CE ConsEnergy
... The energy distributions illustrated in Figure 3.5 are for ideal situation in which no energy is lost to the surroundings. Notice that at all three positions, the distribution of the two forms of mechanical energy varies but the total mechanical energy remains the same. As the student slides down, ...
... The energy distributions illustrated in Figure 3.5 are for ideal situation in which no energy is lost to the surroundings. Notice that at all three positions, the distribution of the two forms of mechanical energy varies but the total mechanical energy remains the same. As the student slides down, ...
Ch 08 B1 QFD.cwk (WP)
... 5. A disk is rotating about a stationary axis. Consider point P on the rim of the disk. (a) Under what conditions will the linear velocity of point P be parallel to its tangential acceleration? (b) Under what conditions will the linear velocity of point P be perpendicular to its (total) linear accel ...
... 5. A disk is rotating about a stationary axis. Consider point P on the rim of the disk. (a) Under what conditions will the linear velocity of point P be parallel to its tangential acceleration? (b) Under what conditions will the linear velocity of point P be perpendicular to its (total) linear accel ...
pdf - at www.arxiv.org.
... Figure 4: A disk is rolling without slipping on a horizontal surface. We can use three pivots for instance: A, C and CM. Let us note that the contact point C is usually considered like a point “momentarily at rest”, because there is no relative motion between disk and horizontal surface. In this man ...
... Figure 4: A disk is rolling without slipping on a horizontal surface. We can use three pivots for instance: A, C and CM. Let us note that the contact point C is usually considered like a point “momentarily at rest”, because there is no relative motion between disk and horizontal surface. In this man ...
Widener University
... A bullet of mass 4.5 x 10-3 kg is fired horizontally into a 2.4 kg wooden block at rest on a horizontal surface. The coefficient of kinetic friction between block and surface is k = 0.20. The bullet comes to rest in the block, which moves 1.8 m after collision. Calculate: a) the speed of the block ...
... A bullet of mass 4.5 x 10-3 kg is fired horizontally into a 2.4 kg wooden block at rest on a horizontal surface. The coefficient of kinetic friction between block and surface is k = 0.20. The bullet comes to rest in the block, which moves 1.8 m after collision. Calculate: a) the speed of the block ...
REVIEW 10 Force and Motion Just as Alicia was about to kick the
... scientists in human history. But how did Newton view himself? As an old man, this is what he wrote of himself: "I do not know what I may appear to the world, but to myself I seem to have been only like a boy playing on the seashore, and diverting myself in now and then finding a smoother pebble or a ...
... scientists in human history. But how did Newton view himself? As an old man, this is what he wrote of himself: "I do not know what I may appear to the world, but to myself I seem to have been only like a boy playing on the seashore, and diverting myself in now and then finding a smoother pebble or a ...
Name: Class: Date:______ Physics Forces Exam Part 1: Multiple
... An object in motion stays in motion unless acted upon by an unbalanced force. For every action, there is an equal and opposite reaction. A constant net force acting on an object produces a change in the object’ s motion. Energy is neither created not destroyed; it simply changes form. ...
... An object in motion stays in motion unless acted upon by an unbalanced force. For every action, there is an equal and opposite reaction. A constant net force acting on an object produces a change in the object’ s motion. Energy is neither created not destroyed; it simply changes form. ...
Center of Mass, Angular Momentum
... In particular, if there are no applied torques, then L = constant, which leads to Principle of Conservation of Angular Momentum If the net external torque ext on an N-particle system is zero, the system’s total angular momentum L = S ra× pa is constant. ...
... In particular, if there are no applied torques, then L = constant, which leads to Principle of Conservation of Angular Momentum If the net external torque ext on an N-particle system is zero, the system’s total angular momentum L = S ra× pa is constant. ...
Tuesday, June 3, 2008
... Newton’s First Law Aristotle (384-322BC): A natural state of a body is rest. Thus force is required to move an object. To move faster, ones needs larger forces. Galileo’s statement on natural states of matter: Any velocity once imparted to a moving body will be rigidly maintained as long as the ext ...
... Newton’s First Law Aristotle (384-322BC): A natural state of a body is rest. Thus force is required to move an object. To move faster, ones needs larger forces. Galileo’s statement on natural states of matter: Any velocity once imparted to a moving body will be rigidly maintained as long as the ext ...
Document
... If one component of the net force is not 0, then that component of momentum is not a constant. For example, consider the motion of a horizontally fired projectile. The y component of P changes while the horizontal component is fixed after the bullet is fired. ...
... If one component of the net force is not 0, then that component of momentum is not a constant. For example, consider the motion of a horizontally fired projectile. The y component of P changes while the horizontal component is fixed after the bullet is fired. ...
motion in one dimension
... physical concepts (such as forces & mass) • KYNEMATICS – the part of dynamics that describe motion ...
... physical concepts (such as forces & mass) • KYNEMATICS – the part of dynamics that describe motion ...
True motion, relative motion, and universal gravity
... flat surface with the line drawn from the center of the Sun to the center of the Earth. For, such a force, acting on all bodies equally along parallel lines, does not change their positions among themselves, and permits bodies to move among themselves through the forces of universal gravity in the s ...
... flat surface with the line drawn from the center of the Sun to the center of the Earth. For, such a force, acting on all bodies equally along parallel lines, does not change their positions among themselves, and permits bodies to move among themselves through the forces of universal gravity in the s ...
Section 13.10 Interference of Waves
... surface and is attached to the free end of the spring. The particle is pulled horizontally so that it stretches the spring 5.00 cm and is then released from rest at t = 0. (a) What is the force constant of the spring? (b) What are the angular frequency ω, the frequency, and the period of the motion? ...
... surface and is attached to the free end of the spring. The particle is pulled horizontally so that it stretches the spring 5.00 cm and is then released from rest at t = 0. (a) What is the force constant of the spring? (b) What are the angular frequency ω, the frequency, and the period of the motion? ...
Answers to Challenge/ extension
... vf is the final speed. We can call vf simply v. Fd = mv2/2 So kinetic energy = mv2/2. This is a nice equation, because acceleration is taken out of it - all you need to know is an object's mass and velocity. If you get hit in the head with a coconut, it doesn't matter whether it fell from a tree ...
... vf is the final speed. We can call vf simply v. Fd = mv2/2 So kinetic energy = mv2/2. This is a nice equation, because acceleration is taken out of it - all you need to know is an object's mass and velocity. If you get hit in the head with a coconut, it doesn't matter whether it fell from a tree ...
solutions to problem set 8
... rearrange the above equation to find the requisite centripetal force for keeping the skier along the presumably circular path. m [v (α)]2 = 2mg (1 − cos α) r The centripetal force (due to gravity) will be mg cos α, so the skier will remain on the snowball as long as gravity can hold her to that path, ...
... rearrange the above equation to find the requisite centripetal force for keeping the skier along the presumably circular path. m [v (α)]2 = 2mg (1 − cos α) r The centripetal force (due to gravity) will be mg cos α, so the skier will remain on the snowball as long as gravity can hold her to that path, ...
Hunting oscillation
Hunting oscillation is a self-oscillation, usually unwanted, about an equilibrium. The expression came into use in the 19th century and describes how a system ""hunts"" for equilibrium. The expression is used to describe phenomena in such diverse fields as electronics, aviation, biology, and railway engineering.