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Transcript
期中報告 授課教授:秦純 教授 班級:碩研電機一甲 姓名:吳旻鴻 學號:MA020127 Question 4.12 The three-phase synchronous machine of Problem 4.9 is to be moved to an application which requires that its operating frequency be reduced from 60 to 50Hz. This application requires that , for the operating condition considered in Problem 4.8, the rms generated voltage equal 13.0 kV line-to-line. As a result, the machine armature must be rewound with a different number of turns. Assuming a winding factor of Kw=0.928, calculate the required number of series turns per phase. Answer 線電壓的均方根值 由4.9可知 因此 Question 4.18 A two-pole, 60 Hz, three-phase, laboratory-size synchronous generator has a rotor radius of 5.71 cm, a rotor length of 18.0 cm, and an air-gap length of 0.25 mm. The rotor filed winding consists of 264 turns with a winding factor of kr = 0.95. The Y-connected armature winding consists of the 45 turns per phase with a winding factor kw = 0.93. a. Calculate the flux per pole and peak fundamental air-gap flux density which will result in an open-circuit, 60-Hz armature voltage of 120 V rms / phase (line-to-neutral). b. Calculate the dc field current required to achieve the operating condition of part (a). c. Calculate the peak values of the field-winding to armature-phase-winding mutual inductance. (a) Answer φ=BA(wb) (b) (c)