Set #6 - McMaster Physics and Astronomy
... 3.88 cm. A friction clutch in the reel exerts a restraining torque of 1.19 N·m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 67.1 rad/s2. What is the force of the fish on the line? Answer: 3.18e+01 N ...
... 3.88 cm. A friction clutch in the reel exerts a restraining torque of 1.19 N·m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 67.1 rad/s2. What is the force of the fish on the line? Answer: 3.18e+01 N ...
Chapter 2 Stations Review
... 4. You are playing ping pong with your friend. The mass of the ping pong ball is 5g. You notice an increase in acceleration of the ball when playing. What did you to your force? Force: ____________ Mass: _______________ Acceleration: _________________ What is the relationship between acceleration an ...
... 4. You are playing ping pong with your friend. The mass of the ping pong ball is 5g. You notice an increase in acceleration of the ball when playing. What did you to your force? Force: ____________ Mass: _______________ Acceleration: _________________ What is the relationship between acceleration an ...
PHY203F08 Exam 3 Name
... 11. Two wheels with moments of inertia I1 = 40 kgm2 and I2 = 60 kgm2 are rotating about the same axle. The first is rotating clockwise at 2.0 rad/s, and the second is rotating counterclockwise at 6.0 rad/s. With clockwise being negative, a) angular momentum of the first wheel is ...
... 11. Two wheels with moments of inertia I1 = 40 kgm2 and I2 = 60 kgm2 are rotating about the same axle. The first is rotating clockwise at 2.0 rad/s, and the second is rotating counterclockwise at 6.0 rad/s. With clockwise being negative, a) angular momentum of the first wheel is ...
Experiments Involving Static Equilibrium
... Activity D: Constructing a single-beam balance 1. Place the 500-g mass at the 0.4-m mark. 2. Use the object of unknown mass to balance the meterstick. 3. Knowing the position of this object that keeps the meterstick in equilibrium, determine the mass of this object. 4. Measure the mass of this objec ...
... Activity D: Constructing a single-beam balance 1. Place the 500-g mass at the 0.4-m mark. 2. Use the object of unknown mass to balance the meterstick. 3. Knowing the position of this object that keeps the meterstick in equilibrium, determine the mass of this object. 4. Measure the mass of this objec ...
Ch. 11.3
... Newton’s Laws • 1. An object in motion or rest remains the same unless acted on by a force. • 2. Force= mass x acceleration. The amount of force needed to move an object is equal to the amount of mass in the object and how much you want to accelerate it. • 3. For every action there is an = and oppo ...
... Newton’s Laws • 1. An object in motion or rest remains the same unless acted on by a force. • 2. Force= mass x acceleration. The amount of force needed to move an object is equal to the amount of mass in the object and how much you want to accelerate it. • 3. For every action there is an = and oppo ...
Exam 2 Physics 125 Fall 2008 Name:
... 5. Immediately after a football on the ground is kicked, it acquires a velocity whose magnitude is 25 m/s and whose direction is at 65° with the horizontal. Neglecting air resistance, find how long the ball stays in the air. (a) (b) (c) (d) ...
... 5. Immediately after a football on the ground is kicked, it acquires a velocity whose magnitude is 25 m/s and whose direction is at 65° with the horizontal. Neglecting air resistance, find how long the ball stays in the air. (a) (b) (c) (d) ...
Ch 3 semester 2 review study guide
... 12. How much does the same car weigh on Jupiter if the acceleration due to gravity is 25.4 m/s2? ...
... 12. How much does the same car weigh on Jupiter if the acceleration due to gravity is 25.4 m/s2? ...
Circular Motion
... • Note that m is the mass of the central object that is being orbited. The mass of the planet or satellite that is in orbit does not affect its speed or period. • The mean radius (r) is the distance between the centers of the two bodies. ...
... • Note that m is the mass of the central object that is being orbited. The mass of the planet or satellite that is in orbit does not affect its speed or period. • The mean radius (r) is the distance between the centers of the two bodies. ...
Power Point presentation - Physics 420 UBC Physics Demonstrations
... What is oscillatory motion? • Oscillatory motion occurs when a force acting on a body is proportional to the displacement of the body from equilibrium. F x • The Force acts towards the equilibrium position causing a periodic back and forth motion. ...
... What is oscillatory motion? • Oscillatory motion occurs when a force acting on a body is proportional to the displacement of the body from equilibrium. F x • The Force acts towards the equilibrium position causing a periodic back and forth motion. ...
Intro Forces and Newton`s 3 Laws
... What is the Fnet acting on this box: ΣF = Fnet = F1 - F2 = 20 N - 20 N = 0 FORCES ARE BALANCED The Fnet is zero which means there is not a change in movement or direction. This box will continue to move with a constant velocity. ...
... What is the Fnet acting on this box: ΣF = Fnet = F1 - F2 = 20 N - 20 N = 0 FORCES ARE BALANCED The Fnet is zero which means there is not a change in movement or direction. This box will continue to move with a constant velocity. ...
Q No - Air University
... c) Calculate the distance of the CM of uniform thin rod of mass m and length l from one of its ends. (2) b) What are the values of xc for m1 ...
... c) Calculate the distance of the CM of uniform thin rod of mass m and length l from one of its ends. (2) b) What are the values of xc for m1 ...
File - Phy 2048-0002
... Two astronauts, each having a mass of 75.0 kg, are connected by a 10.0-m rope of negligible mass. They are isolated in space, orbiting their center of mass at speeds of 5.00 m/s. Treating the astronauts as particles, calculate (a) the magnitude of the angular momentum of the system and (b) the rota ...
... Two astronauts, each having a mass of 75.0 kg, are connected by a 10.0-m rope of negligible mass. They are isolated in space, orbiting their center of mass at speeds of 5.00 m/s. Treating the astronauts as particles, calculate (a) the magnitude of the angular momentum of the system and (b) the rota ...
survey of physics - Stevenson High School
... 12. The hefty toddler (25 kg) was placed on a frictionless slide (30 angle with the ground). Draw a force vector diagram of the child on the slide. Solve for the normal force upon the child. What is the net force acting upon the child? What acceleration will the child experience. Assuming the child ...
... 12. The hefty toddler (25 kg) was placed on a frictionless slide (30 angle with the ground). Draw a force vector diagram of the child on the slide. Solve for the normal force upon the child. What is the net force acting upon the child? What acceleration will the child experience. Assuming the child ...
Circular Motion
... A newspaper report reads in part, “ The space shuttle orbits Earth at an altitude of nearly 200 miles and is traveling at a speed of 18,000 mph. The shuttle remains in orbit because the gravitational force pulling it toward Earth is balanced by the centrifugal force (the force of inertia) that is pu ...
... A newspaper report reads in part, “ The space shuttle orbits Earth at an altitude of nearly 200 miles and is traveling at a speed of 18,000 mph. The shuttle remains in orbit because the gravitational force pulling it toward Earth is balanced by the centrifugal force (the force of inertia) that is pu ...
Rotational Dynamics PowerPoint
... Summary of Rotational Motion • The equations for rotational motion with constant angular acceleration have the same form as those for linear motion with constant acceleration. • Torque is the product of force and lever arm. • The rotational inertia depends not only on the mass of an object but also ...
... Summary of Rotational Motion • The equations for rotational motion with constant angular acceleration have the same form as those for linear motion with constant acceleration. • Torque is the product of force and lever arm. • The rotational inertia depends not only on the mass of an object but also ...
