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Skylar Geer – Stats 1040 Objective I Roll Total 2 3 4 5 6 7 8 9 10 11 12 (Die1, Die2) (1,1) (1,2) (2,1) (1,3) (3,1) (2,2) (1,4) (4,1)(2,3)(3,2) (1,5)(5,1) (3,3)(4,2)(2,4) (1,6)(6,1)(3,4)(4,3)(5,2)(2,5) (2,6)(6,2)(5,3)(3,5)(4,4) (3,6)(6,3)(4,5)(5,4) (5,5)(4,6)(6,4) (5,6) (6,5) (6,6) # of Combo’s 1 2 3 4 5 6 5 4 3 2 1 Total: 36 Probability 1/36 2/36 or 1/18 3/36 or 1/12 4/36 or 1/9 5/36 6/36 or 1/6 5/36 4/36 or 1/9 3/36 or 1/12 2/36 or 1/18 1/36 The Probability of rolling P(7) is: 1/6 Conclusion for objective I: The simulated probability of rolling a 7 is: (Total '7') / 100 = _14/100 or 7/50___. The simulated probability or rolling a 4 is 10/100 or 1/10_? Rolling a 12? 5/100 or 1/25_. Objective II A. less than 20% B. 20-40 C. 40&-60% D. 60%-80% E. Over 80 Procedure for Objective II Step A: To generate random numbers for 25 students who birthdays range from Jan 1 to Dec 31 (365 days) I will click on the “data analysis” tab under the “Data” tab. I will select “random number generator.” I will enter in the following data. Number of variables: 1 Number of random numbers: 25 Distribution: Uniform Parameters: 1 to 365 Output range: $A$1 I will repeat this 9 more times to get a total of 10 classes. Step B: In order to determine if there are duplicate birthdays I will sort all of the 10 classes from smallest to largest. To do this I will right click on the column, click on “sort”, and then click on “custom sort”, and then click on “continue with current selection.” I will repeat this 9 more times to sort all the classes. Then I will compare the numbers to see if anyone has the same birthday. Step C: I will count up the number of “yes’” and take it out of the total of 10 classes. Conclusion: The probability that a class of 25 students will have duplicate birthdays is: __7/10 classes . A. less than 20% B. 20-40 C. 40&-60% D. 60%-80% E. Over 80. I was close just about 10% off.