PHYSICS 231 INTRODUCTORY PHYSICS I Lecture 4
... Newton’s First Law • If the net force exerted on an object is zero, its velocity remains constant (both magnitude and direction). • Objects at rest feel no net force • Objects moving with constant velocity feel no net force • No net force means ...
... Newton’s First Law • If the net force exerted on an object is zero, its velocity remains constant (both magnitude and direction). • Objects at rest feel no net force • Objects moving with constant velocity feel no net force • No net force means ...
Systems Solve by Substitution
... Solving Systems of Equations You can solve a system of equations using different methods. The idea is to determine which method is easiest for ...
... Solving Systems of Equations You can solve a system of equations using different methods. The idea is to determine which method is easiest for ...
Newton`s 2nd Law
... For example, weight (force of gravity) for 1 kg is ( 9.8 Newtons ) = ( 1 kg ) X ( 9.8 m/s2 ) ...
... For example, weight (force of gravity) for 1 kg is ( 9.8 Newtons ) = ( 1 kg ) X ( 9.8 m/s2 ) ...
Resultant velocity of a horizontal projectile
... The figure above illustrates a body thrown horizontally from a point O with a velocity The point O is at a certain height above the ground.� Let x and y be the horizontal and vertical distances covered by the projectile, respectively, in time t. Therefore, at time t, the projectile is at p. In orde ...
... The figure above illustrates a body thrown horizontally from a point O with a velocity The point O is at a certain height above the ground.� Let x and y be the horizontal and vertical distances covered by the projectile, respectively, in time t. Therefore, at time t, the projectile is at p. In orde ...
Lecture 6.Forces
... A) more than its weight B) equal to its weight C) less than its weight but more than zero D) depends on the speed of the puck E) zero ...
... A) more than its weight B) equal to its weight C) less than its weight but more than zero D) depends on the speed of the puck E) zero ...
Bringing Newton`s Laws to Life
... • Pulling on the ends of the rope is a force in the ±x direction. • Pushing down on the rope is a force in the – y direction. • Since these force components are perpendicular to each other, one should not affect the other. • Summary: The ease at which you can push down on the center of the rope has ...
... • Pulling on the ends of the rope is a force in the ±x direction. • Pushing down on the rope is a force in the – y direction. • Since these force components are perpendicular to each other, one should not affect the other. • Summary: The ease at which you can push down on the center of the rope has ...
Force and Motion Demos - California State University, Long Beach
... • Pulling on the ends of the rope is a force in the ±x direction. • Pushing down on the rope is a force in the – y direction. • Since these force components are perpendicular to each other, one should not affect the other. • Summary: The ease at which you can push down on the center of the rope has ...
... • Pulling on the ends of the rope is a force in the ±x direction. • Pushing down on the rope is a force in the – y direction. • Since these force components are perpendicular to each other, one should not affect the other. • Summary: The ease at which you can push down on the center of the rope has ...
Forces
... Some say that the first law is a special case of the second law. However, the way I like to think about this law is that it defines “natural motion” [not an official vocabulary word in p ...
... Some say that the first law is a special case of the second law. However, the way I like to think about this law is that it defines “natural motion” [not an official vocabulary word in p ...
Solutions to Problems in Goldstein, Classical Mechanics
... (a) Show that if a particle describes a circular orbit under the influence of an attractive central force directed at a point on the circle, then the force varies as the inverse fifth power of the distance. (b) Show that for the orbit described the total energy of the particle is zero. (c) Find the ...
... (a) Show that if a particle describes a circular orbit under the influence of an attractive central force directed at a point on the circle, then the force varies as the inverse fifth power of the distance. (b) Show that for the orbit described the total energy of the particle is zero. (c) Find the ...
lecture 10
... plane of angle a: Scleronomic (constraint does not involve time) Non-holonomic (cylinder leaves the inclined plane at some point) Conservative (gravitational force acting is derivable from a potential) A sphere rolling down another sphere which is rolling with a uniform speed along a horizontal plan ...
... plane of angle a: Scleronomic (constraint does not involve time) Non-holonomic (cylinder leaves the inclined plane at some point) Conservative (gravitational force acting is derivable from a potential) A sphere rolling down another sphere which is rolling with a uniform speed along a horizontal plan ...
![Forces-part2 [Compatibility Mode]](http://s1.studyres.com/store/data/008777900_1-5d589672d0a73f66816cf69cd76bbed3-300x300.png)
Forces-part2 [Compatibility Mode]
... Inertial reference frame • An inertial reference frame is one in which an observer: Sees no change in the velocity if the sum of all forces exerted on the system object is zero The force diagram and the motion diagram match. ...
... Inertial reference frame • An inertial reference frame is one in which an observer: Sees no change in the velocity if the sum of all forces exerted on the system object is zero The force diagram and the motion diagram match. ...
When astronauts are in the space shuttle
... To understand the whole picture, however, we need to understand the motion of the Moon around the Earth. Forget the Sun for a moment, then the system Earth-Moon is moving uniformly – no external forces. Both Earth and Moon are massive – act on each other with forces of gravity. Why the Moon do ...
... To understand the whole picture, however, we need to understand the motion of the Moon around the Earth. Forget the Sun for a moment, then the system Earth-Moon is moving uniformly – no external forces. Both Earth and Moon are massive – act on each other with forces of gravity. Why the Moon do ...
Newton`s Laws: Jars, Cars, and Balloons
... each jar on its side and release both from the top of the “ramps” at exactly the same time. 5. In the Table below, record how far each jar rolled. Do not measure the binder itself, just the distance from the end of the binder to where each jar actually stopped. 6. Repeat Steps 3-4 for each of the su ...
... each jar on its side and release both from the top of the “ramps” at exactly the same time. 5. In the Table below, record how far each jar rolled. Do not measure the binder itself, just the distance from the end of the binder to where each jar actually stopped. 6. Repeat Steps 3-4 for each of the su ...
