the forces are exerted on different objects
... 4-5 Newton’s Third Law of Motion Conceptual Example 4-4: What exerts the force to move a car? Response: A common answer is that the engine makes the car move forward. But it is not so simple. The engine makes the wheels go around. But if the tires are on slick ice or deep mud, they just spin. Frict ...
... 4-5 Newton’s Third Law of Motion Conceptual Example 4-4: What exerts the force to move a car? Response: A common answer is that the engine makes the car move forward. But it is not so simple. The engine makes the wheels go around. But if the tires are on slick ice or deep mud, they just spin. Frict ...
Lectures 32, 33, 34
... Two men of equal mass are skating in a circle on a perfectly frictionless pond. They are each holding onto a rope of length R. What happens to the magnitude of momentum p of each man if they both pull on the rope, “hand over hand”, and shorten the distance between them to R/2. (Assume the men agai ...
... Two men of equal mass are skating in a circle on a perfectly frictionless pond. They are each holding onto a rope of length R. What happens to the magnitude of momentum p of each man if they both pull on the rope, “hand over hand”, and shorten the distance between them to R/2. (Assume the men agai ...
6.2 Newton`s Second Law
... Keep the following important ideas in mind: 1. The net force is what causes acceleration. 2. If there is no acceleration, the net force must be zero. 3. If there is acceleration, there must also be a net force. 4. The force unit of newtons is ...
... Keep the following important ideas in mind: 1. The net force is what causes acceleration. 2. If there is no acceleration, the net force must be zero. 3. If there is acceleration, there must also be a net force. 4. The force unit of newtons is ...
Unit C2: Scheme of Work
... and the word resultant; (e) multiplication by a scalar, inverse and subtraction. The triangle for vector addition is so important in later work on force and the students need a solid picture of it in their minds. ...
... and the word resultant; (e) multiplication by a scalar, inverse and subtraction. The triangle for vector addition is so important in later work on force and the students need a solid picture of it in their minds. ...
Unbalanced Forces – Advanced Problem Solving
... DIRECTIONS: Read the following sections (including the example problems) and then complete the problems. Hopefully, at this point in the year, we understand the difference between balanced and unbalanced forces. ...
... DIRECTIONS: Read the following sections (including the example problems) and then complete the problems. Hopefully, at this point in the year, we understand the difference between balanced and unbalanced forces. ...
Course: Physics 11 Big Ideas Elaborations: CORE MODULES: 1
... Elaborations: 1-D Kinematics vector: e.g., solve for vector components and vector addition projectile motion principles: vertical projectiles and simple 2-D projectiles (e.g., cannon being fired off cliff) the relationship between variables: Refer to the formula sheet 1-D Dynamics gravitational forc ...
... Elaborations: 1-D Kinematics vector: e.g., solve for vector components and vector addition projectile motion principles: vertical projectiles and simple 2-D projectiles (e.g., cannon being fired off cliff) the relationship between variables: Refer to the formula sheet 1-D Dynamics gravitational forc ...
Speed up Slow down Change direction 2 m/s 2 Ball rolling down a
... •Obj. may or may not move •Affects acceleration •More mass need more force ...
... •Obj. may or may not move •Affects acceleration •More mass need more force ...
Forces in One Direction
... Newton’s Second Law • The acceleration of an object is directly proportional to the net force acting on the object, is in the direction of the net force, and is inversely proportional to the mass of the object. • a = F/m • This can be rearranged to solve for forces. ...
... Newton’s Second Law • The acceleration of an object is directly proportional to the net force acting on the object, is in the direction of the net force, and is inversely proportional to the mass of the object. • a = F/m • This can be rearranged to solve for forces. ...
Name Period Date Student Sheet 3.1 Conceptual Physical Science
... the y coordinates is the “rise” and the difference of x coordinates is the “run.” Calculate the slope by dividing the rise by the run. Plug these values into the general equation for any straight line: y = kx + b where k is the slope and b is the y-intercept. The y-intercept of the boulder’s velocit ...
... the y coordinates is the “rise” and the difference of x coordinates is the “run.” Calculate the slope by dividing the rise by the run. Plug these values into the general equation for any straight line: y = kx + b where k is the slope and b is the y-intercept. The y-intercept of the boulder’s velocit ...