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Transcript
ionization potential • IP(Z) of 2nd row elements why IP(Be)> IP(B) and I(O)< I(N)? 2p 2s ↑↓ atomic radius electron affinity • IP(Z) of 2nd row elements why IP(Be)> IP(B) and I(O)< I(N)? Physical Chemistry Fundamentals: Table 9.3 Physical Chemistry Fundamentals: Table 9.4 Sc (3d4s2) Sc (3d24s1) Sc+1 (3d2) • Neutral atom: strong e--e- repulsion in the 3d orbitals. • Electronic configuration 3dn4s2 for Sc(n=1) through Zn(n=8). exceptions: Cr and Cu • When ionized, 4s electrons are removed. ex: V2+(3d3) which is isoelectronic to Sc(3d14s2) → e-e repulsion energy is compensated by Coulomb attraction by the V2+ nucleus with a higher Zeff than that of Sc. Physical Chemistry Fundamentals: Figure 9.16
