Download Master Sheet Mole:Mole Ratios and Mass

Master Sheet Mole:Mole Ratios and Mass
Name:
You’ve gotten a job at Eli Lilly & Co! You must calculate how many grams of a certain chemical you will need in
order to make the drug that you are in charge of. How will you do this? You will use, in part, mole to mole ratios.
How to use mole: mole ratios to determine how much of a chemical is needed for a reaction:
1. Balance the chemical equation.
2. Use factor label!
3. Convert to moles (using atomic or molar masses)
4. Use the chemical equation to write a mole:mole ratio that allows you to convert from one chemical
to another. This is a Magic Moment: it is the ONLY time you can go from one chemical to another! I
use a DIAMOND to mark this kind of factor.
5. Convert moles to grams (again, using atomic or molar masses)
Example: Propane, C3H8, when used as a fuel, reacts with oxygen gas to produce carbon dioxide and water:
C3H8 (g) + O2(g)  CO2 (g) + H2O (g)
What mass of oxygen gas will be required to react exactly with 96.1g of propane?
Balanced EQ: C3H8 (g) + 5O2(g)  3CO2 (g) + 4H2O (g)
96.1 g propane x 1 mole propane x 5 mole O2 x 32.0 g O2 = 349.5 g O2
44.0 g propane 1 mole propane 1 mole O2
Practice:
Na2SiO3 (s) + 8 HF(aq) H2SiF6 (aq) + 2 NaF(aq) + 3 H2O (l)
a. How many moles of HF are needed to react with 0.300 mol of Na2SiO3?
b. How many grams of NaF form when 0.500 mol of HF reacts with excess Na2SiO3?
c. How many grams of Na2SiO3 can react with 0.800 g of HF?
WS Mole- Mole Ratios and Mass
Name:
C6H12O6 (aq) 2 C2H5OH (aq) + 2 CO2 (g)
a. How many grams of CO2 are produced when 0.400 mol of C6H12O6 are put into the reaction?
b. How many grams of C6H12O6 are needed to form 7.50 g of C2H5OH?
c. How many grams of CO2 form when 7.50 g of C2H5OH are produced?