model paper-1 - WordPress.com
... the first Bohr orbit to the fifth Bohr orbit, and what is the wavelength of the light emitted when the electron returns to the \ground state? The ground state electron energy is -2.18x10-11 ergs. c) Assign the values of n, l and m for a (i) 2s orbital (ii) 4d orbital 5M 25. At 473 K, equilibrium con ...
... the first Bohr orbit to the fifth Bohr orbit, and what is the wavelength of the light emitted when the electron returns to the \ground state? The ground state electron energy is -2.18x10-11 ergs. c) Assign the values of n, l and m for a (i) 2s orbital (ii) 4d orbital 5M 25. At 473 K, equilibrium con ...
5H2O → CuSO4 + 5H2O(g)
... Most reactions in general chemistry take place in an aqueous environment. What does that mean? Terms: ◦ Solution: homogeneous mixture of two or more substances ◦ Solute: substance present in smaller amount ◦ Solvent: substance present in greater amount ◦ Aqueous solution: solvent is water ...
... Most reactions in general chemistry take place in an aqueous environment. What does that mean? Terms: ◦ Solution: homogeneous mixture of two or more substances ◦ Solute: substance present in smaller amount ◦ Solvent: substance present in greater amount ◦ Aqueous solution: solvent is water ...
practice problems of chap4_5 - Chemistry
... (b) H2 + O2 H2O2 (c) CaCO3 CaO + CO2 (d) 2HNO3 + Mg Mg(NO3) 2+ H2 (e) Cl2+NaBrNaCl+Br2 Hint: Redox reaction involves electron transfer, which leads to change of oxidation n umber of the elements. You need first to figure out the oxidation number of each species. The reac tion that does not h ...
... (b) H2 + O2 H2O2 (c) CaCO3 CaO + CO2 (d) 2HNO3 + Mg Mg(NO3) 2+ H2 (e) Cl2+NaBrNaCl+Br2 Hint: Redox reaction involves electron transfer, which leads to change of oxidation n umber of the elements. You need first to figure out the oxidation number of each species. The reac tion that does not h ...
Starter S-30
... -reactants can be impure -reactions may not go to completion -may compete with smaller “side” reactions In some reactions as little as 60% yield is considered a good result ...
... -reactants can be impure -reactions may not go to completion -may compete with smaller “side” reactions In some reactions as little as 60% yield is considered a good result ...
Exercise #5_Chpt 2
... Sodium hydrogen carbonate, NaHCO3, combines with HCl as indicated below. NaHCO3(aq) + HCl(aq) NaCl(aq) + CO2(g) + H2O(l) a) What volume of 1.5M HCl solution should be present to combine totally with 0.14 moles of NaHCO 3? b) How many moles of CO2 are produced when 0.49 g of NaHCO3 combines with ex ...
... Sodium hydrogen carbonate, NaHCO3, combines with HCl as indicated below. NaHCO3(aq) + HCl(aq) NaCl(aq) + CO2(g) + H2O(l) a) What volume of 1.5M HCl solution should be present to combine totally with 0.14 moles of NaHCO 3? b) How many moles of CO2 are produced when 0.49 g of NaHCO3 combines with ex ...
Introduction
... when they are placed in water, specifically ionic versus covalent compounds. One breaks apart in water, the other does not. Which one is more likely to be pulled apart by water molecules? Electrolytes are ionic and strong acid solutions (e.g., GatoradeTM); Nonelectrolytes ...
... when they are placed in water, specifically ionic versus covalent compounds. One breaks apart in water, the other does not. Which one is more likely to be pulled apart by water molecules? Electrolytes are ionic and strong acid solutions (e.g., GatoradeTM); Nonelectrolytes ...
Final Exam SG Part 1 (Unit 5).
... b. What is the ratio of black and white molecules to produce the products? c. How many moles are produced from the moles of the reactants? d. If you double the amount of white molecules (so now you have 8 pairs) but keep the same amount of black molecules, how many molecules can you produce? 4. Perc ...
... b. What is the ratio of black and white molecules to produce the products? c. How many moles are produced from the moles of the reactants? d. If you double the amount of white molecules (so now you have 8 pairs) but keep the same amount of black molecules, how many molecules can you produce? 4. Perc ...
File
... Problem #1: Balance the following equation: H2 + O2 ---> H2O It is an unbalanced equation. This means that there are UNEQUAL numbers of at least one atom on each side of the arrow. In the example equation, there are two atoms of hydrogen on each side, BUT there are two atoms of oxygen on the left si ...
... Problem #1: Balance the following equation: H2 + O2 ---> H2O It is an unbalanced equation. This means that there are UNEQUAL numbers of at least one atom on each side of the arrow. In the example equation, there are two atoms of hydrogen on each side, BUT there are two atoms of oxygen on the left si ...
Slide 1
... If EӨ for I2 + 2e 2I- +0.54 V, then ½ I2 + e I- not (1/2 x 0.54V) but is +0.54V. The reactivity of metals increases as the electrode potential become more negative while the reactivity if non metal increases as the electrode potential become more positive. The strength of oxidizing agents increa ...
... If EӨ for I2 + 2e 2I- +0.54 V, then ½ I2 + e I- not (1/2 x 0.54V) but is +0.54V. The reactivity of metals increases as the electrode potential become more negative while the reactivity if non metal increases as the electrode potential become more positive. The strength of oxidizing agents increa ...
Stoichiometry Notes
... an unknown solution. To carry out this analytical method, the chemist would measure accurately the volume of a solution of unknown concentration and react with a solution of known concentration. The volume of the known solution is determined by finding what is called the EQUIVALENCE POINT (stoichiom ...
... an unknown solution. To carry out this analytical method, the chemist would measure accurately the volume of a solution of unknown concentration and react with a solution of known concentration. The volume of the known solution is determined by finding what is called the EQUIVALENCE POINT (stoichiom ...
Types of Chemical Reactions
... He correctly postulated that the extent to which a solution can conduct an electric current depends directly on the number of ions present. ...
... He correctly postulated that the extent to which a solution can conduct an electric current depends directly on the number of ions present. ...
Chapter 18 Electrochemistry
... of a Cd electrode in a 1.0 M Cd(NO3)2 solution and a Cr electrode in a 1.0 M Cr(NO3)3 solution? Cd2+ (aq) + 2e- ...
... of a Cd electrode in a 1.0 M Cd(NO3)2 solution and a Cr electrode in a 1.0 M Cr(NO3)3 solution? Cd2+ (aq) + 2e- ...
chemistry 110 lecture
... PROBLEMS: 1. Calcium hydroxide is reacted with nitric acid. a. How many moles of calcium nitrate is produced when 3 moles of calcium hydroxide and 4 moles of nitric acid are mixed? METHOD: Find the L.R. J Calculate the moles of product that can be produced from each reactant ...
... PROBLEMS: 1. Calcium hydroxide is reacted with nitric acid. a. How many moles of calcium nitrate is produced when 3 moles of calcium hydroxide and 4 moles of nitric acid are mixed? METHOD: Find the L.R. J Calculate the moles of product that can be produced from each reactant ...
Unit 3
... Acids + Bases • A strong acid and a strong base produce a salt which is neutral. • A strong acid and a weak base produce a salt which is acidic. • A weak acid and a strong base produce a salt which is basic. ...
... Acids + Bases • A strong acid and a strong base produce a salt which is neutral. • A strong acid and a weak base produce a salt which is acidic. • A weak acid and a strong base produce a salt which is basic. ...
Document
... if graph ln[A] vs time is straight line, then exponent on A in rate law is 1, rate constant = -slope if graph 1/[A] vs time is straight line, exponent on A in rate law is 2, rate constant = slope ...
... if graph ln[A] vs time is straight line, then exponent on A in rate law is 1, rate constant = -slope if graph 1/[A] vs time is straight line, exponent on A in rate law is 2, rate constant = slope ...