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Transcript
Name __________________________________________________________________ Period:______ Sex-Linked Traits Worksheet Background Information: Sex-linked traits are those whose genes are found on the X chromosome but not on the Y chromosome. In humans the X chromosomes are much larger than the Y chromosome and contains thousands of more genes than the Y chromosome. For each of the genes that are exclusively on the X chromosomes, females, who are XX, would obviously have two alleles. Males, who are XY, would have only one allele. Thus females with one recessive allele and one dominant allele, for a gene that is unique to the X chromosome, will always display the dominant phenotype. However, a male with a recessive allele for a gene unique to the X chromosome will always exhibit that recessive trait because there is no other corresponding allele on the Y chromosome. In humans, each of two different sex-linked genes has a defective recessive allele that causes a disease. The diseases are hemophilia and colorblindness. In hemophilia, the defective allele prevents the synthesis of a factor needed for blood clotting. In colorblindness, the defective allele prevents a person from seeing certain colors. 1. What is a sex-linked trait? 2. Why must males inherit colorblindness or hemophilia from their mothers? 3. Why is colorblindness or hemophilia more common in males than in females? Use the information below to answer the following questions. XH- X chromosome with normal dominant allele (no hemophilia) Xh - X chromosome with recessive hemophilia allele Y - Y chromosome (does not contain comparable gene) XB - X chromosome with normal dominant allele (not colorblind) Xb - X chromosome with recessive colorblind allele Y -Y chromosome (does not contain comparable gene) 1. Write the genotypes for the following phenotypes of red-green color blindness. a. normal male _____________ b. normal female carrying no colorblind alleles (Ho) _____________ c. colorblind male ___________ d. normal female carrying the colorblind allele (He) ______________ e. colorblind female _________ 2. XBXB x XbY a. What percentage of the male children are colorblind? _____________ b. What percentage of the female children are colorblind? _____________ 3. XBXb x XBY a. What percentage of the male children are colorblind? _____________ b. What percentage of the female children are colorblind? _____________ 4. A normal-sighted woman (whose father was colorblind) marries a colorblind man. _____________ X _____________ a. What is the probability that they will have a son who is colorblind? _________ b. What is the probability that they will have a colorblind daughter? __________ For the following Sex-Linked Punnett Squares: H= normal blood clotting h=hemophilia 5. XHXh x XHY a. What is the probability that any of their offspring will have hemophilia? _____________ 6. A woman who is a carrier for hemophilia marries a hemophiliac man. a. What percentage of the male children are hemophiliacs? _____________ b. What percentage of the female children are hemophiliacs? _____________ In fruit flies, the gene for red eyes (R) is dominant over the gene for white eyes (r). This is sex-liked. 7. Cross a heterozygous female and a red eyed male. a. What percentage of the male children have red eyes? ____________ b. What percentage of the female children have red eyes? ___________ 8. Cross a heterozygous female and a white eyed male. a. What percentage of the male children will have white eyes? _________ b. What percentage of the female children will have white eyes? ________ In cats, black color is due to the gene (B) and yellow color is (b). Yellow color is codominant to black with heterozygous condition resulting in a color known as calico (Bb), which is black, yellow, and white spotted. These genes are sex-linked and carried on the X chromosome. 9. Mate a black male with a yellow female. a. What percentage of the females are calico? _________ b. What color will the make kittens be? _________ 10. Mate a calico female with a black male. a. What percentage of the females are calico? __________ b. What percentage of the males are yellow? ___________ Human Genetics Review 1. The karyotype shows a (female/male). 2. Is the karyotype missing a chromosomes? (yes/no) 3. If so, what chromosome pair? _____ 4. Does the karyotype have an extra chromosome? (yes/no) 5. If so, what chromosome pair? _____ 6. _____ Which of the following genotypes result in the same phenotype? a. IAIB and IAIA c. IBIB and IAIB A A A b. I I and I i d. IBi and ii 7. _____ A woman with blood type B gives birth to a type O baby. Which of the following males below must be the baby’s father? a. Tom – type B blood homozygous c. Jim – type AB blood b. Bob – type A blood heterozygous d. John – type ABC blood 8. A woman with type B blood marries a man with type A blood. They have two children. One of the children has type B like his or her mother and one has O type blood. a. Complete the Punnett square. b. Write the genotypes of the parents. ___________X ________________ c. Write all possible phenotypes for the children. ________________________________