MVT 181 - Easun Reyrolle
... The relay is provided with two status inputs, one of which is to be connected across the circuit breaker auxiliary contact 52a. From this the circuit breaker closed or opened condition is found out. This information is used to introduce a time delay between successive switching of the capacitor bank ...
... The relay is provided with two status inputs, one of which is to be connected across the circuit breaker auxiliary contact 52a. From this the circuit breaker closed or opened condition is found out. This information is used to introduce a time delay between successive switching of the capacitor bank ...
L. Huang, W. Rieutort-Louis, A. Gualdino, L. Teagno, Y. Hu, J. Mouro, J. Sanz-Robinson, J.C. Sturm, S. Wagner, V. Chu, J. Conde, and N. Verma, "An ASIC for Readout of Post-processed Thin-film MEMS Resonators by Employing Capacitive Interfacing and Active Parasitic Cancellation", VLSI Symp. on Circuits (VLSI) (JUN2014).
... a corresponding DC component is generated and provided to the integrator, while, with VCP out of phase, the corresponding DC component is nulled. In fact, this approach not only isolates the RMLMCM admittance, but further enhances its resonant peak. In particular, off resonance, the admittance reduc ...
... a corresponding DC component is generated and provided to the integrator, while, with VCP out of phase, the corresponding DC component is nulled. In fact, this approach not only isolates the RMLMCM admittance, but further enhances its resonant peak. In particular, off resonance, the admittance reduc ...
Antenna Theory - The Free Information Society
... 1. General. An antenna is the component of a radio system that is used to send or receive a radio signal. A radio frequency (RF) signal that has been generated in a radio transmitter travels through a transmission line (coaxial cable) to an antenna. An antenna connected to a transmitter is the devi ...
... 1. General. An antenna is the component of a radio system that is used to send or receive a radio signal. A radio frequency (RF) signal that has been generated in a radio transmitter travels through a transmission line (coaxial cable) to an antenna. An antenna connected to a transmitter is the devi ...
High-Frequency RFID Tags: An Analytical and Numerical Approach
... used: ZL = 0 Ω, ZL = 10 MΩ, and ZL = 50 Ω to model a short-circuit load, an open-circuit load, and something close to a matched load. A half-wavelength dipole was used for the tag antenna. The current distribution along the tag antenna is shown in Figure 2. We note that the tag impedance has a defin ...
... used: ZL = 0 Ω, ZL = 10 MΩ, and ZL = 50 Ω to model a short-circuit load, an open-circuit load, and something close to a matched load. A half-wavelength dipole was used for the tag antenna. The current distribution along the tag antenna is shown in Figure 2. We note that the tag impedance has a defin ...
Linear Graph Modeling: One-Port Elements
... The development of a unified modeling methodology requires us to draw analogies between the variables and elements in different energy domains. Several different types of analogs may be defined. In this text we have chosen to relate elements using the concepts of generalized “through” and “across” varia ...
... The development of a unified modeling methodology requires us to draw analogies between the variables and elements in different energy domains. Several different types of analogs may be defined. In this text we have chosen to relate elements using the concepts of generalized “through” and “across” varia ...
EE2003 Circuit Theory
... • Amplitude and phase difference are two principal concerns in the study of voltage and current sinusoids. • Phasor will be defined from the cosine function in all our proceeding study. If a voltage or current expression is in the form of a sine, it will be changed to a cosine by subtracting 90 deg ...
... • Amplitude and phase difference are two principal concerns in the study of voltage and current sinusoids. • Phasor will be defined from the cosine function in all our proceeding study. If a voltage or current expression is in the form of a sine, it will be changed to a cosine by subtracting 90 deg ...
Mesh-Current Method The mesh-current is analog of the node
... Thus, v = va + vb = 5 − 10 = −5 V. Note: Using superposition results in slightly simpler circuits (one element is replaced with either a short or open circuit) but more circuits. In general superposition requires more work than node-voltage or mesh-current methods. Superposition is used: a) If sourc ...
... Thus, v = va + vb = 5 − 10 = −5 V. Note: Using superposition results in slightly simpler circuits (one element is replaced with either a short or open circuit) but more circuits. In general superposition requires more work than node-voltage or mesh-current methods. Superposition is used: a) If sourc ...
Author template for journal articles
... bias, either the current or voltage, limits substantially the effectiveness of the feedback that promotes a rapid cooling of the detector to the operating point. In this paper we try to overcome this restriction: the biasing of the resonant bolometer is periodic by the current and voltage. This supp ...
... bias, either the current or voltage, limits substantially the effectiveness of the feedback that promotes a rapid cooling of the detector to the operating point. In this paper we try to overcome this restriction: the biasing of the resonant bolometer is periodic by the current and voltage. This supp ...
Electrical impedance
... complex terms on the right-hand side. Given the symmetry, we only need to perform the analysis for one right-hand term; the results will be identical for the other. At the end of any calculation, we may return to real-valued sinusoids by further noting that ...
... complex terms on the right-hand side. Given the symmetry, we only need to perform the analysis for one right-hand term; the results will be identical for the other. At the end of any calculation, we may return to real-valued sinusoids by further noting that ...
Laplace Transform Solutions of Transient Circuits
... • In a circuit with energy storage elements, voltages and currents are the solutions to linear, constant coefficient differential equations • Real engineers almost never solve the differential equations directly • It is important to have a qualitative understanding of the solutions Lect13 ...
... • In a circuit with energy storage elements, voltages and currents are the solutions to linear, constant coefficient differential equations • Real engineers almost never solve the differential equations directly • It is important to have a qualitative understanding of the solutions Lect13 ...
Chapter 2
... Using two sorts of constraints, we can analysis any lumped circuit (solve out all the voltages and currents). ...
... Using two sorts of constraints, we can analysis any lumped circuit (solve out all the voltages and currents). ...
Bus Edison Overcurrent Protective Devices
... 10 ohms. The only impedance remaining to oppose the flow of current is 0.02 ohms which is the total impedance of the conductors. Short-circuit current now flows around the load as shown by the arrow in the heavy line. The value of short-circuit current flow for this simple illustration is determined ...
... 10 ohms. The only impedance remaining to oppose the flow of current is 0.02 ohms which is the total impedance of the conductors. Short-circuit current now flows around the load as shown by the arrow in the heavy line. The value of short-circuit current flow for this simple illustration is determined ...
Introduction - Electrical and Computer Engineering
... Energy being supplied by the circuit element Current enters the negative polarity of the voltage ELEC 308 ...
... Energy being supplied by the circuit element Current enters the negative polarity of the voltage ELEC 308 ...
Solution
... found by multiplying the complex current (through the inductor) by the complex impedance of the inductor VL (t) = I(t)ZL . Consistent with the given values, the absolute value of this voltage is V0,L = I0 XL = 20 mA · 200 ω = 4 V. Since the phase of the complex impedance of the inductor is 90◦ , th ...
... found by multiplying the complex current (through the inductor) by the complex impedance of the inductor VL (t) = I(t)ZL . Consistent with the given values, the absolute value of this voltage is V0,L = I0 XL = 20 mA · 200 ω = 4 V. Since the phase of the complex impedance of the inductor is 90◦ , th ...