Name: ______ Date
... a) A process that absorbs energy from its surroundings is called endothermic. b) In an exothermic reaction the enthalpy of species increases. c) Energy is the capacity to do work or to transfer heat. d) Kinetic energy is the energy of motion. There are two properties of a reacting system that determ ...
... a) A process that absorbs energy from its surroundings is called endothermic. b) In an exothermic reaction the enthalpy of species increases. c) Energy is the capacity to do work or to transfer heat. d) Kinetic energy is the energy of motion. There are two properties of a reacting system that determ ...
Test 9 Review - Evan`s Chemistry Corner
... Collision theory. In order for a reaction to occur, particles of the reactant must collide. Not all collisions cause reactions. An effective collision is one in which the colliding particles approach each other at the proper angle and with the proper amount of energy to cause a reaction. The greater ...
... Collision theory. In order for a reaction to occur, particles of the reactant must collide. Not all collisions cause reactions. An effective collision is one in which the colliding particles approach each other at the proper angle and with the proper amount of energy to cause a reaction. The greater ...
Unit 2.7: Periodic Table Group1 Group2 Li Be Na Mg K Ca Rb Sr Cs
... 50.0cm3 1.00mol/dm3 HCl solution was slowly added. The equation for the reaction is When the fizzing had ceased, the contents of the beaker were washed into a standard 250cm3 volumetric flask, made up to the mark and thoroughly shaken. A pipette was used to transfer a 25.0cm 3 sample into a conical ...
... 50.0cm3 1.00mol/dm3 HCl solution was slowly added. The equation for the reaction is When the fizzing had ceased, the contents of the beaker were washed into a standard 250cm3 volumetric flask, made up to the mark and thoroughly shaken. A pipette was used to transfer a 25.0cm 3 sample into a conical ...
CHEMISTRY
... use elemental name unchanged. 2. Non-metals – change ending to “ide” *multivalent metals – those that can have more than one charge. Examples, K+ - potassium ion; N-3 – nitride ion; Cu+ - copper (I) ion (multivalent) – Do Page 158 #1,2 – Choose five other elements and write the symbol and name for t ...
... use elemental name unchanged. 2. Non-metals – change ending to “ide” *multivalent metals – those that can have more than one charge. Examples, K+ - potassium ion; N-3 – nitride ion; Cu+ - copper (I) ion (multivalent) – Do Page 158 #1,2 – Choose five other elements and write the symbol and name for t ...
Note Sheets and Sample Problems
... o e is charge on electron in Coulombs, (C) and m is its mass. o Thomson discovered that he could repeat this deflection and calculation using electrodes of different metals ∴ all metals contained electrons and ALL ATOMS contained electrons o Furthermore, all atoms were neutral ∴ there must be some ( ...
... o e is charge on electron in Coulombs, (C) and m is its mass. o Thomson discovered that he could repeat this deflection and calculation using electrodes of different metals ∴ all metals contained electrons and ALL ATOMS contained electrons o Furthermore, all atoms were neutral ∴ there must be some ( ...
Practice EXAM I
... examining P2O5. Now the equation is updated to __PH3 + __O2 1 P2O5 + __H2O Since P2O5 contains 2 phosphorus atoms, so we need two phosphorus atoms at the left side, which leads us to put 2 (called coefficient) in front of the PH3. Now the equation is updated to 2 PH3 + __O2 1 P2O5 + __H2O As the ...
... examining P2O5. Now the equation is updated to __PH3 + __O2 1 P2O5 + __H2O Since P2O5 contains 2 phosphorus atoms, so we need two phosphorus atoms at the left side, which leads us to put 2 (called coefficient) in front of the PH3. Now the equation is updated to 2 PH3 + __O2 1 P2O5 + __H2O As the ...
Language of chemistry
... MgCO3 magnesium carbonate NH4NO3 ammonium nitrate Writing formulae – Writing a formula for a compound means we should know what elements make up the compound. For example water is made up of hydrogen and oxygen in the ratio of 1:2. Therefore the formula of water is H2O. That means there are 2 hydrog ...
... MgCO3 magnesium carbonate NH4NO3 ammonium nitrate Writing formulae – Writing a formula for a compound means we should know what elements make up the compound. For example water is made up of hydrogen and oxygen in the ratio of 1:2. Therefore the formula of water is H2O. That means there are 2 hydrog ...
Today Electrochemistry electrons moving about equilibrium with a
... electrons are moving between different chemical species 2Na(s) + 2H2O(l) 2Na(s) + 2H2O(l) ...
... electrons are moving between different chemical species 2Na(s) + 2H2O(l) 2Na(s) + 2H2O(l) ...
Unit 2 – Quantities Review
... 18. Determine the percentage composition of sodium carbonate, Na2CO3. 19. Calculate the percentage composition by mass of sulfuric acid,H2SO4(aq), used in car batteries. 20. Calculate the percentage by mass of magnesium in magnesium hydroxide, Mg(OH)2(s), used in some antacids. 21. Iron and oxygen c ...
... 18. Determine the percentage composition of sodium carbonate, Na2CO3. 19. Calculate the percentage composition by mass of sulfuric acid,H2SO4(aq), used in car batteries. 20. Calculate the percentage by mass of magnesium in magnesium hydroxide, Mg(OH)2(s), used in some antacids. 21. Iron and oxygen c ...
Note 1.1 Chemistry of Life
... Some isotopes have a nucleus that is unstable therefore it may breakdown over time, giving off particles of matter that can be detected as radioactive. As the atoms nucleus breaks down, the atom is transformed into a different element. Examples: Hydrogen and Carbon Figure 3: Comparison of nuclei of ...
... Some isotopes have a nucleus that is unstable therefore it may breakdown over time, giving off particles of matter that can be detected as radioactive. As the atoms nucleus breaks down, the atom is transformed into a different element. Examples: Hydrogen and Carbon Figure 3: Comparison of nuclei of ...
Chapter 6 Chemical Composition
... If ratio ?.5, multiply all by 2; if ratio ?.33 or ?.67, multiply all by 3, etc. Skip if already whole numbers after Step 4. ...
... If ratio ?.5, multiply all by 2; if ratio ?.33 or ?.67, multiply all by 3, etc. Skip if already whole numbers after Step 4. ...
AP Chemistry MC Review Questions
... (E) Wave nature of matter 18. _____Can be used to predict that a gaseous carbon atom in its ground state is paramagnetic 19. _____Explains the experimental phenomenon of electron diffraction 20. _____Indicates that an atomic orbital can hold no more than two electrons 21. _____Predicts that it is im ...
... (E) Wave nature of matter 18. _____Can be used to predict that a gaseous carbon atom in its ground state is paramagnetic 19. _____Explains the experimental phenomenon of electron diffraction 20. _____Indicates that an atomic orbital can hold no more than two electrons 21. _____Predicts that it is im ...
Acid-Base Reactions
... 17. Combining aqueous solutions of BaI 2 and Na 2 SO 4 affords a precipitate of BaSO 4 . Which ion(s) is/are spectator ions in the reaction? A) Ba 2 only B) Na only C) Ba 2 and SO 4 2 D) Na + and I E) SO 4 2 and I 18. Write the net ionic equation for the precipitation reaction that occurs w ...
... 17. Combining aqueous solutions of BaI 2 and Na 2 SO 4 affords a precipitate of BaSO 4 . Which ion(s) is/are spectator ions in the reaction? A) Ba 2 only B) Na only C) Ba 2 and SO 4 2 D) Na + and I E) SO 4 2 and I 18. Write the net ionic equation for the precipitation reaction that occurs w ...
Electrochemistry
... -the oxidizing agent pulls electrons through the wire from the reducing agent. aka. electromotive force -unit is the volt: 1V = 1J of work per coulomb of charge (J/coulomb) -measured with a voltmeter: -drawing of current through a known resistance -or a potentiometer: measures opposition to current ...
... -the oxidizing agent pulls electrons through the wire from the reducing agent. aka. electromotive force -unit is the volt: 1V = 1J of work per coulomb of charge (J/coulomb) -measured with a voltmeter: -drawing of current through a known resistance -or a potentiometer: measures opposition to current ...
Empirical and Molecular Formula Problems – Set I
... 2. A 10.00 g sample of vitamin C was analyzed and found to contain 4.092 g of C, 0.458 g of H, and 5.450 g of O. Given that the molar mass of the compound is 176g, determine the molecular formula of vitamin C. (answer: C6H8O6) ...
... 2. A 10.00 g sample of vitamin C was analyzed and found to contain 4.092 g of C, 0.458 g of H, and 5.450 g of O. Given that the molar mass of the compound is 176g, determine the molecular formula of vitamin C. (answer: C6H8O6) ...
Fundamental Knowledge for Analysis of Chemical Reactor
... How long a reaction time will be? • Example: Decomposition of di-tert-butyl peroxide (CH3)3COOC(CH3)2C2H6 + 2CH3COCH3 • What is the reaction rate: r = -dN/dt • How long a time for a given conversion: t = N0N(-dN/r) • Obviously, r = r(N) ...
... How long a reaction time will be? • Example: Decomposition of di-tert-butyl peroxide (CH3)3COOC(CH3)2C2H6 + 2CH3COCH3 • What is the reaction rate: r = -dN/dt • How long a time for a given conversion: t = N0N(-dN/r) • Obviously, r = r(N) ...
Exam 3 Review
... Dichromate Tungstate Molybdate tetrathionate Thiosulfate Sulfite Sulfate Carbonate Hydrogen phosphate ...
... Dichromate Tungstate Molybdate tetrathionate Thiosulfate Sulfite Sulfate Carbonate Hydrogen phosphate ...
Chapter 15 - cloudfront.net
... without changing the identity of the substances that make up the material is a physical property. ...
... without changing the identity of the substances that make up the material is a physical property. ...
South Pasadena • AP Chemistry Name
... The enthalpy of the reactants, Hreactants and the enthalpy of the products, Hproducts depend on the bonding of the reactants and products… nothing else. So, the Hreaction only depends on the initial and final state of the reaction, not how you got from one state to another state. It is called a “st ...
... The enthalpy of the reactants, Hreactants and the enthalpy of the products, Hproducts depend on the bonding of the reactants and products… nothing else. So, the Hreaction only depends on the initial and final state of the reaction, not how you got from one state to another state. It is called a “st ...
Mole
... Mole Ratio In a balanced equation, the ration between the numbers of moles of any two substances. ...
... Mole Ratio In a balanced equation, the ration between the numbers of moles of any two substances. ...
Test - Regents
... If you wish to change an answer, erase your first penciled circle and then circle with pencil the number of the answer you want. After you have completed the examination and you have decided that all of the circled answers represent your best judgment, signal a proctor and turn in all examination ma ...
... If you wish to change an answer, erase your first penciled circle and then circle with pencil the number of the answer you want. After you have completed the examination and you have decided that all of the circled answers represent your best judgment, signal a proctor and turn in all examination ma ...
Unit A Review Questions
... The zinc electrode is gaining mass because the copper ions are coming out of the solution and are being reduced by the zinc metal being oxidized. This would also account for the colour change in the copper nitrate solution. As the copper ions come out of the solution, the solution becomes a fainter ...
... The zinc electrode is gaining mass because the copper ions are coming out of the solution and are being reduced by the zinc metal being oxidized. This would also account for the colour change in the copper nitrate solution. As the copper ions come out of the solution, the solution becomes a fainter ...
Stoichiometry
Stoichiometry /ˌstɔɪkiˈɒmɨtri/ is the calculation of relative quantities of reactants and products in chemical reactions.Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of product can be empirically determined, then the amount of the other reactants can also be calculated.As seen in the image to the right, where the balanced equation is:CH4 + 2 O2 → CO2 + 2 H2O.Here, one molecule of methane reacts with two molecules of oxygen gas to yield one molecule of carbon dioxide and two molecules of water. Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry. In the example above, reaction stoichiometry measures the relationship between the methane and oxygen as they react to form carbon dioxide and water.Because of the well known relationship of moles to atomic weights, the ratios that are arrived at by stoichiometry can be used to determine quantities by weight in a reaction described by a balanced equation. This is called composition stoichiometry.Gas stoichiometry deals with reactions involving gases, where the gases are at a known temperature, pressure, and volume and can be assumed to be ideal gases. For gases, the volume ratio is ideally the same by the ideal gas law, but the mass ratio of a single reaction has to be calculated from the molecular masses of the reactants and products. In practice, due to the existence of isotopes, molar masses are used instead when calculating the mass ratio.