Lecture-06-09
... In this case the “apparent weight” is the normal force, and is equal to the sum of the gravitational attaction (actual weight) and the force required to accelerate the body, as specified ...
... In this case the “apparent weight” is the normal force, and is equal to the sum of the gravitational attaction (actual weight) and the force required to accelerate the body, as specified ...
Chapter 10
... the speed of the ball is constant, but its direction of travel is continuously changing, so its velocity is not constant; i.e., it has an acceleration. To compute the acceleration, we consider the change in velocity, v, which occurs for a time increment, t, during which the ball rotates through an ...
... the speed of the ball is constant, but its direction of travel is continuously changing, so its velocity is not constant; i.e., it has an acceleration. To compute the acceleration, we consider the change in velocity, v, which occurs for a time increment, t, during which the ball rotates through an ...
Rotational Dynamics and Static Equilibrium
... Conservation of angular momentum means that the total angular momentum around any axis must be constant. This is why gyroscopes are so stable. ...
... Conservation of angular momentum means that the total angular momentum around any axis must be constant. This is why gyroscopes are so stable. ...
Document
... constant speed as it follows a sharp, unbanked curve to the left. You feel the door pushing on the right side of your body. Which of the following forces in the horizontal direction are acting on you? a) a static frictional force between you and the seat b) a normal force of the door c) a force push ...
... constant speed as it follows a sharp, unbanked curve to the left. You feel the door pushing on the right side of your body. Which of the following forces in the horizontal direction are acting on you? a) a static frictional force between you and the seat b) a normal force of the door c) a force push ...
ch13_lecture
... Assume the object is initially pulled to x = A and released from rest As the object moves toward the equilibrium position, F and a decrease, but v increases At x = 0, F and a are zero, but v is a maximum The object’s momentum causes it to overshoot the equilibrium position The force and acceleration ...
... Assume the object is initially pulled to x = A and released from rest As the object moves toward the equilibrium position, F and a decrease, but v increases At x = 0, F and a are zero, but v is a maximum The object’s momentum causes it to overshoot the equilibrium position The force and acceleration ...
to the object`s - Northwest ISD Moodle
... object and its speed When the air resistance magnitude equals the force of gravity magnitude, terminal speed is ...
... object and its speed When the air resistance magnitude equals the force of gravity magnitude, terminal speed is ...
ap physics b
... not talking about a new kind of force, but a new kind of situation in which the same old forces such as, the gravitational force, frictional force, normal force, the tension in a string, or a combination thereof constrain the object to follow a curved path. The centripetal force does NO work on an o ...
... not talking about a new kind of force, but a new kind of situation in which the same old forces such as, the gravitational force, frictional force, normal force, the tension in a string, or a combination thereof constrain the object to follow a curved path. The centripetal force does NO work on an o ...
No Slide Title
... mass, but same length. =I=mL2/3 also =Fd=mgL/2 so =3g/(2L) independent of mass! Compare the angular acceleration for 2 bars of same mass, but different length =3g/(2L) so if L goes up, goes down! PHY 231 ...
... mass, but same length. =I=mL2/3 also =Fd=mgL/2 so =3g/(2L) independent of mass! Compare the angular acceleration for 2 bars of same mass, but different length =3g/(2L) so if L goes up, goes down! PHY 231 ...
HONG KONG EXAMINATIONS AUTHORITY
... A sphere P of mass 2 kg makes a head-on collision with another sphere Q of mass 1 kg which is initially at rest. The speed of P just before collision is 6 m s1. If the two spheres move in the same direction after collision, which of the following could be the speed(s) of Q just after collision ? (1 ...
... A sphere P of mass 2 kg makes a head-on collision with another sphere Q of mass 1 kg which is initially at rest. The speed of P just before collision is 6 m s1. If the two spheres move in the same direction after collision, which of the following could be the speed(s) of Q just after collision ? (1 ...
Special Rotational Dynamics Outline
... Torques Due to Wrapped Strings: Frequently, the AP exam includes problems in which a string is wrapped around an object (kind of like a yo-yo) and then is pulled. If the string does not slip, the torque is the tension at that point times the radius of the object. ...
... Torques Due to Wrapped Strings: Frequently, the AP exam includes problems in which a string is wrapped around an object (kind of like a yo-yo) and then is pulled. If the string does not slip, the torque is the tension at that point times the radius of the object. ...
Chapter 5
... For a fixed mass, the conservation of linear momentum is equivalent to Newton’s second law: ...
... For a fixed mass, the conservation of linear momentum is equivalent to Newton’s second law: ...
here
... Unclear work will not be graded. Use g=10m/s2. Write the conservation of energy equations for any mathematical problem. 1. Describe the law of conservation of energy in your own terms. 2. What are the units for: a) Kinetic Energy b) Spring Energy d) Work ...
... Unclear work will not be graded. Use g=10m/s2. Write the conservation of energy equations for any mathematical problem. 1. Describe the law of conservation of energy in your own terms. 2. What are the units for: a) Kinetic Energy b) Spring Energy d) Work ...
(Work together) Consider the child, initially at rest
... upward force, in which case the upward rope force must “beat” the downward gravitational force to make the child move up. Can we reconcile that intuition with the Newtonian conclusion that the upward force merely equals the downward force? In a previous tutorial and in lecture, you learned about Ref ...
... upward force, in which case the upward rope force must “beat” the downward gravitational force to make the child move up. Can we reconcile that intuition with the Newtonian conclusion that the upward force merely equals the downward force? In a previous tutorial and in lecture, you learned about Ref ...
