Exercise 6
... The next step is to extract the schematic and parasitic elements from the layout. For the extraction we use the process of frame identification as we create a symbol for each identified frame. The symbol is placed in extracted schematic view which is generated with each program starting. An identifi ...
... The next step is to extract the schematic and parasitic elements from the layout. For the extraction we use the process of frame identification as we create a symbol for each identified frame. The symbol is placed in extracted schematic view which is generated with each program starting. An identifi ...
Class-AB Amplifier
... • Input, power and output cables constitute antennas and can radiate EMI if they are not appropriately filtered. • Traces on PCBs also constitute antennas and can have the same undesirable effect. • So, filter input, power and output lines as required and locate filters as close as possible to the g ...
... • Input, power and output cables constitute antennas and can radiate EMI if they are not appropriately filtered. • Traces on PCBs also constitute antennas and can have the same undesirable effect. • So, filter input, power and output lines as required and locate filters as close as possible to the g ...
History of AC - Portal UniMAP
... PEAK TO PEAK VALUES (VPP, IPP) • Peak to Peak Voltage (Current) – Symbol VPP ( IPP ) – The difference between the maximum value of V (I) and the minimum value of V (I) – From the graph: VMAX – VMIN – Equals twice peak value VPP = 2VP ...
... PEAK TO PEAK VALUES (VPP, IPP) • Peak to Peak Voltage (Current) – Symbol VPP ( IPP ) – The difference between the maximum value of V (I) and the minimum value of V (I) – From the graph: VMAX – VMIN – Equals twice peak value VPP = 2VP ...
Basic Laws Here we explore two fundamental laws that govern
... two-terminal elements; multi-terminal elements will be modeled using combinations of two-terminal elements. We have already several two-terminal Definition 2.2.1. Since the elements of anseen electric circuit can be inelements such as resistors, voltage sources, and current sources. Electronic terco ...
... two-terminal elements; multi-terminal elements will be modeled using combinations of two-terminal elements. We have already several two-terminal Definition 2.2.1. Since the elements of anseen electric circuit can be inelements such as resistors, voltage sources, and current sources. Electronic terco ...
The Dipole
... circuit. Picturing the dipole folded back to be part of the feed line will make this idea clearer. The current and voltage distribution along the dipole are similar to those for a section of transmission line terminated in an open circuit, where power is reflected. The resulting standing wave patter ...
... circuit. Picturing the dipole folded back to be part of the feed line will make this idea clearer. The current and voltage distribution along the dipole are similar to those for a section of transmission line terminated in an open circuit, where power is reflected. The resulting standing wave patter ...
Feed lines
... If the characteristic impedance of the feedline does not match the antenna input impedance then: standing waves are produced in the feedline The result of the presence of standing waves on a transmission line is: reduced transfer of RF energy to the antenna What does the standing wave ration means? ...
... If the characteristic impedance of the feedline does not match the antenna input impedance then: standing waves are produced in the feedline The result of the presence of standing waves on a transmission line is: reduced transfer of RF energy to the antenna What does the standing wave ration means? ...
Feed lines
... If the characteristic impedance of the feedline does not match the antenna input impedance then: standing waves are produced in the feedline The result of the presence of standing waves on a transmission line is: reduced transfer of RF energy to the antenna What does the standing wave ration means? ...
... If the characteristic impedance of the feedline does not match the antenna input impedance then: standing waves are produced in the feedline The result of the presence of standing waves on a transmission line is: reduced transfer of RF energy to the antenna What does the standing wave ration means? ...
Feed lines
... If the characteristic impedance of the feedline does not match the antenna input impedance then: standing waves are produced in the feedline The result of the presence of standing waves on a transmission line is: reduced transfer of RF energy to the antenna What does the standing wave ration means? ...
... If the characteristic impedance of the feedline does not match the antenna input impedance then: standing waves are produced in the feedline The result of the presence of standing waves on a transmission line is: reduced transfer of RF energy to the antenna What does the standing wave ration means? ...
feedlines
... Why does coaxial cable make a good antenna feed line? It is weatherproof, and its impedance is higher than that of most amateur antennas What is the best antenna feed line to use, if it must be put near grounded metal objects? Coaxial cable What commonly available antenna feed line can be buried dir ...
... Why does coaxial cable make a good antenna feed line? It is weatherproof, and its impedance is higher than that of most amateur antennas What is the best antenna feed line to use, if it must be put near grounded metal objects? Coaxial cable What commonly available antenna feed line can be buried dir ...
Ohm`s and Kirchhoff`s Laws
... The direction of the current flow will be from the high voltage (potential) region to the low voltage (potential) region. The higher voltage side of an element is indicated by a plus (+) sign and the lower voltage side is indicated by a minus (-) sign. Current always flows from the plus to the minus ...
... The direction of the current flow will be from the high voltage (potential) region to the low voltage (potential) region. The higher voltage side of an element is indicated by a plus (+) sign and the lower voltage side is indicated by a minus (-) sign. Current always flows from the plus to the minus ...
Millimeter Wave Corrugated Platelet Feeds
... implicit symmetries of a lumped circuit element – namely that the structure only has a single mode of propagation and length scales characterizing the element are small compared to a wavelength – must be respected over the required design band. Stated another way a simple lumped circuit element can ...
... implicit symmetries of a lumped circuit element – namely that the structure only has a single mode of propagation and length scales characterizing the element are small compared to a wavelength – must be respected over the required design band. Stated another way a simple lumped circuit element can ...
Electrical Resistance
... An ammeter is used to measure the current flowing in a circuit. An ammeter is connected in series with the circuit elements, the current flowing through them is the same as that through the ammeter. A voltmeter is used to measure the potential difference [voltage] across a circuit element or across ...
... An ammeter is used to measure the current flowing in a circuit. An ammeter is connected in series with the circuit elements, the current flowing through them is the same as that through the ammeter. A voltmeter is used to measure the potential difference [voltage] across a circuit element or across ...
6.013 Electromagnetics and Applications, Chapter 11
... infrared region and beyond. The output of an antenna is a voltage or field proportional to the input field strength⎯E(t) and at the same frequency. By this definition, devices that merely amplify, detect, or mix signals are not antennas because they do not preserve phase and frequency, although they ...
... infrared region and beyond. The output of an antenna is a voltage or field proportional to the input field strength⎯E(t) and at the same frequency. By this definition, devices that merely amplify, detect, or mix signals are not antennas because they do not preserve phase and frequency, although they ...
Antenna Theory and Design
... representing the instantaneous electric field. The field must be observed along the direction of propagation. ...
... representing the instantaneous electric field. The field must be observed along the direction of propagation. ...
Complex impedance method for AC circuits
... potential in driving a charge q through a potential difference V is qV . Therefore the rate of doing work on the charges in a circuit, i.e. the power, is P = V dq/dt = V I. In an AC circuit, just as in a mechanical oscillator, the sign of this oscillating work is not in general constant in time. Wha ...
... potential in driving a charge q through a potential difference V is qV . Therefore the rate of doing work on the charges in a circuit, i.e. the power, is P = V dq/dt = V I. In an AC circuit, just as in a mechanical oscillator, the sign of this oscillating work is not in general constant in time. Wha ...
4. Compensation Method
... Connecting the studied galvanic element ε to the points A and C the potentials of point A and one terminal will be equal. By moving the slide C one will find its position when current is zero in the circuit consisting of galvanometer. The potential φC of the point C is then equal to the potential of ...
... Connecting the studied galvanic element ε to the points A and C the potentials of point A and one terminal will be equal. By moving the slide C one will find its position when current is zero in the circuit consisting of galvanometer. The potential φC of the point C is then equal to the potential of ...
A B E D Intermediate conclusion after the 4th week. Correct
... Hints after the 3rd week: In the case of a dodecahedron, current I, if driven into a node P, cannot be driven out at infinity because the circuit is finite. However, there is still a way to drive it out from the nodes of the dodecahedron so that (i) the current distribution remains symmetric; (ii) f ...
... Hints after the 3rd week: In the case of a dodecahedron, current I, if driven into a node P, cannot be driven out at infinity because the circuit is finite. However, there is still a way to drive it out from the nodes of the dodecahedron so that (i) the current distribution remains symmetric; (ii) f ...