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Transcript
Chapter 18 Electric Forces and Electric Fields
The equation for Coulomb’s law is
Kq1 q 2
FE =
r2
where FE is the electric force, q1 and q2 are the charges, r is the distance between their
centers, and K is a constant which equals 9 x 109 Nm2/C2.
r
F
-q1
+q2
Sometimes the constant K is written as K =
1
4πε o
, where εo = 8.85 x 10-12 C2 / Nm2.
Example 4
r
+2 µC
-4 µC
Two point charges q1 = +2 µC and q2 = - 4 µC are separated by a distance r, as shown
above.
(a) If the force between the charges is 2 N, what is the value of r?
(b) Where could you place a third charge q3 = +1 µC on the horizontal axis so that there
would be no net force acting on q3? Find an equation which could be solved for x, where
x is the distance from the +2 µC charge to q3. It is not necessary to solve this equation.
Solution
(a)
Kq1 q 2
FE =
r2
r=

Nm 2
 9 x10 9
C2
Kq1 q 2

=
FE
2N



= 0.19 m
205
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