Download Lecture Notes for Section 2.3

Trigonometry Lecture Notes
Section 2.3
Page 1 of 7
Section 2.3: Finding Trigonometric Function Values Using a Calculator
Big Idea: If you need the value of a trigonometric function of an angle that is not 30, 45, or
60, then you need a calculator to get the answer.
Big Skill: You should be able to use a calculator to find the value of any trig function at any
given angle.
Evaluating Sine, Cosine, and Tangent on a Calculator
 Make sure your calculator is in degree mode.

Enter the trig function followed by the angle in parentheses.

For angles in DMS, you can enter the angle using the DMS functionality of your
calculator.

For angles in DMS, you also can enter the angle as the number of degrees plus fractions
of a degree.
Trigonometry Lecture Notes
Practice:
1. Compute sin(52)
2. Compute cos(187.48)
3. Compute tan(-2000)
4. Compute sin(187 44)
5. Compute cos(-225 32 11)
6. Compute tan(1500 22 38.95)
Section 2.3
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Trigonometry Lecture Notes
Section 2.3
Page 3 of 7
Evaluating Secant, Cosecant, and Cotangent on a Calculator
 Calculators do not have buttons for these functions.
 You have to use the reciprocal identities to evaluate these trig functions on a calculator.
1
sec  
cos 
The Reciprocal Identities (Section 1.4)
1
1
csc 
cot  
sin 
tan 

To enter the reciprocal calculations correctly, you have to enter 1 divided by the correct
trig function. DO NOT use the SIN-1, COS-1, or TAN-1 buttons for cosecant, secant, or
cotangent; those are the inverse functions (not the reciprocals).

For angles in DMS, you can enter the angle using the DMS functionality of your
calculator.

For angles in DMS, you also can enter the angle as the number of degrees plus fractions
of a degree.
Trigonometry Lecture Notes
Practice:
7. Compute sec(52)
8. Compute csc(187.48)
9. Compute cot(-2000)
10. Compute cot(187 44)
11. Compute csc(-225 32 11)
12. Compute sec(1500 22 38.95)
Section 2.3
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Trigonometry Lecture Notes
Section 2.3
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Finding Angle Measures on a Calculator
 Recall the use of inverse functions from algebra:
o The composition of a function and its inverse (and vice-versa) “cancel”
o
 16 
2
  4   16 ;
2
32  9  3 ; the square root and squaring functions are
inverses of each other
o We also say that the composition of a function and its inverse return the argument of
the inner function.
o This property can be used to solve equations by isolating a function and then applying
the inverse function to both sides.
x  15
f  x  k
 x

2
f 1  f  x    f 1  k 
 152
x  f 1  k 
x  225
We can use this inverse function property notion to solve equations where a trig function
of an unknown angle is equal to a constant. We then just take the inverse function of
both sides of the equation to find the angle.
o The inverse sine function is written as sin-1.
o The inverse cosine function is written as cos-1.
o The inverse tangent function is written as tan-1.
sin    0.5
cos    0.5
sin 1  sin     sin 1  0.5 
cos 1  cos     cos 1  0.5 
  sin 1  0.5 
  cos 1  0.5 
  30
  60
tan    0.5
tan 1  tan     tan 1  0.5 
  tan 1  0.5 
  26.565

Note that when you use the inverse trig functions on a calculator,
o The sin-1 function returns an angle in the interval 90    90 .
o The cos-1 function returns an angle in the interval 0    180 .
o The tan-1 function returns an angle in the interval 90    90 .
Trigonometry Lecture Notes

Section 2.3
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To find an angle for the secant, cosecant, and cotangent functions, you have to use the
reciprocal identities first to convert the equation so that it has cosine, sine, or tangent.
csc    2.2
sec    19
1
 2.2
sin  
1
 19
cos  
1
2.2
1
sin  sin     sin 1 1/ 2.2 
1
19
1
cos  cos     cos 1  1/19 
  sin 1 1/ 2.2 
  cos 1  1/19 
  27.036
  93.017
sin   
cos    
cot    1
1
 1
tan  
tan    1
tan 1  tan     tan 1  1
  tan 1  1
  45
Practice:
13. Find an approximate numerical answer for a value of  that satisfies cos    0.87 .
14. Find an approximate numerical answer for a value of  that satisfies sin    0.53 .
15. Find an approximate numerical answer for a value of  that satisfies tan    1.115 .
Trigonometry Lecture Notes
Section 2.3
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16. Find an approximate numerical answer for a value of  that satisfies sec    2.54 .
17. Find an approximate numerical answer for a value of  that satisfies csc    2.6 .
18. Find an approximate numerical answer for a value of  that satisfies cot    12.5 .