Download Problem 3.67 For the circuit in Fig. P3.66, find the Thévenin

Problem 3.67 For the circuit in Fig. P3.66, find the Thévenin equivalent circuit as
seen by the 6-Ω resistor connected between terminals (c, d) as if the 6-Ω resistor is a
load resistor connected to (but external to) the circuit. Determine the current flowing
through that resistor.
4A
c
4Ω
+
d
_
Voc
8Ω
4Ω
I1
+
_
10 Ω
48 V
I2
Solution:
16I1 − 12I2 = −48
I2 = −4 A
Hence, I1 = −6 A.
To find Voc , we write a KVL equation for loop in lower right-hand corner:
−48 + 8(I2 − I1 ) +Voc + 10I2 = 0
Voc = 48 + 8I1 − 18I2
= 48 − 48 + 18 × 4 = 72 V.
Suppressing the sources:
Req
c
4Ω
4Ω
d
10 Ω
8Ω
RTh = 14 Ω.
I
c
6Ω
d
14 Ω
+_
I=
72
72
=
= 3.6 A.
14 + 6 20
72 V
c
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