Chapter 3
... • A formula weight is the sum of the atomic weights for the atoms in a chemical formula. • So, the formula weight of calcium chloride, CaCl2, would be Ca: 1(40.08 amu) + Cl: 2(35.453 amu) 110.99 amu • Formula weights are generally reported for ionic compounds. ...
... • A formula weight is the sum of the atomic weights for the atoms in a chemical formula. • So, the formula weight of calcium chloride, CaCl2, would be Ca: 1(40.08 amu) + Cl: 2(35.453 amu) 110.99 amu • Formula weights are generally reported for ionic compounds. ...
Final Exam - Seattle Central College
... lecture notes! Naming ionic compounds: - cation name + anion name - IA, IIA, Al, Ag, Zn, Cd don't need Roman #s - All other metals need Roman #s Nomenclature for Ionic Compounds: - Given the formula of a compound, determine its name, or vice versa. ...
... lecture notes! Naming ionic compounds: - cation name + anion name - IA, IIA, Al, Ag, Zn, Cd don't need Roman #s - All other metals need Roman #s Nomenclature for Ionic Compounds: - Given the formula of a compound, determine its name, or vice versa. ...
09/11/03 lecture
... much does an atom weigh? What units do we describe the mass of an atom in? • The atomic mass unit (amu): defined explicitly in terms of the 12C atom--the mass of 1 12C atom = 12 amu. • All other atomic masses are defined relative to the 12C atom. ...
... much does an atom weigh? What units do we describe the mass of an atom in? • The atomic mass unit (amu): defined explicitly in terms of the 12C atom--the mass of 1 12C atom = 12 amu. • All other atomic masses are defined relative to the 12C atom. ...
Topic 9 – Percent Composition, Empirical and Molecular Formulas I
... B. Ores containing a higher percent by mass of the metal are typically more profitable to process. C. Percent by mass can also be used to identify compounds with the help of a mass spectrometer. The mass spectrometer can identify the percent of each element present in a compound. D. Calculating perc ...
... B. Ores containing a higher percent by mass of the metal are typically more profitable to process. C. Percent by mass can also be used to identify compounds with the help of a mass spectrometer. The mass spectrometer can identify the percent of each element present in a compound. D. Calculating perc ...
formula
... Find O on the periodic table. It’s mass is ______ amu. It has ___ protons. It must have ___ neutrons. Electrically neutral atoms (as opposed to ions) have one electron for every proton. Fill in this chart for these neutral atoms: Atom Mass protons neutrons electrons He Si Be ...
... Find O on the periodic table. It’s mass is ______ amu. It has ___ protons. It must have ___ neutrons. Electrically neutral atoms (as opposed to ions) have one electron for every proton. Fill in this chart for these neutral atoms: Atom Mass protons neutrons electrons He Si Be ...
AQA Additional Sci C2 Revision Guide
... because they only have one electron in their outer shells to lose. Group 2 metals have two electrons in their outer shells which they lose to form ions with a double positive charge. The elements in Group 7 of the periodic table (the halogens) all react with the alkali metals to form ionic compounds ...
... because they only have one electron in their outer shells to lose. Group 2 metals have two electrons in their outer shells which they lose to form ions with a double positive charge. The elements in Group 7 of the periodic table (the halogens) all react with the alkali metals to form ionic compounds ...
Unit Two Objectives
... 2. Heat is the total energy of all of the particles in the sample; it is the form of energy that flows between two bodies when the bodies are at different temperatures; heat will flow from the hotter body to the cooler body. a. Endothermic Change: occurs when matter ABSORBS energy (in=endo) b. Exoth ...
... 2. Heat is the total energy of all of the particles in the sample; it is the form of energy that flows between two bodies when the bodies are at different temperatures; heat will flow from the hotter body to the cooler body. a. Endothermic Change: occurs when matter ABSORBS energy (in=endo) b. Exoth ...
Determining Chemical Formulas
... III.A.1(e) - Calculate the percent composition of a substance, given its formula or masses of each component element in a sample III.A.1(f) - Determine the empirical formulas and molecular formulas of compounds, given percent composition data or mass composition ...
... III.A.1(e) - Calculate the percent composition of a substance, given its formula or masses of each component element in a sample III.A.1(f) - Determine the empirical formulas and molecular formulas of compounds, given percent composition data or mass composition ...
Topic 4 Chemistry of the Elements of the Main Group
... The main group elements are classified according to their conduction properties into three groups: Metals, Metalloids and non-Metals Non-metals are not electrical conductors, they are characterised by a high electronegativity value (over 2). The valence electrons of non-metals are strongly attract ...
... The main group elements are classified according to their conduction properties into three groups: Metals, Metalloids and non-Metals Non-metals are not electrical conductors, they are characterised by a high electronegativity value (over 2). The valence electrons of non-metals are strongly attract ...
600 $600
... Fe2O3 + 3CO → 2Fe + 3CO2 In this reaction, how many grams of Fe2O3 are required to completely react with 84 grams of CO? A 64 g B 80 g C 160 g D 1400 ...
... Fe2O3 + 3CO → 2Fe + 3CO2 In this reaction, how many grams of Fe2O3 are required to completely react with 84 grams of CO? A 64 g B 80 g C 160 g D 1400 ...
Chapter 30 - The Chemical Basis of Animal Life
... Latin, natrium). Currently, scientists recognize 92 elements occurring in nature. Fifteen elements are found in large quantities in most animals, and four of these (carbon, hydrogen, oxygen, and nitrogen) account for the majority (97%) of an animal’s body weight (table 30.1). The remaining 3% of an ...
... Latin, natrium). Currently, scientists recognize 92 elements occurring in nature. Fifteen elements are found in large quantities in most animals, and four of these (carbon, hydrogen, oxygen, and nitrogen) account for the majority (97%) of an animal’s body weight (table 30.1). The remaining 3% of an ...
Chapter 3 Molecules, Compounds, and Chemical Equations How
... • These prefixes are the same as those used in naming hydrates: mono = 1 di = 2 tri = 3 tetra = 4 penta = 5 ...
... • These prefixes are the same as those used in naming hydrates: mono = 1 di = 2 tri = 3 tetra = 4 penta = 5 ...
I. Properties of Matter
... hydrogen, and 10.26 g of oxygen, what is the percent by mass of each of the elements in the compound? ...
... hydrogen, and 10.26 g of oxygen, what is the percent by mass of each of the elements in the compound? ...
Chemical reactions and equations
... 1) Write the formulas of the reactants using element symbols to the left of the yield sign (arrow) 2) Draw the arrow 3) Write the formulas of the products to the right. ...
... 1) Write the formulas of the reactants using element symbols to the left of the yield sign (arrow) 2) Draw the arrow 3) Write the formulas of the products to the right. ...
with answers
... (d) Explain why compounds of the formulae Na2O and NH3 form from their respective constituent elements. Give reasons for your answer. (4P) Na attains inert gas configuration by losing its one valence (forming Na+). N reaches inert gas configuration by gaining three electrons (through formation of th ...
... (d) Explain why compounds of the formulae Na2O and NH3 form from their respective constituent elements. Give reasons for your answer. (4P) Na attains inert gas configuration by losing its one valence (forming Na+). N reaches inert gas configuration by gaining three electrons (through formation of th ...
PowerPoint - Types of Chemical Reactions
... CaCl2(aq) + Na3PO4(aq) Pb(NO3)2(aq) + BaCl2(aq) FeCl3(aq) + NaOH(aq) H2SO4(aq) + NaOH(aq) ...
... CaCl2(aq) + Na3PO4(aq) Pb(NO3)2(aq) + BaCl2(aq) FeCl3(aq) + NaOH(aq) H2SO4(aq) + NaOH(aq) ...
Ch 3 Student.pptx
... 1. The cation is always named first and the anion second. 2. Cation takes its name from the name of the parent element. 3. Anion is named by taking the root of the element name and adding –ide. ...
... 1. The cation is always named first and the anion second. 2. Cation takes its name from the name of the parent element. 3. Anion is named by taking the root of the element name and adding –ide. ...
Dear Chemistry Student, I am excited that you have chosen to
... -Begin memorizing the 85 Polyatomic Ions list. You will need to know both name and ion formulas. These are the easiest exam points you will earn all year so be sure to make it happen! =) - Check out Mrs. Martin’s video page on You Tube. There are some review videos that may help you with various par ...
... -Begin memorizing the 85 Polyatomic Ions list. You will need to know both name and ion formulas. These are the easiest exam points you will earn all year so be sure to make it happen! =) - Check out Mrs. Martin’s video page on You Tube. There are some review videos that may help you with various par ...
Unit 2 Review Game
... • During a chemical reaction, a group combines 5.00 grams of sodium and 7.72 grams of chlorine. The result of the reaction was 12.72 grams of sodium chloride. Which law does this support? ...
... • During a chemical reaction, a group combines 5.00 grams of sodium and 7.72 grams of chlorine. The result of the reaction was 12.72 grams of sodium chloride. Which law does this support? ...
6.1 Moles and Molar Masses
... the posted key. Otherwise, we will do them in class. SC.1) A pure copper penny (before 1982) has a mass of 3.1 g. Calculate the number of copper atoms used to make a single pure copper penny. ...
... the posted key. Otherwise, we will do them in class. SC.1) A pure copper penny (before 1982) has a mass of 3.1 g. Calculate the number of copper atoms used to make a single pure copper penny. ...
Determination of the Atomic Weight of Magnesium CHEM 101
... the balance. Other potential sources of experimental uncertainty are: the reaction might not be complete; if not enough time was allowed for total oxidation, less than complete oxidation of the magnesium might have, in part, reacted with nitrogen in the air (incorrect reaction); the magnesium oxide ...
... the balance. Other potential sources of experimental uncertainty are: the reaction might not be complete; if not enough time was allowed for total oxidation, less than complete oxidation of the magnesium might have, in part, reacted with nitrogen in the air (incorrect reaction); the magnesium oxide ...
PowerPoint Presentation - Chapter 2
... • The periodic table of the elements shows the electron distribution for each element ...
... • The periodic table of the elements shows the electron distribution for each element ...
Chemistry 11 – Course Review
... Calculate the average atomic mass of element “X” to 3 decimal places. ...
... Calculate the average atomic mass of element “X” to 3 decimal places. ...
Chemistry B11 Chapter 4 Chemical reactions
... Avogadro’s number (6.022× ×1023): number of formula units in a mole. 1 mole of hydrogen atoms = 6.022×1023 atoms of hydrogen 1 mole of water molecules = 6.022×1023 molecules of water 1 mole of Na+ ions = 6.022×1023 ions of Na+ Molar mass: is the mass of one mole of the substance expressed in grams. ...
... Avogadro’s number (6.022× ×1023): number of formula units in a mole. 1 mole of hydrogen atoms = 6.022×1023 atoms of hydrogen 1 mole of water molecules = 6.022×1023 molecules of water 1 mole of Na+ ions = 6.022×1023 ions of Na+ Molar mass: is the mass of one mole of the substance expressed in grams. ...