
Mass Spectrometer
... •These high energy electrons knock an e- from a sample atom. Producing a positive ion. •X(g) X+(g) + e- ...
... •These high energy electrons knock an e- from a sample atom. Producing a positive ion. •X(g) X+(g) + e- ...
South Pasadena A.P. Physics Name Chapter 8 Rotational Motion
... and is accelerated by a force of 150 N at a radius of 1 m from its center. If this force is applied at an angle of 90° from the line of action for a time of 0.5 seconds, what is the final rotational velocity, ω, of the merry-goround? ...
... and is accelerated by a force of 150 N at a radius of 1 m from its center. If this force is applied at an angle of 90° from the line of action for a time of 0.5 seconds, what is the final rotational velocity, ω, of the merry-goround? ...
Unit 3 Powerpoint
... to solve any problem involving onedimensional motion with a constant acceleration You may need to use two of the equations to solve one problem Many times there is more than one way to solve a problem ...
... to solve any problem involving onedimensional motion with a constant acceleration You may need to use two of the equations to solve one problem Many times there is more than one way to solve a problem ...
Circular Motion
... Root word “Tangent” a straight line (LINEAR) or plane that touches a curve or curved surface at a point but does not intersect it at that point 2nd word “Speed” d / t For a constant tangential speed: v = tangential speed, m/s ...
... Root word “Tangent” a straight line (LINEAR) or plane that touches a curve or curved surface at a point but does not intersect it at that point 2nd word “Speed” d / t For a constant tangential speed: v = tangential speed, m/s ...
DP Physics Unit 2 part 2 Practice Test 1. A rocket is fired vertically. At
... the momentum of the gas is equal but opposite in direction to the momentum of the rocket. B. the gas pushes on the air at the back of the rocket. C. the change in momentum of the gas gives rise to a force on the rocket. D. the ejected gas creates a region of high pressure behind the rocket. ...
... the momentum of the gas is equal but opposite in direction to the momentum of the rocket. B. the gas pushes on the air at the back of the rocket. C. the change in momentum of the gas gives rise to a force on the rocket. D. the ejected gas creates a region of high pressure behind the rocket. ...
No Slide Title
... is zero the object continues in its original state of motion; if it was at rest, it remains at rest. If it was moving with a certain velocity, it will keep on moving with the same velocity. Second Law: The acceleration of an object is proportional to the net force acting on it, and inversely propo ...
... is zero the object continues in its original state of motion; if it was at rest, it remains at rest. If it was moving with a certain velocity, it will keep on moving with the same velocity. Second Law: The acceleration of an object is proportional to the net force acting on it, and inversely propo ...
Demonstrate understanding of mechanical systems Level 3 Credits 6
... downward acceleration at the top of the loop is 9.8 ms-2. This is the acceleration of an object which is falling. The aircraft, being accelerated downward at 9.8 ms-2 is effectively falling. If net force =mv2 / R = mg then reaction force = 0 so apparent weight is zero - "weightlessness". ...
... downward acceleration at the top of the loop is 9.8 ms-2. This is the acceleration of an object which is falling. The aircraft, being accelerated downward at 9.8 ms-2 is effectively falling. If net force =mv2 / R = mg then reaction force = 0 so apparent weight is zero - "weightlessness". ...
Lab8_MomentofInertia
... Introduction: You have learned that an unbalanced force causes acceleration and acceleration is a change of velocity. You have also learned that when an object has a velocity we say that the object has kinetic energy, ½ m v2. You then learned about potential energy and how a force such as gravity ca ...
... Introduction: You have learned that an unbalanced force causes acceleration and acceleration is a change of velocity. You have also learned that when an object has a velocity we say that the object has kinetic energy, ½ m v2. You then learned about potential energy and how a force such as gravity ca ...
Physics Review #1
... Cart A has a mass of 2 kg and speed of 3 m/s. Cart B has a mass of 3 kg and speed of 2 m/s. Compared to the inertia and magnitude of momentum of cart A, cart B has (A) the same inertia and a smaller magnitude of momentum (B) the same inertia and the same magnitude of momentum (C) greater inertia an ...
... Cart A has a mass of 2 kg and speed of 3 m/s. Cart B has a mass of 3 kg and speed of 2 m/s. Compared to the inertia and magnitude of momentum of cart A, cart B has (A) the same inertia and a smaller magnitude of momentum (B) the same inertia and the same magnitude of momentum (C) greater inertia an ...
Chapter 3
... Air Resistance If air resistance is negligible, a projectile will rise to its maximum height in the same amount of time it takes it to fall back down. ...
... Air Resistance If air resistance is negligible, a projectile will rise to its maximum height in the same amount of time it takes it to fall back down. ...
Part I - Otterbein
... • We conclude v=dx/dt=2[4.9m/s2]t a=dv/dt=2[4.9m/s2]=9.8m/s2 • Hence the force exerted on the ball must be • F = 9.8/4 kg m/s2 = 2.45 N – Note that the force does not change, since the acceleration does not change: a constant force acts on the ball and accelerates it steadily. ...
... • We conclude v=dx/dt=2[4.9m/s2]t a=dv/dt=2[4.9m/s2]=9.8m/s2 • Hence the force exerted on the ball must be • F = 9.8/4 kg m/s2 = 2.45 N – Note that the force does not change, since the acceleration does not change: a constant force acts on the ball and accelerates it steadily. ...