Mrs. Burns: 2012185859 Day 1 Physics consist of a variety of topics
... Law of inertia: an object is in motion when it is in motion. And an object is at rest unless it is acted upon. At rest= static equal liberium V and A are all zero. Dynamic equal liberium: when velocity is not zero but the acceleration is zero. Force: push or pull external system. The force cannot be ...
... Law of inertia: an object is in motion when it is in motion. And an object is at rest unless it is acted upon. At rest= static equal liberium V and A are all zero. Dynamic equal liberium: when velocity is not zero but the acceleration is zero. Force: push or pull external system. The force cannot be ...
REVIEW: (Chapter 8) LINEAR MOMENTUM and COLLISIONS The
... The previous example involved essentially just one particle, the car. The wall was fixed there as a device for exerting a constant force during the collision. A more complex example can be studied when two particles collide. We first make the approximation that the two particles are subjected to no ...
... The previous example involved essentially just one particle, the car. The wall was fixed there as a device for exerting a constant force during the collision. A more complex example can be studied when two particles collide. We first make the approximation that the two particles are subjected to no ...
Impulse and Conservation of Momentum Notes
... Ex. I: What is the initial velocity of a 1000 kg car traveling to the right that hits a 3000 kg truck traveling at 20 m/s to the left. After the elastic collision, the truck is traveling 10 m/s and the car is traveling 15 m/s both to the left? ...
... Ex. I: What is the initial velocity of a 1000 kg car traveling to the right that hits a 3000 kg truck traveling at 20 m/s to the left. After the elastic collision, the truck is traveling 10 m/s and the car is traveling 15 m/s both to the left? ...
c - APPhysics-PHY101-PHY111-PHY112
... EXAMPLE: Show that the following formula is correct: E2 = p2c2 +m02c4 Relativistic momentum / energy SOLUTION: Note: E2 = 2m02c4 and p2 = 2m02v2. So… p2c2 + m02c4 = 2m02v2c2 + m02c4 = m02c2( 2v2 + c2 ) = m02c2[ v2 / (1 – v2/ c2) + c2 ] = m02c2[ c2v2 / (c2 – v2) + c2 ] = m02c4[ v2 / (c2 – v2) + 1 ...
... EXAMPLE: Show that the following formula is correct: E2 = p2c2 +m02c4 Relativistic momentum / energy SOLUTION: Note: E2 = 2m02c4 and p2 = 2m02v2. So… p2c2 + m02c4 = 2m02v2c2 + m02c4 = m02c2( 2v2 + c2 ) = m02c2[ v2 / (1 – v2/ c2) + c2 ] = m02c2[ c2v2 / (c2 – v2) + c2 ] = m02c4[ v2 / (c2 – v2) + 1 ...
Rotary
... -Angular velocity is the change in angular displacement per unit time. The symbol for angular velocity is ω and the units are typically rad s-1. Angular speed is the magnitude of angular velocity. -The instantaneous angular velocity is ...
... -Angular velocity is the change in angular displacement per unit time. The symbol for angular velocity is ω and the units are typically rad s-1. Angular speed is the magnitude of angular velocity. -The instantaneous angular velocity is ...
Circular Motion
... (horizontal). Estimate the force a person must exert on a string attached to a 0.150-kg ball to make the ball revolve in a horizontal circle of radius 0.600 m. The ball makes 2.00 revolutions per second. Ignore the string’s mass. ...
... (horizontal). Estimate the force a person must exert on a string attached to a 0.150-kg ball to make the ball revolve in a horizontal circle of radius 0.600 m. The ball makes 2.00 revolutions per second. Ignore the string’s mass. ...
Centripetal Force - MsHughesClassroom
... 5. What force is needed to turn a 750kg car around a corner with a radius of 12m if the car is going 43m/s? 6. The centripetal force required to turn a 17,000kg plane around a 450m arc is 54,0000N, how fast is the plane traveling? 7. A rock is on the end of a 3m string spinning at 25m/s. The centrip ...
... 5. What force is needed to turn a 750kg car around a corner with a radius of 12m if the car is going 43m/s? 6. The centripetal force required to turn a 17,000kg plane around a 450m arc is 54,0000N, how fast is the plane traveling? 7. A rock is on the end of a 3m string spinning at 25m/s. The centrip ...
Homework Booklet - Lesmahagow High School
... a) Calculate the peak voltage of the supply. b) An oscilloscope, with its time-base switched off, is connected across the supply. The Y-gain of the oscilloscope is set to 5 V cm–1. Describe the trace seen on the oscilloscope screen. ...
... a) Calculate the peak voltage of the supply. b) An oscilloscope, with its time-base switched off, is connected across the supply. The Y-gain of the oscilloscope is set to 5 V cm–1. Describe the trace seen on the oscilloscope screen. ...
30155-doc - Project Gutenberg
... you were chased about for uncounted hours by conscientious teachers. By reason of our past experience, you would certainly regard everyone with disdain who should pronounce even the most out-of-the-way proposition of this science to be untrue. But perhaps this feeling of proud certainty would leave ...
... you were chased about for uncounted hours by conscientious teachers. By reason of our past experience, you would certainly regard everyone with disdain who should pronounce even the most out-of-the-way proposition of this science to be untrue. But perhaps this feeling of proud certainty would leave ...
PS-5
... If an object is traveling at a constant speed, the instantaneous speed at each point will be equal to the average speed. If an object is traveling with varying speeds, the average speed is the total distance covered divided by the total time. Understand Velocity: ○ Velocity refers to both the ...
... If an object is traveling at a constant speed, the instantaneous speed at each point will be equal to the average speed. If an object is traveling with varying speeds, the average speed is the total distance covered divided by the total time. Understand Velocity: ○ Velocity refers to both the ...
Physics 207: Lecture 2 Notes
... D. We can’t tell about n without knowing v. At what speed do we lose contact? This occurs when the normal force goes to zero or, equivalently, when all the weight is used to achieve circular motion. Fc = mg = m v2 /R v = (g/R) ½ (just like an object in orbit) ...
... D. We can’t tell about n without knowing v. At what speed do we lose contact? This occurs when the normal force goes to zero or, equivalently, when all the weight is used to achieve circular motion. Fc = mg = m v2 /R v = (g/R) ½ (just like an object in orbit) ...
topic 1 - Dr. Mohd Afendi Bin Rojan, CEng MIMechE
... Acceleration is the rate of change in the velocity of a particle. It is a vector quantity. Typical units are m/s2 or ft/s2. The instantaneous acceleration is the time derivative of velocity. Vector form: a = dv/dt Scalar form: a = dv/dt = d2s/dt2 Acceleration can be positive (speed increasing) or ne ...
... Acceleration is the rate of change in the velocity of a particle. It is a vector quantity. Typical units are m/s2 or ft/s2. The instantaneous acceleration is the time derivative of velocity. Vector form: a = dv/dt Scalar form: a = dv/dt = d2s/dt2 Acceleration can be positive (speed increasing) or ne ...
