Unit 2 - aqaphysics.co.uk
... An object that falls freely will accelerate towards the Earth because of the force of gravity acting on it. The size of this acceleration does not depend mass, so a feather and a bowling ball accelerate at the same rate. On the Moon they hit the ground at the same time, on Earth the resistance of th ...
... An object that falls freely will accelerate towards the Earth because of the force of gravity acting on it. The size of this acceleration does not depend mass, so a feather and a bowling ball accelerate at the same rate. On the Moon they hit the ground at the same time, on Earth the resistance of th ...
Rotation
... Translation: body’s movement described by x(t). Rotation: body’s movement given by θ(t) = angular position of the body’s reference line as function of time. Angular displacement: body’s rotation about its axis changing the angular position from θ1 to θ2. ...
... Translation: body’s movement described by x(t). Rotation: body’s movement given by θ(t) = angular position of the body’s reference line as function of time. Angular displacement: body’s rotation about its axis changing the angular position from θ1 to θ2. ...
Fundamentals
of
Physics
in
Engineering
I
Unit 3.- WORK AND ENERGY
... between the force F and the horizontal direction is 30º and the coefficient of friction between the block and the horizontal surface is µ = 0.3. What is the work done by the force F? 2.-A 3 kg object is dropped from a certain height with an initial velocity of v0 = 2 m/s, directed vertically downwar ...
... between the force F and the horizontal direction is 30º and the coefficient of friction between the block and the horizontal surface is µ = 0.3. What is the work done by the force F? 2.-A 3 kg object is dropped from a certain height with an initial velocity of v0 = 2 m/s, directed vertically downwar ...
Ball 1 of mass m moving right with speed v bounces off ball 2 with
... all of its lost KE was translational KE. While for the hoop, only half of its lost KE was lost translational KE (the other half was lost rotational KE). Both start out with the same KEtrans, but the hoop loses less KEtrans in going up the hill, so it finishes with more KEtrans than the puck. Greater ...
... all of its lost KE was translational KE. While for the hoop, only half of its lost KE was lost translational KE (the other half was lost rotational KE). Both start out with the same KEtrans, but the hoop loses less KEtrans in going up the hill, so it finishes with more KEtrans than the puck. Greater ...
Momentum
... The impulse given to the car: - 10,000 N*s The car’s change in momentum: - 10,000 kg*m/s The car’s final momentum: 10,155 kg*m/s The car’s final velocity: 14 m/s ...
... The impulse given to the car: - 10,000 N*s The car’s change in momentum: - 10,000 kg*m/s The car’s final momentum: 10,155 kg*m/s The car’s final velocity: 14 m/s ...
PY1052 Problem Set 8 – Autumn 2004 Solutions
... In other words, about 99.4% of the initial kinetic energy is lost. (c) The rod will momentarily stop when it gets to a point where all its initial kinetic energy has been transformed into gravitational potential energy. We can choose any height for h = 0, so let’s choose the initial horizontal heigh ...
... In other words, about 99.4% of the initial kinetic energy is lost. (c) The rod will momentarily stop when it gets to a point where all its initial kinetic energy has been transformed into gravitational potential energy. We can choose any height for h = 0, so let’s choose the initial horizontal heigh ...
Chapter 27
... it moves in a magnetic field What is the net effect if we have multiple charges moving together, as a current in a wire? We start with a wire of length l and cross section area A in a magnetic field of strength B with the charges having a drift velocity of vd The total number of charges in this sect ...
... it moves in a magnetic field What is the net effect if we have multiple charges moving together, as a current in a wire? We start with a wire of length l and cross section area A in a magnetic field of strength B with the charges having a drift velocity of vd The total number of charges in this sect ...
Document
... An easy way to measure the moment of inertia of an object about any axis is to measure the period of oscillation about that axis. (a) Suppose a nonuniform 1.0-kg stick can be balanced at a point 42 cm from one end. If it is pivoted about that end, it oscillates with a period of 1.6 s. What is its mo ...
... An easy way to measure the moment of inertia of an object about any axis is to measure the period of oscillation about that axis. (a) Suppose a nonuniform 1.0-kg stick can be balanced at a point 42 cm from one end. If it is pivoted about that end, it oscillates with a period of 1.6 s. What is its mo ...
