point i to point f is ...
... force. Thus, the work done by the gravitational force on a particle moving from an initial point i to a final point f is independent of the path taken between the points. The change DU in the gravitational potential energy from point i to point f is ...
newtons laws 2015
... called equilibrium. In equilibrium, all forces cancel out leaving zero net force. Objects that are standing still are in equilibrium because their acceleration is zero. ...
... called equilibrium. In equilibrium, all forces cancel out leaving zero net force. Objects that are standing still are in equilibrium because their acceleration is zero. ...
4.3 Netwon*s Second and Third Laws
... Newton’s Third Law If two objects interact, the magnitude of the force exerted on object 1 by object 2 is equal to the magnitude of the force simultaneously exerted on object 2 by object 1, and these two forces are opposite in direction. In other words, for every action, there is an equal and opposi ...
... Newton’s Third Law If two objects interact, the magnitude of the force exerted on object 1 by object 2 is equal to the magnitude of the force simultaneously exerted on object 2 by object 1, and these two forces are opposite in direction. In other words, for every action, there is an equal and opposi ...
Homework 4 - UCLA Astronomy
... Due: Friday, May 9, 2008 in class or to Ian by noon. Reading: Chapter on The Milky Way Problems: ...
... Due: Friday, May 9, 2008 in class or to Ian by noon. Reading: Chapter on The Milky Way Problems: ...
chapter4MakingSenseU..
... • G value depends upon the units used for F, the force, M1 and M2 the mass, and d the distance. • If SI, Standard International units, MKS, meterkilogram-second, is used then G=(6.6742±0.0010)×10-11m3s-2kg-1 • If cgs, centimeter-gram-second, units are used then G=(6.6742±0.0010) ×10-8cm3s-2g-1 • If ...
... • G value depends upon the units used for F, the force, M1 and M2 the mass, and d the distance. • If SI, Standard International units, MKS, meterkilogram-second, is used then G=(6.6742±0.0010)×10-11m3s-2kg-1 • If cgs, centimeter-gram-second, units are used then G=(6.6742±0.0010) ×10-8cm3s-2g-1 • If ...
Force Law
... rest in Frame 2 is zero then the vector sum of forces acting on the object moving at constant speed in Frame 1 is also zero ...
... rest in Frame 2 is zero then the vector sum of forces acting on the object moving at constant speed in Frame 1 is also zero ...
2nd Term Exam - UTA HEP WWW Home Page
... 6. An object moves in a circular path at a constant speed. Consider the direction of the object's velocity and acceleration vectors. a) Both vectors point in the same direction. b) The vectors point in opposite directions. c) The vectors are perpendicular. d) The question is meaningless, since the a ...
... 6. An object moves in a circular path at a constant speed. Consider the direction of the object's velocity and acceleration vectors. a) Both vectors point in the same direction. b) The vectors point in opposite directions. c) The vectors are perpendicular. d) The question is meaningless, since the a ...
Kreutter: Linear Dynamics 7 Newton`s Second Law: Quantitative I
... constant, than a will decrease. If we decrease c and keep b constant, than a will increase. Think about how this is different than if we increase or decrease b. Newton’s Second Law of Motion: We choose a particular object (objects) as our object of interest — the system. The acceleration a of the sy ...
... constant, than a will decrease. If we decrease c and keep b constant, than a will increase. Think about how this is different than if we increase or decrease b. Newton’s Second Law of Motion: We choose a particular object (objects) as our object of interest — the system. The acceleration a of the sy ...
IV. Force & Acceleration
... Mass and Acceleration • If you throw a softball and a baseball as hard as you can, why don’t they have the same speed? • The difference is due to their masses. • If it takes the same amount of time to throw both balls, the softball would have less. • Force, mass, acceleration and acceleration are r ...
... Mass and Acceleration • If you throw a softball and a baseball as hard as you can, why don’t they have the same speed? • The difference is due to their masses. • If it takes the same amount of time to throw both balls, the softball would have less. • Force, mass, acceleration and acceleration are r ...
Modified Newtonian dynamics
In physics, modified Newtonian dynamics (MOND) is a theory that proposes a modification of Newton's laws to account for observed properties of galaxies. Created in 1983 by Israeli physicist Mordehai Milgrom, the theory's original motivation was to explain the fact that the velocities of stars in galaxies were observed to be larger than expected based on Newtonian mechanics. Milgrom noted that this discrepancy could be resolved if the gravitational force experienced by a star in the outer regions of a galaxy was proportional to the square of its centripetal acceleration (as opposed to the centripetal acceleration itself, as in Newton's Second Law), or alternatively if gravitational force came to vary inversely with radius (as opposed to the inverse square of the radius, as in Newton's Law of Gravity). In MOND, violation of Newton's Laws occurs at extremely small accelerations, characteristic of galaxies yet far below anything typically encountered in the Solar System or on Earth.MOND is an example of a class of theories known as modified gravity, and is an alternative to the hypothesis that the dynamics of galaxies are determined by massive, invisible dark matter halos. Since Milgrom's original proposal, MOND has successfully predicted a variety of galactic phenomena that are difficult to understand from a dark matter perspective. However, MOND and its generalisations do not adequately account for observed properties of galaxy clusters, and no satisfactory cosmological model has been constructed from the theory.