chapter 4 - forces and newton`s laws of motion
... Contact forces require the objects involved to be touching. An example would be a bat striking a ball. Action at a distance forces exist regardless of contact. Gravity and magnetic forces are examples. Forces are vector quantities with direction and magnitude. Example - your weight has a magnitude(n ...
... Contact forces require the objects involved to be touching. An example would be a bat striking a ball. Action at a distance forces exist regardless of contact. Gravity and magnetic forces are examples. Forces are vector quantities with direction and magnitude. Example - your weight has a magnitude(n ...
PPT
... Roller Coaster with Friction A roller coaster car of mass m starts at rest at height y1 and falls down the path with friction, then back up until it hits height y2 (y1 > y2). An odometer tells us that the total scalar distance traveled is d. Assuming we don’t know anything about the friction or the ...
... Roller Coaster with Friction A roller coaster car of mass m starts at rest at height y1 and falls down the path with friction, then back up until it hits height y2 (y1 > y2). An odometer tells us that the total scalar distance traveled is d. Assuming we don’t know anything about the friction or the ...
8. Rotatory Motion
... A uniform circular disc of radius R lies in the X-Y plane with its centre coinciding with the origin of the coordinate system. Its moment of inertia about an axis, lying in the X-Y plane, parallel to the X-axis and passing through a point on the Y-axis at a distance y=2R is I1. Its moment of inertia ...
... A uniform circular disc of radius R lies in the X-Y plane with its centre coinciding with the origin of the coordinate system. Its moment of inertia about an axis, lying in the X-Y plane, parallel to the X-axis and passing through a point on the Y-axis at a distance y=2R is I1. Its moment of inertia ...
Dynamics
... A smooth wood block is placed on a smooth wooden tabletop. You find that you must exert a force of 14.0 N to keep the 40.0 N block moving at a constant velocity. a) what is the coefficient of sliding friction for the block and table? ...
... A smooth wood block is placed on a smooth wooden tabletop. You find that you must exert a force of 14.0 N to keep the 40.0 N block moving at a constant velocity. a) what is the coefficient of sliding friction for the block and table? ...
Newton`s Laws of Motion - pams
... exerting equal force on the rope in opposite directions. This balanced force results in no change of motion. ...
... exerting equal force on the rope in opposite directions. This balanced force results in no change of motion. ...
Basic fluid dynamics
... But fluids and solids are extremes, and there are many transition materials with properties in between. It is therefore important as far as possible to analyze matter in motion without distinguishing between particular types of matter. In this chapter the two basic mechanical equations governing the ...
... But fluids and solids are extremes, and there are many transition materials with properties in between. It is therefore important as far as possible to analyze matter in motion without distinguishing between particular types of matter. In this chapter the two basic mechanical equations governing the ...
Mid Year Review
... 3. A car accelerates at 5.0 m/s2 from an initial velocity of 14 m/s. How long will it take to reach a velocity of 65 m/s? 10.2 s 4. A car accelerates form rest at 12.0 m/s2 for 14.0 s. a) How fast is it moving after 14.0 s? 168 m/s b) How far has it traveled in this time? 1176 m = 1180 m 5. A skier ...
... 3. A car accelerates at 5.0 m/s2 from an initial velocity of 14 m/s. How long will it take to reach a velocity of 65 m/s? 10.2 s 4. A car accelerates form rest at 12.0 m/s2 for 14.0 s. a) How fast is it moving after 14.0 s? 168 m/s b) How far has it traveled in this time? 1176 m = 1180 m 5. A skier ...
sy30_may10_s12
... Circular orbits: Dynamical quantities (v,E,K,U,F) involve radius K(r) = - ½ U(r) Employ conservation of angular momentum in elliptical orbits No need to derive Kepler’s Laws (know the reasons for them) Energy transfer when orbit radius changes(e.g. escape velocity) Physics 201: Lecture 30, Pg 18 ...
... Circular orbits: Dynamical quantities (v,E,K,U,F) involve radius K(r) = - ½ U(r) Employ conservation of angular momentum in elliptical orbits No need to derive Kepler’s Laws (know the reasons for them) Energy transfer when orbit radius changes(e.g. escape velocity) Physics 201: Lecture 30, Pg 18 ...