Recitation 1
... Plugging our A and ω into our x(t) yields the equation of motion we set out to find. (b) To find the maximum speed, we could either take the derivative of x(t) (like we did in 12.2), or realize that the derivative will have another factor of ω in it’s amplitude and jump to the answer vmax = Aω = 6π ...
... Plugging our A and ω into our x(t) yields the equation of motion we set out to find. (b) To find the maximum speed, we could either take the derivative of x(t) (like we did in 12.2), or realize that the derivative will have another factor of ω in it’s amplitude and jump to the answer vmax = Aω = 6π ...
Clicker Question
... Summary of Newton’s Three Laws • An object tends to remain at rest, or, if moving, to continue moving at constant speed in a straight line (1st Law). Objects tend to resist changes in motion (inertia) – mass measures this. • (2nd Law) When there is a net force on an object, it will accelerate: a = ...
... Summary of Newton’s Three Laws • An object tends to remain at rest, or, if moving, to continue moving at constant speed in a straight line (1st Law). Objects tend to resist changes in motion (inertia) – mass measures this. • (2nd Law) When there is a net force on an object, it will accelerate: a = ...
Unit I: Concept Enhancer
... and acceleration in order to develop Newton’s 2nd Law. In these activities you discovered the variables that affected acceleration. We call acceleration the dependent variable because it depends on the value of other variables such as force and mass. Force and mass are independent variables because ...
... and acceleration in order to develop Newton’s 2nd Law. In these activities you discovered the variables that affected acceleration. We call acceleration the dependent variable because it depends on the value of other variables such as force and mass. Force and mass are independent variables because ...
Part IV
... Example: Accelerometer A small mass m hangs from a thin string & can swing like a pendulum. You attach it above the window of your car as shown. What angle does the string make a. When the car accelerates at a constant a = 1.20 m/s2? b. When the car moves at constant velocity, v = 90 km/h? ...
... Example: Accelerometer A small mass m hangs from a thin string & can swing like a pendulum. You attach it above the window of your car as shown. What angle does the string make a. When the car accelerates at a constant a = 1.20 m/s2? b. When the car moves at constant velocity, v = 90 km/h? ...
Investigation 1: Gathering Evidence and Modeling
... Some of the lines will go through the Earth without hitting the inner circle. Some of the lines, however, will hit the inner circle. This is a boundary between zones with different wave speeds – remember from the last part what happens when waves go through QuickTime™ and a boundaries. TIFF (Unc ...
... Some of the lines will go through the Earth without hitting the inner circle. Some of the lines, however, will hit the inner circle. This is a boundary between zones with different wave speeds – remember from the last part what happens when waves go through QuickTime™ and a boundaries. TIFF (Unc ...
Centripetal force - mrhsluniewskiscience
... Reminder: AP test and solutions manual giancoli physics principles with applications 6th edition solution manual 3rd site in google gives a pdf Physics – Comcast.net ...
... Reminder: AP test and solutions manual giancoli physics principles with applications 6th edition solution manual 3rd site in google gives a pdf Physics – Comcast.net ...
Circular Motion
... 1. If the central force is continually increased, the body will spiral in. this gives a displacement in the direction of the force, work is done and the body speeds up. 2. If the central force is increased and then held constant, a smaller faster circular path results 3. If the force is held constan ...
... 1. If the central force is continually increased, the body will spiral in. this gives a displacement in the direction of the force, work is done and the body speeds up. 2. If the central force is increased and then held constant, a smaller faster circular path results 3. If the force is held constan ...
CFA #2 Study Guide Name: Class: ______ Kinetmatics Review 1. A
... d) slightly more than 2 N, leftward ...
... d) slightly more than 2 N, leftward ...
Here - UCSB HEP
... > m1g Net force on the two blocks is F = m2g. But F=(m1+m2)a Æ a = m2g/(m1+m2). Consider the mass m1: it has the acceleration given above, and the net force on it is the tension of the string. Thus T = m1a = m1m2g/(m1+m2). Then, since m1/(m1+m2) < 1, it follows that T< m2g Æ Correct answer is B (We ...
... > m1g Net force on the two blocks is F = m2g. But F=(m1+m2)a Æ a = m2g/(m1+m2). Consider the mass m1: it has the acceleration given above, and the net force on it is the tension of the string. Thus T = m1a = m1m2g/(m1+m2). Then, since m1/(m1+m2) < 1, it follows that T< m2g Æ Correct answer is B (We ...
