Ch 7 Impulse and Momentum
... Law of conservation of momentum A net force is required to change an object’s momentum (Newton’s 2 nd law). You probably remember from Newton’s 3rd law that forces always occur in pairs (action-reaction), so when two objects interact the forces they apply on each other must be equal in magnitude ...
... Law of conservation of momentum A net force is required to change an object’s momentum (Newton’s 2 nd law). You probably remember from Newton’s 3rd law that forces always occur in pairs (action-reaction), so when two objects interact the forces they apply on each other must be equal in magnitude ...
lecture-no-4-Quiz-law-of-newton
... on block of mass 3 kg. Find the resultant force and acceleration of the block ? 2. A girl of 50kg mass is running with speed 7m/s on a rough horizontal floor skids a distance 4 m till stopped . Find the force of friction 3. An box of mass m=10Kg is pulled by a force F on a smooth horizontal floor. I ...
... on block of mass 3 kg. Find the resultant force and acceleration of the block ? 2. A girl of 50kg mass is running with speed 7m/s on a rough horizontal floor skids a distance 4 m till stopped . Find the force of friction 3. An box of mass m=10Kg is pulled by a force F on a smooth horizontal floor. I ...
Intro Sheet
... Essential Knowledge 3.B.2: Free-body diagrams are useful tools for visualizing forces being exerted on a single object and writing the equations that represent a physical situation. ...
... Essential Knowledge 3.B.2: Free-body diagrams are useful tools for visualizing forces being exerted on a single object and writing the equations that represent a physical situation. ...
Document
... This is the simplest form of motion, and we deal with it in most of our discussion of motion. A simple example of linear motion is a car moving along a straight and Level road. ...
... This is the simplest form of motion, and we deal with it in most of our discussion of motion. A simple example of linear motion is a car moving along a straight and Level road. ...
Chapter 3-
... Momentum is the property of a moving object. The momentum of an object is the product of its mass and velocity. Momentum is represented by the symbol (p) and can be calculated as follows: Momentum (p) = mass (m) x velocity (v) The SI unit for momentum is kg x m/s ...
... Momentum is the property of a moving object. The momentum of an object is the product of its mass and velocity. Momentum is represented by the symbol (p) and can be calculated as follows: Momentum (p) = mass (m) x velocity (v) The SI unit for momentum is kg x m/s ...
Wednesday, Feb. 16, 2011
... Field Forces: Forces exerted without physical contact of objects Examples of Field Forces: Gravitational Force, Electro-magnetic force What are possible ways to measure strength of a force? A calibrated spring whose length changes linearly with the force exerted . Forces are vector quantities, so th ...
... Field Forces: Forces exerted without physical contact of objects Examples of Field Forces: Gravitational Force, Electro-magnetic force What are possible ways to measure strength of a force? A calibrated spring whose length changes linearly with the force exerted . Forces are vector quantities, so th ...
Physics I - Rose
... more direct upward pull). The magnitude of the traction force, roughly one-tenth the weight of a human body, seems reasonable. 5.40. Model: We assume that Sam is a particle moving in a straight horizontal line under the influence of two forces: the thrust of his jet skis and the resisting force of f ...
... more direct upward pull). The magnitude of the traction force, roughly one-tenth the weight of a human body, seems reasonable. 5.40. Model: We assume that Sam is a particle moving in a straight horizontal line under the influence of two forces: the thrust of his jet skis and the resisting force of f ...
NEWTON`S FIRST LAW CONCEPTUAL WORKSHEET
... A metal ball is put into the end of the tube indicated by the arrow. The ball is then shot out of the other end of the tube at high speed. Pick the path the ball will follow after it exits the tube. Note – you are looking down on these tubes, they are not vertical. ...
... A metal ball is put into the end of the tube indicated by the arrow. The ball is then shot out of the other end of the tube at high speed. Pick the path the ball will follow after it exits the tube. Note – you are looking down on these tubes, they are not vertical. ...
Chapter 6. Central Force Motion
... It is to be noted that the centrifugal potential “reduces” the effect of the inverse-squarelaw on the particle. This is because the inverse-square-law force is attractive while the centrifugal force is repulsive. This can be seen in Figure 6-2. It is also possible to guess some characteristics of po ...
... It is to be noted that the centrifugal potential “reduces” the effect of the inverse-squarelaw on the particle. This is because the inverse-square-law force is attractive while the centrifugal force is repulsive. This can be seen in Figure 6-2. It is also possible to guess some characteristics of po ...
NEWTON`S FIRST LAW CONCEPTUAL WORKSHEET
... A metal ball is put into the end of the tube indicated by the arrow. The ball is then shot out of the other end of the tube at high speed. Pick the path the ball will follow after it exits the tube. Note – you are looking down on these tubes, they are not vertical. ...
... A metal ball is put into the end of the tube indicated by the arrow. The ball is then shot out of the other end of the tube at high speed. Pick the path the ball will follow after it exits the tube. Note – you are looking down on these tubes, they are not vertical. ...
A space-time geometric interpretation of the beta factor in Special
... possible implications. First, it provides some heuristic comfort in the idea that mass has an enormous "hidden" (i.e. atomic) energy in the form of E = mc^2. Another possible significance is that an object in motion seems to rotate its velocity vector in space-time, maintaining a constant magnitude ...
... possible implications. First, it provides some heuristic comfort in the idea that mass has an enormous "hidden" (i.e. atomic) energy in the form of E = mc^2. Another possible significance is that an object in motion seems to rotate its velocity vector in space-time, maintaining a constant magnitude ...
Skill Sheet 7.1A Adding Displacement Vectors
... vertical motion of an object. When we drop a ball from a height, we know that its speed increases as it falls. The increase in vertical speed is due to the acceleration gravity, g = 9.8 m/sec2. So the vertical speed of the ball will increase by 9.8 m/sec after each second. After the first second has ...
... vertical motion of an object. When we drop a ball from a height, we know that its speed increases as it falls. The increase in vertical speed is due to the acceleration gravity, g = 9.8 m/sec2. So the vertical speed of the ball will increase by 9.8 m/sec after each second. After the first second has ...
NEWTON`S THREE LAWS OF MOTION
... force of gravity • Magnitude of the force depends on 1. the mass of the object 2. the distance between objects *increased mass = increased effect of the force of gravity on the object (takes more effort to pull down a larger object) *distance increases between objects = decrease in the effect of the ...
... force of gravity • Magnitude of the force depends on 1. the mass of the object 2. the distance between objects *increased mass = increased effect of the force of gravity on the object (takes more effort to pull down a larger object) *distance increases between objects = decrease in the effect of the ...
Numerical Integration of Newton`s Second Law of Motion
... to 0.9 sec). And we can check these results because we know how to calculate all these quantities for simple projectile motion: R = (v02/g) sin 2Θ = 8.837 m, yMAX = (v0 sin Θ)2/2g = 1.276 m, time for yMAX is t=(v0 sin Θ)/g = 0.510 sec and time for R is t=(2v0 sin Θ)/g = 1.020 sec. Notice that all th ...
... to 0.9 sec). And we can check these results because we know how to calculate all these quantities for simple projectile motion: R = (v02/g) sin 2Θ = 8.837 m, yMAX = (v0 sin Θ)2/2g = 1.276 m, time for yMAX is t=(v0 sin Θ)/g = 0.510 sec and time for R is t=(2v0 sin Θ)/g = 1.020 sec. Notice that all th ...
