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Bernard Nefalar Calculus Period 4 Introduction 5/31/2013 Outcome: Students will be able to evaluate integrals. Warm Up Standards 1 10+5=15 mins Find dy. dx 1) y + 7x6 = 0 2) xy - 3x5 = -1 3) y2 - 13x4 + 6x3 + x = – 1 x Topic 1: Integrals Definition Antiderivative (Integral) – F(x): A function x of y such that x’ = y. (Think opposite of derivative.) [Don’t write this.] Question…What is the difference between dy of 2x3 + 5 and dy of 2x3 + 99? dx dx Does the 5 or 99 matter? But the functions are totally different. Here we introduce C or the constant. This is important for antiderivatives/integrals. In addition, each f’(x) will have a dx attached to it which comes from the dx of the dy. dx Given f’(x) then, f(x) + C = f’(x) dx. (9:25-9:40) 30 mins. Procedure Step 1: Start with the exponent and add 1 to find the new exponent. Step 2: Divide the coefficient with this new exponent. Step 3: Don’t forget to add the C (constant to the new function to cover all of the constants that will make the function true). Note: Given a f(x) multiplied by a constant c, cf(x) dx = c f(x) dx. For examples 1-6, find the antiderivative. Example 1 x2 dx Example 2 (x2 – 5) dx Example 3 5 dx Example 4 1 dx x3 Example 5 5(x2 + 1) dx Example 6 -(x3 + 5x) dx Checkpoint Find the antiderivative. 1) (x2 – 2) dx 2) 3(x2 – 2x + 3) dx 3) (x3/2 + 2x + 1) dx 4) 1 dx 2x4 (9:40-9:55) 15+5=20 mins.