Notes for Topic 6
... As u and v vary over their domains, the points (x, y, z) cover the surface. The Mathematica command for plotting a parametric surface is ParametricPlot3D. To make a graph of the surface, execute the command ParametricPlot3D[{f[u,v],g[u,v],h[u,v]}, {u,u1,u2},{v,v1,v2}] In this command, (u1 , u2 ) is ...
... As u and v vary over their domains, the points (x, y, z) cover the surface. The Mathematica command for plotting a parametric surface is ParametricPlot3D. To make a graph of the surface, execute the command ParametricPlot3D[{f[u,v],g[u,v],h[u,v]}, {u,u1,u2},{v,v1,v2}] In this command, (u1 , u2 ) is ...
determination of the acceleration of an elevator.
... DETERMINATION OF THE ACCELERATION OF AN ELEVATOR. INTRODUCTION: In order for an object to accelerate, there must be a net force acting on it. We know that the direction of the acceleration will be in the same direction as the direction of the net force. The equation for Newton’s 2nd law is F = ma o ...
... DETERMINATION OF THE ACCELERATION OF AN ELEVATOR. INTRODUCTION: In order for an object to accelerate, there must be a net force acting on it. We know that the direction of the acceleration will be in the same direction as the direction of the net force. The equation for Newton’s 2nd law is F = ma o ...
Lecture Mechanics Newton ppt
... Property 1: Any vector in an N-dimensional space can be decomposed into N-orthogonal components (N=3 in our physical space). There are infinite number of ways to assign these N-components. A unique way of writing down its N-components is specified once we specify a coordinate system. ...
... Property 1: Any vector in an N-dimensional space can be decomposed into N-orthogonal components (N=3 in our physical space). There are infinite number of ways to assign these N-components. A unique way of writing down its N-components is specified once we specify a coordinate system. ...
Chapter 7:Rotation of a Rigid Body
... The unit of torque is N m (newton metre), a vector product unlike the joule (unit of work), also equal to a newton metre, which is scalar product. Torque is occurred because of turning (twisting) effects of the forces on a body. Sign convention of torque: Positive - turning tendency of the force i ...
... The unit of torque is N m (newton metre), a vector product unlike the joule (unit of work), also equal to a newton metre, which is scalar product. Torque is occurred because of turning (twisting) effects of the forces on a body. Sign convention of torque: Positive - turning tendency of the force i ...
Physics Words
... 4. Repeat the process by pulling the cart with a constant force of 2 N by placing another 100 gram mass on the hanger for a total of 200 grams on the hanger. a) Sketch the shape of the water in the liquid accelerometer to the right. b) How is it different from what you observed in "a" when the force ...
... 4. Repeat the process by pulling the cart with a constant force of 2 N by placing another 100 gram mass on the hanger for a total of 200 grams on the hanger. a) Sketch the shape of the water in the liquid accelerometer to the right. b) How is it different from what you observed in "a" when the force ...
Newton`s Laws II - Rutgers Physics
... Uncertainly lab write-up you did early in the semester. B) Measure the coefficients of static and kinetic friction of a block using a force sensor. 1. Detach the force sensor from the cart by loosening the single black thumbscrew that attaches the two; put the cart aside (see photo below). Place the ...
... Uncertainly lab write-up you did early in the semester. B) Measure the coefficients of static and kinetic friction of a block using a force sensor. 1. Detach the force sensor from the cart by loosening the single black thumbscrew that attaches the two; put the cart aside (see photo below). Place the ...
Uniform circular motion
... three-quarters circle. A golf ball is pushed into the tube at one end at high speed. The ball rolls through the tube and exits at the opposite end. Describe the path of the golf ball as it exits the tube. The ball will move along a path which is tangent to the spiral at the point where it exits the ...
... three-quarters circle. A golf ball is pushed into the tube at one end at high speed. The ball rolls through the tube and exits at the opposite end. Describe the path of the golf ball as it exits the tube. The ball will move along a path which is tangent to the spiral at the point where it exits the ...
Motion Characteristics for Circular Motion
... moving in a circle has an outward force acting on it, a socalled centrifugal (center-fleeing) force. Consider for example a person swinging a ball on the end of a string. If you have ever done this yourself, you know that you feel a force pulling outward on your hand. This misconception arises when ...
... moving in a circle has an outward force acting on it, a socalled centrifugal (center-fleeing) force. Consider for example a person swinging a ball on the end of a string. If you have ever done this yourself, you know that you feel a force pulling outward on your hand. This misconception arises when ...
PHYS 1443 – Section 501 Lecture #1
... Dr. Jaehoon Yu •Newton’s Laws of Motion –Free-body Diagrams –Applications of Newton’s Laws ...
... Dr. Jaehoon Yu •Newton’s Laws of Motion –Free-body Diagrams –Applications of Newton’s Laws ...
Introduction to Classical Mechanics 1 HISTORY
... After the publication of Principia, Newton was the most renowned scientist in the world. His achievement was fully recognized during his lifetime. Today scientists and engineers still use Newton’s theory of mechanics. In the 20th century some limitations of Newtonian mechanics were discovered: Class ...
... After the publication of Principia, Newton was the most renowned scientist in the world. His achievement was fully recognized during his lifetime. Today scientists and engineers still use Newton’s theory of mechanics. In the 20th century some limitations of Newtonian mechanics were discovered: Class ...
Monday, April 1, 2013
... 1. Define your system by deciding which objects would be included in it. 2. Identify the internal and external forces with respect to the system. 3. Verify that the system is isolated. 4. Set the final momentum of the system equal to its initial momentum. Remember that momentum is a vector. Monday, ...
... 1. Define your system by deciding which objects would be included in it. 2. Identify the internal and external forces with respect to the system. 3. Verify that the system is isolated. 4. Set the final momentum of the system equal to its initial momentum. Remember that momentum is a vector. Monday, ...
Slide 1
... string Y and then hung from a beam using string X. String X is burned through using a candle. Neglecting the mass of each string, what is the tension in string Y I Before string X is burned through & II After string X is burned through? ...
... string Y and then hung from a beam using string X. String X is burned through using a candle. Neglecting the mass of each string, what is the tension in string Y I Before string X is burned through & II After string X is burned through? ...
Document
... acceleration. 42. A sprinter runs at a speed of 3.00 m/s on a circular track that has a radius of 40.00 m. Find the centripetal acceleration of the sprinter. 43. A car moving at 12.67 m/s rounds a bend in the road. The bend is semicircular and has a radius of 60.0 m. What is the centripetal accelera ...
... acceleration. 42. A sprinter runs at a speed of 3.00 m/s on a circular track that has a radius of 40.00 m. Find the centripetal acceleration of the sprinter. 43. A car moving at 12.67 m/s rounds a bend in the road. The bend is semicircular and has a radius of 60.0 m. What is the centripetal accelera ...
Coefficient of Friction Worksheet
... 2. A block weighing 300 N is moved at a constant speed over a horizontal surface by a force of 50 N applied parallel to the surface. What does the “constant speed” tell you about the forces acting on the block? a. Draw a free body diagram for the block. b. What is the coefficient of kinetic friction ...
... 2. A block weighing 300 N is moved at a constant speed over a horizontal surface by a force of 50 N applied parallel to the surface. What does the “constant speed” tell you about the forces acting on the block? a. Draw a free body diagram for the block. b. What is the coefficient of kinetic friction ...
V - USU Physics
... • Velocity is a vector and represents a bodies speed and direction. • A force must act on a body to change its velocity (i.e. its speed, direction or both). • The force causes the body to accelerate resulting in a change in its velocity. • Acceleration is a vector and represents the rate of change o ...
... • Velocity is a vector and represents a bodies speed and direction. • A force must act on a body to change its velocity (i.e. its speed, direction or both). • The force causes the body to accelerate resulting in a change in its velocity. • Acceleration is a vector and represents the rate of change o ...
