Thermo notes
... Note: The Calories reported on food wrappers are measured as heat needed to increase the temperature of 1000 grams of water by 1 °C, 1 Calorie (Cal) = 1000 calories (cal) = 1 kilocalorie (kcal) Drinking a whole can of Pepsi actually means drinking: 250 Cal = 250,000 calories! ...
... Note: The Calories reported on food wrappers are measured as heat needed to increase the temperature of 1000 grams of water by 1 °C, 1 Calorie (Cal) = 1000 calories (cal) = 1 kilocalorie (kcal) Drinking a whole can of Pepsi actually means drinking: 250 Cal = 250,000 calories! ...
Seat: PHYS 1500 (Fall 2006) Exam #2, V1 Name: 1. Two objects are
... what is the net force acting on the mass? (d) When the mass is at the bottom of the circle, what is its velocity? (a) Since the mass is rotating clockwise, the angular velocity is ω = −v/r. (b) The angular acceleration can be found from α = at /r. Gravity is the only force acting along the circle wh ...
... what is the net force acting on the mass? (d) When the mass is at the bottom of the circle, what is its velocity? (a) Since the mass is rotating clockwise, the angular velocity is ω = −v/r. (b) The angular acceleration can be found from α = at /r. Gravity is the only force acting along the circle wh ...
R= 8.31 J/mol K = 0.0821 L atm/mol K = 62.4 L torr/mol K PV = nRT
... ______13. A tank contains 32.00 grams of O2 gas and 16.00 grams of He gas. If the partial pressure of the oxygen gas is 0.400 atm, what is the total pressure of the gases in the tank? A) 0.800 atm. B) 0.600 atm C) 1.20 atm D) 1.60 atm E) 2.00 atm ______14. Samples of Ne gas and He gas are mixed in a ...
... ______13. A tank contains 32.00 grams of O2 gas and 16.00 grams of He gas. If the partial pressure of the oxygen gas is 0.400 atm, what is the total pressure of the gases in the tank? A) 0.800 atm. B) 0.600 atm C) 1.20 atm D) 1.60 atm E) 2.00 atm ______14. Samples of Ne gas and He gas are mixed in a ...
Abby AII1 C083 Ye, Zi Topic: Energy in Simple harmonic motion
... transformation between potential energy and kinetic energy. In the example ...
... transformation between potential energy and kinetic energy. In the example ...
Chemical energy thread: Homework problems
... tubular components measuring 1-2 micrometers in diameter. Each myofibril is divided along its length into sarcomeres (the basic unit of a muscle, with a single myosin filament), each of which ...
... tubular components measuring 1-2 micrometers in diameter. Each myofibril is divided along its length into sarcomeres (the basic unit of a muscle, with a single myosin filament), each of which ...
Chemistry 534
... b. If a compound contains 300 kJ of energy and it breaks up into two elements each containing 160 kJ, then the reaction should have released 20 kJ of heat into the environment. FALSE (160 + 160) – 300 = + 20 kJ = endothermic, so it needs to absorb or steal 20 kJ from its environment, not release. ...
... b. If a compound contains 300 kJ of energy and it breaks up into two elements each containing 160 kJ, then the reaction should have released 20 kJ of heat into the environment. FALSE (160 + 160) – 300 = + 20 kJ = endothermic, so it needs to absorb or steal 20 kJ from its environment, not release. ...
Unit 7 - Working vs work (Gregg Swackhamer)
... every pertinent energy exchange. Keeping track of the amounts of energy in various entities can be done quite nicely using the energy bar graphs advocated by Alan Van Heuvelen. Keeping track of the sources and recipients of energy can be done with energy flow diagrams as prescribed by the faculty of ...
... every pertinent energy exchange. Keeping track of the amounts of energy in various entities can be done quite nicely using the energy bar graphs advocated by Alan Van Heuvelen. Keeping track of the sources and recipients of energy can be done with energy flow diagrams as prescribed by the faculty of ...
Statistical Physics
... 4) An ideal gas ( =1.4) expands quasi-statically and adiabatically. If the final temperature is one third the initial temperature so by what factor does its volume change? a. 10 c. 16 b. 20 d. 12 5) Following question 4 above, by what factor does its pressure change? a. 1 c. 0.02 b. 1.2 d. 2 6) O ...
... 4) An ideal gas ( =1.4) expands quasi-statically and adiabatically. If the final temperature is one third the initial temperature so by what factor does its volume change? a. 10 c. 16 b. 20 d. 12 5) Following question 4 above, by what factor does its pressure change? a. 1 c. 0.02 b. 1.2 d. 2 6) O ...
Physics Curriculum Map - Norwell High School SUBJECT: Physics
... motion if we know that it is subjected to balanced or Interpret and apply Newton’s three laws of motion. Use a free-body force diagram to show forces acting on a system consisting of a unbalanced forces? pair of interacting objects. For a diagram with only co-linear forces, determine the n ...
... motion if we know that it is subjected to balanced or Interpret and apply Newton’s three laws of motion. Use a free-body force diagram to show forces acting on a system consisting of a unbalanced forces? pair of interacting objects. For a diagram with only co-linear forces, determine the n ...
Physics218_lecture_010
... Calculating the work • Work is done only if the force (or some component of it) is in the same (or opposite) direction as the displacement • Work is the force done Parallel to the displacement – Think of it as “amount of displacement should be affected by the force if it is doing any work” • Pushin ...
... Calculating the work • Work is done only if the force (or some component of it) is in the same (or opposite) direction as the displacement • Work is the force done Parallel to the displacement – Think of it as “amount of displacement should be affected by the force if it is doing any work” • Pushin ...
Worked solutions Chapter 2: Collisions and
... No, during the collision some energy would have been transformed into heat and sound energy. Truly elastic collisions only occur at the atomic level. W = U s = 0.5 kx2, where k = gradient of force–compression graph = 1.0 103 N m–1 Then W = 0.5 × 1.0 103 × 0.0102 = 0.050 N m During compression, ...
... No, during the collision some energy would have been transformed into heat and sound energy. Truly elastic collisions only occur at the atomic level. W = U s = 0.5 kx2, where k = gradient of force–compression graph = 1.0 103 N m–1 Then W = 0.5 × 1.0 103 × 0.0102 = 0.050 N m During compression, ...
Answer - whoawiki
... If the same force is applied on the objects of different masses it will cause them to move at different rates of acceleration. Ex: 20 N of force is applied to two objects. One object is 10 kg, the other has less mass at 5kg. When the same force (20N) is applied to both the larger object moves less ...
... If the same force is applied on the objects of different masses it will cause them to move at different rates of acceleration. Ex: 20 N of force is applied to two objects. One object is 10 kg, the other has less mass at 5kg. When the same force (20N) is applied to both the larger object moves less ...
Unit_4_AP_Review_Problems_Momentum,_Work,_Power,_Energy
... whose mass is 1800 kg. The cars lock bumpers and skid off together with the wheels locked. a. What is the velocity of the two cars just after the collision? (8.98 m/s) b. Find the impulse (magnitude and direction) that acts on the skidding cars from just after the collision until they come to a halt ...
... whose mass is 1800 kg. The cars lock bumpers and skid off together with the wheels locked. a. What is the velocity of the two cars just after the collision? (8.98 m/s) b. Find the impulse (magnitude and direction) that acts on the skidding cars from just after the collision until they come to a halt ...
docx
... static friction coefficient. For finding rolling friction force we had performed same operation as for finding air drag: we had pushed car forward and plotted its motion; through this plot we found total friction force, acting on the car. Also we could already calculate static friction force; the di ...
... static friction coefficient. For finding rolling friction force we had performed same operation as for finding air drag: we had pushed car forward and plotted its motion; through this plot we found total friction force, acting on the car. Also we could already calculate static friction force; the di ...
Energy, work, heat and chemical reactions
... work -- occurs when an object is moved against an applied force Work = Force x Distance d ...
... work -- occurs when an object is moved against an applied force Work = Force x Distance d ...