Lecture 16 - Circular Motion
... normal force and gravity act in the same direction. The minimum speed for weightlessness corresponds to normal force = 0. In that case the only centripetal force is mg. This gives us a condition for v which is independent of m. So for a given r, all objects will become weightless at that v just at t ...
... normal force and gravity act in the same direction. The minimum speed for weightlessness corresponds to normal force = 0. In that case the only centripetal force is mg. This gives us a condition for v which is independent of m. So for a given r, all objects will become weightless at that v just at t ...
Lecture powerpoint
... W > 0: The environment does work on the system and the system’s energy increases. W < 0: The system does work on the environment and the system’s energy decreases. ...
... W > 0: The environment does work on the system and the system’s energy increases. W < 0: The system does work on the environment and the system’s energy decreases. ...
10-1 Note 10 Rotational Motion I
... angular displacement of P measured relative to the positive x-axis. Because the object is rigid, the angular displacement of every particle in the object is the same as the angular displacement of P. Angular displacement is measured in the dimensionless unit called radian (abbreviated rad) and in th ...
... angular displacement of P measured relative to the positive x-axis. Because the object is rigid, the angular displacement of every particle in the object is the same as the angular displacement of P. Angular displacement is measured in the dimensionless unit called radian (abbreviated rad) and in th ...
Work and Kinetic Energy
... Q19) A block is attached to the end of an ideal spring and moved from coordinate xi to coordinate xf . The relaxed position is at x = 0. The work done by spring is positive if: 1) xi = 2cm and xf = 4cm 2) xi = -2 cm and xf = 4cm 3) xi = -2 cm and xf = -4 cm 4) xi = 2 cm and xf = -4 cm 5) xi = -4 cm ...
... Q19) A block is attached to the end of an ideal spring and moved from coordinate xi to coordinate xf . The relaxed position is at x = 0. The work done by spring is positive if: 1) xi = 2cm and xf = 4cm 2) xi = -2 cm and xf = 4cm 3) xi = -2 cm and xf = -4 cm 4) xi = 2 cm and xf = -4 cm 5) xi = -4 cm ...
Circular Motion RS
... 2. What is the direction of the centripetal acceleration of an object in uniform circular motion? Why? 3. A ball is whirled around in a circle. What happens to the centripetal acceleration if the velocity is doubled? 4. If a string breaks that holds a whirling can in it circular path, what causes it ...
... 2. What is the direction of the centripetal acceleration of an object in uniform circular motion? Why? 3. A ball is whirled around in a circle. What happens to the centripetal acceleration if the velocity is doubled? 4. If a string breaks that holds a whirling can in it circular path, what causes it ...
Here - Solipsys Limited
... That means that the formula for its motion (in simple form) can be written as We can substitute that into our earlier formula and we get where a is the amplitude of the swing, and ...
... That means that the formula for its motion (in simple form) can be written as We can substitute that into our earlier formula and we get where a is the amplitude of the swing, and ...
Newton and Friction
... 2) Net Force = (mass)(acceleration) Forces are in Newtons (N), Mass in kg Weight (force) = (mass)(acceleration due to gravity) {you weigh between 500 N to 600 N} {1 stick of butter = 1 Newton} 3) For every action (force) there is an equal and opposite reaction (force). If a bat hits a ball with a fo ...
... 2) Net Force = (mass)(acceleration) Forces are in Newtons (N), Mass in kg Weight (force) = (mass)(acceleration due to gravity) {you weigh between 500 N to 600 N} {1 stick of butter = 1 Newton} 3) For every action (force) there is an equal and opposite reaction (force). If a bat hits a ball with a fo ...
Kreutter: Linear Dynamics 7 Newton`s Second Law: Quantitative I
... object of interest — the system. The acceleration a of the system is directly proportional to the unbalanced force exerted on the system by other objects and inversely proportional to the mass m of the system object: ...
... object of interest — the system. The acceleration a of the system is directly proportional to the unbalanced force exerted on the system by other objects and inversely proportional to the mass m of the system object: ...
Physics Test MC. Thru 10 Two wires have the same diameter and
... An object is in nonuniform circular motion with constant angular acceleration. Identify the correct statement. a. 1 only b. 2 only c. 3 only d. 1, 2, and 3 a. 2 and 3 f. 1 and 2 g. 1 and 3 h. none of them ...
... An object is in nonuniform circular motion with constant angular acceleration. Identify the correct statement. a. 1 only b. 2 only c. 3 only d. 1, 2, and 3 a. 2 and 3 f. 1 and 2 g. 1 and 3 h. none of them ...
Slide 1
... An object at rest must have no net force on it. If it is sitting on a table, the force of gravity is still there; what other force is there? The force exerted perpendicular to a surface is called the normal force. It is ...
... An object at rest must have no net force on it. If it is sitting on a table, the force of gravity is still there; what other force is there? The force exerted perpendicular to a surface is called the normal force. It is ...
Chapter AA
... where it is clear that we use the latest value of v (computed in the first line) to update the position x (computed in the second line). So these computations start from a given acceleration, update the speed then update the position of the object. There’s one small issue. Where does the acceleratio ...
... where it is clear that we use the latest value of v (computed in the first line) to update the position x (computed in the second line). So these computations start from a given acceleration, update the speed then update the position of the object. There’s one small issue. Where does the acceleratio ...
Rotational Kinematics
... When discussing kinematics, what are some common vector quantities we discuss? • Displacement Angular displacement • Velocity Angular velocity • Acceleration Angular acceleration • Force Torque • Momentum Angular momentum ALL of these vectors can be described in terms of rotational motion! ...
... When discussing kinematics, what are some common vector quantities we discuss? • Displacement Angular displacement • Velocity Angular velocity • Acceleration Angular acceleration • Force Torque • Momentum Angular momentum ALL of these vectors can be described in terms of rotational motion! ...
SAMPLE TEST 1: PHYSICS 103
... d = d0 + vo . t + ½ a.t2 where d is the final position after time t, d0 is the initial position, t is the time, a is the acceleration, and vo is the initial velocity For anything moving at constant acceleration, the final velocity (v ) can be found using: v= vo + a. t From Newton’s second law: F=m.a ...
... d = d0 + vo . t + ½ a.t2 where d is the final position after time t, d0 is the initial position, t is the time, a is the acceleration, and vo is the initial velocity For anything moving at constant acceleration, the final velocity (v ) can be found using: v= vo + a. t From Newton’s second law: F=m.a ...