Ch5 - OCCC.edu
... either discrete or continuous. a. Discrete random variable – a random variable that takes on whole numbers or integers. b. Continuous random variable – when the random variable can take on any value in an interval; not just whole numbers. 2. Discrete Probability Model – This is a probability model t ...
... either discrete or continuous. a. Discrete random variable – a random variable that takes on whole numbers or integers. b. Continuous random variable – when the random variable can take on any value in an interval; not just whole numbers. 2. Discrete Probability Model – This is a probability model t ...
Randomness and Probability
... • As a special promotion for its 20-ounce bottles of soda, a soft drink company printed a message on the inside of each bottle cap. Some of the caps said, “please try again!” while others said “you’re a winner!” the company advertised the promotion with the slogan, “1 in 6 wins a prize.” Seven frien ...
... • As a special promotion for its 20-ounce bottles of soda, a soft drink company printed a message on the inside of each bottle cap. Some of the caps said, “please try again!” while others said “you’re a winner!” the company advertised the promotion with the slogan, “1 in 6 wins a prize.” Seven frien ...
Discrete Probability
... What is the probability that a family with two children has two boys, given that they have at least one boy? F = {BB, BG, GB} E = {BB} ...
... What is the probability that a family with two children has two boys, given that they have at least one boy? F = {BB, BG, GB} E = {BB} ...
PPT - Carnegie Mellon School of Computer Science
... Let X be a random variable which denotes the value of the outcome of a certain experiment. We will assign probabilities to the possible outcomes of an experiment. We do this by assigning to each outcome wj a nonnegative number m(wj) in such a way that m(w1) + … + m(wn)=1 The function m(wj) is called ...
... Let X be a random variable which denotes the value of the outcome of a certain experiment. We will assign probabilities to the possible outcomes of an experiment. We do this by assigning to each outcome wj a nonnegative number m(wj) in such a way that m(w1) + … + m(wn)=1 The function m(wj) is called ...
What are the assumptions for creating a
... What is the probability of a center NOT fouling out in a game? What then is the probability of fouling out? If a player earns 3 fouls in the first half, the coach will usually sit that player for the rest of the half. If the player starts the second half, what’s the probability of not fouling out in ...
... What is the probability of a center NOT fouling out in a game? What then is the probability of fouling out? If a player earns 3 fouls in the first half, the coach will usually sit that player for the rest of the half. If the player starts the second half, what’s the probability of not fouling out in ...
binomial distribution
... There are n trials. Each trial results in a success or a failure. The probability of a success, p, is constant from trial to trial. The trials are independent. -Knowing the result of one observation tells you nothing about the other observations. ...
... There are n trials. Each trial results in a success or a failure. The probability of a success, p, is constant from trial to trial. The trials are independent. -Knowing the result of one observation tells you nothing about the other observations. ...
day8
... – categories, such as much above average, above average, near average, below average, much below average – binary variables, such as dropout/no dropout ...
... – categories, such as much above average, above average, near average, below average, much below average – binary variables, such as dropout/no dropout ...
Probability Essentials Chapter 3
... W, number of ways to choose 4 things from eight objects is 8! / [4!4!] = 70 (denoted as (84)--”8, choose 4”) • Ex. 5.4, How many of these choices include 3 correct (house brand) and 1 incorrect? W(A) = (43)(41) = 42 = 16. • What is probability that taster gets 3 correct (out of 4) by chance? P(A) = ...
... W, number of ways to choose 4 things from eight objects is 8! / [4!4!] = 70 (denoted as (84)--”8, choose 4”) • Ex. 5.4, How many of these choices include 3 correct (house brand) and 1 incorrect? W(A) = (43)(41) = 42 = 16. • What is probability that taster gets 3 correct (out of 4) by chance? P(A) = ...
DepeNDeNt aND INDepeNDeNt eveNts
... Dependent and Independent Events NSTRUCTIONS: Decide whether the following events are independent or dependent events. Write your answer in the space provided. 1. Mrs. Eskew draws two student names from a shoe box and awards each of the two students a prize. ...
... Dependent and Independent Events NSTRUCTIONS: Decide whether the following events are independent or dependent events. Write your answer in the space provided. 1. Mrs. Eskew draws two student names from a shoe box and awards each of the two students a prize. ...
Sampling/probability/inferential statistics
... The point is to convert your particular metric (e.g., height, IQ scores) into the metric of the normal curve (Z-scores). If all of your values were converted to Zscores, the distribution will have a mean of zero and a standard deviation of one. ...
... The point is to convert your particular metric (e.g., height, IQ scores) into the metric of the normal curve (Z-scores). If all of your values were converted to Zscores, the distribution will have a mean of zero and a standard deviation of one. ...
Powerpoint
... • Suppose that an experiment has only n outcomes. The equally likely approach to probability assigns a probability of 1/n to each of the outcomes. • Further, if an event A is made up of m outcomes, then P (A) = m/n. ...
... • Suppose that an experiment has only n outcomes. The equally likely approach to probability assigns a probability of 1/n to each of the outcomes. • Further, if an event A is made up of m outcomes, then P (A) = m/n. ...
Math 141 Lecture Notes
... that a randomly selected Pulsar 19-inch color television set will have a defective picture tube? ...
... that a randomly selected Pulsar 19-inch color television set will have a defective picture tube? ...
Ars Conjectandi
Ars Conjectandi (Latin for The Art of Conjecturing) is a book on combinatorics and mathematical probability written by Jakob Bernoulli and published in 1713, eight years after his death, by his nephew, Niklaus Bernoulli. The seminal work consolidated, apart from many combinatorial topics, many central ideas in probability theory, such as the very first version of the law of large numbers: indeed, it is widely regarded as the founding work of that subject. It also addressed problems that today are classified in the twelvefold way, and added to the subjects; consequently, it has been dubbed an important historical landmark in not only probability but all combinatorics by a plethora of mathematical historians. The importance of this early work had a large impact on both contemporary and later mathematicians; for example, Abraham de Moivre.Bernoulli wrote the text between 1684 and 1689, including the work of mathematicians such as Christiaan Huygens, Gerolamo Cardano, Pierre de Fermat, and Blaise Pascal. He incorporated fundamental combinatorial topics such as his theory of permutations and combinations—the aforementioned problems from the twelvefold way—as well as those more distantly connected to the burgeoning subject: the derivation and properties of the eponymous Bernoulli numbers, for instance. Core topics from probability, such as expected value, were also a significant portion of this important work.