Presentation
... mass m and radius r. The three objects are arranged so that an axis of rotation passes through the center of each object. The rotation axis is perpendicular to the plane of the flat disk. Which of the three objects has the largest moment of inertia? a) The solid sphere and hollow sphere have the sam ...
... mass m and radius r. The three objects are arranged so that an axis of rotation passes through the center of each object. The rotation axis is perpendicular to the plane of the flat disk. Which of the three objects has the largest moment of inertia? a) The solid sphere and hollow sphere have the sam ...
Forces and Motion
... The acceleration of an object is directly proportional to the force acting on it. Force (increases) = Acceleration (increases) The acceleration is inversely proportional to the objects mass. Mass (increase) = Acceleration (decreases) ...
... The acceleration of an object is directly proportional to the force acting on it. Force (increases) = Acceleration (increases) The acceleration is inversely proportional to the objects mass. Mass (increase) = Acceleration (decreases) ...
Chapter 4 Forces and Newton’s Laws of Motion continued
... An object is in equilibrium when it has zero acceleration. ...
... An object is in equilibrium when it has zero acceleration. ...
System of linear equations
... completely dropped out of the solution, leaving only a single solution. In other cases, though, remains and hence an infinitude of potential values of the free parameter vector give an infinitude of solutions of the equation. ...
... completely dropped out of the solution, leaving only a single solution. In other cases, though, remains and hence an infinitude of potential values of the free parameter vector give an infinitude of solutions of the equation. ...
What you need to be able to do
... (b) No force is needed; moving objects tend to slow down. (c) The puck is moving one direction and friction is pushing in the opposite direction. 9) Ingrid drops the 3-kg steel puck and the 1-kg aluminum puck at the same time from the same height. Ingrid observes that the pucks land at the same time ...
... (b) No force is needed; moving objects tend to slow down. (c) The puck is moving one direction and friction is pushing in the opposite direction. 9) Ingrid drops the 3-kg steel puck and the 1-kg aluminum puck at the same time from the same height. Ingrid observes that the pucks land at the same time ...
F - Cloudfront.net
... IP = ICM + MR2 (M is the mass of the wheel, Icm is its rotational inertia about an axis through its center of mass, and R is the wheel’s radius, at a perpendicular distance h). Using the relation vcm =R, we get: ...
... IP = ICM + MR2 (M is the mass of the wheel, Icm is its rotational inertia about an axis through its center of mass, and R is the wheel’s radius, at a perpendicular distance h). Using the relation vcm =R, we get: ...
Linking Asteroids and Meteorites through Reflectance
... Questions: • Compare the momentum of a 1 kg cart moving at 10 m/s with that of a 2 kg cart moving at 5 m/s. • Does the moving cart have impulse? • Does a moving cart have momentum? • For the same force, which cannon imparts a greater impulse to a cannonball – a long cannon or a short one? ...
... Questions: • Compare the momentum of a 1 kg cart moving at 10 m/s with that of a 2 kg cart moving at 5 m/s. • Does the moving cart have impulse? • Does a moving cart have momentum? • For the same force, which cannon imparts a greater impulse to a cannonball – a long cannon or a short one? ...
Chapter 5, Part IV
... • The force given above is strictly valid only for: – Very small masses m1 & m2 (point masses) – Uniform spheres • For other objects: Need integral calculus! ...
... • The force given above is strictly valid only for: – Very small masses m1 & m2 (point masses) – Uniform spheres • For other objects: Need integral calculus! ...
A Collection of Problems in Rigid Body and Analytical
... Problem 9 A top consists of of a homogeneous, circular disc of radius r, and a light axis of length r/2 perpendicular to the disc through its center. The axis is connected by a joint to a point A on the periphery of a horizontal circular merry-go-round of radius R, so that the axis of the top can mo ...
... Problem 9 A top consists of of a homogeneous, circular disc of radius r, and a light axis of length r/2 perpendicular to the disc through its center. The axis is connected by a joint to a point A on the periphery of a horizontal circular merry-go-round of radius R, so that the axis of the top can mo ...
Forces and Motion
... Special Applications of Newton’s Laws Weight and Friction Weight – The force between too bodies, usually between a large mass and a much smaller mass Weight is not an inherent property of an object (like mass or inertia) but is location dependent The farther an object is from the center of the mass ...
... Special Applications of Newton’s Laws Weight and Friction Weight – The force between too bodies, usually between a large mass and a much smaller mass Weight is not an inherent property of an object (like mass or inertia) but is location dependent The farther an object is from the center of the mass ...
Midterms: Place, Rules, How to study
... PLACE AND TIME: Friday, September 16 we have the first midterm, covering Units 1-6. All midterms will be during regular class hours but will take place in the S Beh auditorium which is located south of the Marriott Library - check it out on the campus map. If possible, please be there at least 5 min ...
... PLACE AND TIME: Friday, September 16 we have the first midterm, covering Units 1-6. All midterms will be during regular class hours but will take place in the S Beh auditorium which is located south of the Marriott Library - check it out on the campus map. If possible, please be there at least 5 min ...
Wednesday, July 14, 2004
... To simplify the problem, we will only deal with forces acting on x-y plane, giving torque only along z-axis. What do you think the conditions for equilibrium be in this case? The six possible equations from the two vector equations turns to three equations. ...
... To simplify the problem, we will only deal with forces acting on x-y plane, giving torque only along z-axis. What do you think the conditions for equilibrium be in this case? The six possible equations from the two vector equations turns to three equations. ...
Chapter 4: Forces and Newton`s Laws of Motion
... The free body diagram (FBD) is a simplified representation of an object, and the forces acting on it. It is called free because the diagram will show the object without its surroundings; i.e. the body is “free” of its environment. We will consider only the forces acting on our object of interest. Th ...
... The free body diagram (FBD) is a simplified representation of an object, and the forces acting on it. It is called free because the diagram will show the object without its surroundings; i.e. the body is “free” of its environment. We will consider only the forces acting on our object of interest. Th ...
Wizard Test Maker
... 19. Which combination of fundamental unit can be used to express the weight of an object? (A) kilogram/second (C) kilogram•meter/second (B) kilogram•meter (D) kilogram•meter/second2 20. Which two quantities are measured in the same units? (A) velocity and acceleration (C) mass and weight (B) weight ...
... 19. Which combination of fundamental unit can be used to express the weight of an object? (A) kilogram/second (C) kilogram•meter/second (B) kilogram•meter (D) kilogram•meter/second2 20. Which two quantities are measured in the same units? (A) velocity and acceleration (C) mass and weight (B) weight ...