Download COMPETENCY 1: Graphing Lines Using a T

ALGEBRA I
Linear Systems
REVIEW 2
Directions: Do each of the following problems on a separate piece of
paper. Copy all problems and follow the criteria for credit.
COMPETENCY 1: Solutions and Solving
Systems by Graphing
1. Tell whether the ordered pair (3, -2) is a
solution of the system. Justify your answer.
x - 2y = 7
COMPETENCY 3: Distributed Practice
11. Graph the line through the point (-3, -1) that
is a) parallel and b) perpendicular
to the line in the following graph.
2x - y = 8
5
4
3
2. Tell whether the ordered pair (-2, 1) is a
solution of the system. Justify your answer.
- x + y = -1
2
1
3x + y = -5
-5 -4 -3 -2 -1
-1
1
2
3
-2
For questions 3-5, Solve each system by
graphing.
-3
-4
-5
3.
y = -x + 3
y = 2x – 3
4.
2x - y = 4
4x - 8 = 2y
5.
y=
1
x+3
2
12. Write the equation of the line that has a
slope of -
1
and passes through (0,3 ).
2
2x - 4y = 8
13. Solve.
COMPETENCY 2: Solving Systems by
Substitution and Elimination
a) 10 - 2x + 5x = - 3x + 22
b) -15 – 5y – 6 < 3 + y
6. Solve the system by substitution:
3x + y = 12
y = 5x - 20
14. Simplify.
7. Solve the system by elimination:
2x - 5y = -7
5x - 3y = 11
15. The equation x2 - 2x - 3 = 0 can be solved
8. Solve the system:
-2x + 2y= 6
9. Solve the system:
a)
y=x-2
b) -9x - 3y = -18
3(2x2 + 1x) - 2(x - 3)
using the formula
4x - y = 3
 b  b 2  4ac
.
2a
Given that a = 1, b = - 2, and c = -3, substitute
to solve. (Remember: you will get two answers.)
x - y = -2
3x + y = 6
10. Use a system to solve the following:
The sum of two numbers is 26. The difference
of the same two numbers is 6. Find the two
numbers.
Property of Springdale School District, 2008
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ALGEBRA I
Linear Systems
REVIEW 2
Directions: Do each of the following problems on a separate piece of
paper. Copy all problems and follow the criteria for credit.
ANSWERS
1. (3, -2) is a solution because
3 + 4 = 7 and 6 + 2 = 8
2. (-2, 1) is not a solution because
2 + 1  -1 but -6 + 1 = -5
3.
5
6. (4, 0)
7. (4, 3)
8. (2, 5)
9. a) no solution
b) many solutions
10. The numbers are 16 and 10.
x + y = 26
x-y=6
x = 16 and y = 10
4
3
2
-5 -4 -3 -2 -1
-1
4
(-3, -1)
2
3
1
(2,1)
5
11.a.
1
2
3
4
5
m=-
-2
-3
1
2
3
-5 -4 -3 -2 -1
-1
-4
-2
-5
-3
1
2
3
4
5
1
2
3
4
5
-4
-5
5
4.
5
4
4
3
1
-5 -4 -3 -2 -1
-1
2
1
4
3
2
1
5
m=
-2
-3
many solutions
3
11.b.
(-3, -1)
2
-5 -4 -3 -2 -1
3
2
-1
-2
-4
-3
-5
-4
-5
5
4
5.
12. y = -
3
1
x+3
2
2
1
-5 -4 -3 -2 -1
-1
-2
-3
-4
13.a. x = 2
1
2
3
4
13.b.
y>–4
5
14. 6x2 + x + 6
15.
x = 3 or x = -1
no solution
Property of Springdale School District, 2008
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