Download Algebra: Products and Factors Unit 3 Dividing up

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Penrose tiling wikipedia , lookup

Addition wikipedia , lookup

Factorization wikipedia , lookup

Elementary mathematics wikipedia , lookup

Transcript
Unit 3
Unit 3
Factors
Dividing up
Dividing up
WHAT THIS UNIT IS ABOUT
In this unit you will be dividing up numbers
into their factors. A factor is a number that can
divide into another number without leaving a
remainder.
In this unit you will be using factors to help to
design patterns of bathroom tiles and to work
out how to make a family sized bar of chocolate
so that it can be divided up fairly among the
people in different families.
You will then learn about factorising algebraic
expressions rather than numbers. You will find
out how to take out common factors from an
expression and how to factorise expressions
that involve the difference of two squares.
Photograph of a bathroom being tiled.
In this unit you will

Work out the number of rows and
columns of tiles you will need to
cover the space above a kitchen sink
and how many tiles you will need if
you want to use a range of colours.

Factorise algebraic expressions by
taking out common factors

Factorise a range of different
numbers

Factorise expressions containing the
difference of two squares.

Design a chocolate bar that can be
divided up equally among families
with different numbers of people.

Rearrange and regroup algebraic
expressions to allow them to be
factorised more easily.
©PROTEC 2001
15
Activity 1
Kitchen Tiles
The situation
A friend has asked you to help him tile the wall above his
kitchen sink. He wants to tile from the left hand wall to
the window, a distance of 120cm. He wants the tiles to
reach at least 75cm above the sink.
Kitchen
He wants you to work out how many tiles he will need if
he has chosen tiles that are 10cm square.
1.1 Discuss the situation above with your group and then answer the
questions below to help your friend to tile his kitchen.

How many tiles will fit in each row between the window and the wall of the
kitchen.

How many rows of tiles will be needed to cover 75cm of wall above the sink if
you only use whole tiles?

What is the total number of tiles you will need for the job?

If your friend decides on 3 colours how many of each colour will he need if he
uses equal numbers of each colour?

Could he choose 4 colours? If so how many of each colour would he need if he
uses equal numbers of each colour?

Tile City have a special on packs of 12 tiles in different colours. Advise your
friend how many different colours he should buy and how many packs of tiles he
will need.

Draw a diagram of a few rows of tiles showing him how to arrange the colours to
give a balanced look.

How many of each colour will be in each row?
The numbers 3,4 and 8 are
factors of the number 96
because 3x4x8=96
©PROTEC 2001
16
Lowest Factors or Prime
Factors
The lowest
factors of 96 are
2x2x2x2x2x3
The lowest factors of a number
are numbers that cannot be
divided into any other numbers.
In the tiling example above the
factors of 96 are 3,4 and 8 but both 4 and 8 can be further
divided into smaller whole numbers.
Some numbers can only be divided by themselves and 1. These are known as prime
numbers. 2,3,5 and 7 are the first prime numbers. A prime number is a number that has 2
and only 2 factors, themselves and 1.
Lowest factors are always prime numbers because they cannot be divided further. That is
why they are also called Prime Factors.
1.2 Find the prime factors of the following numbers.
1
2
3
4
24
6
8
12
5
6
7
8
18
36
14
60
9
10
11
12
33
10
7
25
Using Prime Factors to find new factors.
Prime factors can be recombined to create new factors for the
same number.
In the tiling example 12 tiles per row times 8 rows gave 96 tiles
in total. 3 colours times 36 tiles of each colour also comes to 96
tiles in total. If we wanted to use 4 colours we would need 24
tiles of each colour to give us 96.
Tips for finding prime factors.




Divide by 2 until you have an odd
number.
Divide by 3 as many times as you can
Then 5 then 7 until all the factors
you have are prime numbers.
Check that when you multiply all
your factors together you get the
original number.
©PROTEC 2001
8x12, 3x36 and
4x24 are different
ways of combining
the factors of 96.
These could also be
written as
(2x2x2)x(3x2x2),
3x(2x2x3x3) and
(2x2)x(3x2x2x2)
17
Activity 2
Reshaping the family chocolate
The situation
Nestburies is a new chocolate company that wish to appeal to families. They are
investigating new shapes and sizes for chocolate that can be shared equally among family
members.
They have asked you to come up with a range of different drawings of big (family sized)
slabs of chocolate, showing how pieces can be broken off. They have decided to target
families with 6 members but they have asked that you make your design suit as many
different families as possible.
2.1
Discuss this situation with your group. Discuss the different sizes of
chocolate bars and how many pieces the bar can be divided into. Also
discuss how many pieces each family member would be happy with
when the chocolate is divided up.
Then work through the questions below as a guide to come up with
some solutions.
2.2
1.
Work out how many pieces of chocolate the whole bar could have.
2
Work out the prime factors of this number. You will need lots of factors to be
able to cater for different family sizes.
3
Change the number if you want to increase the number of ways you can
divide the chocolate.
4
Come up with another list of lowest factors.
5
Make sure your chocolate bar can be shared equally by a family of 6
members. If so how many pieces can each member have?
6
Check how this size suits different families.
7
Draw different shapes for the bar of chocolate, from thin and long to square.
For each shape write down how many rows in the slab and how many pieces
per row. (e.g. 8x8=64 pieces)
©PROTEC 2001
18
Activity 3
Factors and Algebra
Common Factors
Factorising algebraic expressions is like reversing the Distributive law used to work out
the product of expressions.
Examples
2x+2y=2(x+y)

a(x+y)+b(x+y)=(a+b)(x+y)
3.1
2 is a factor common to both terms.
(x+y) is a common factor to both terms

Fully Factorise the algebraic expressions below:
1. 2rh  2r 2
4. 3 px  3 py  2 x  2 y
2. ( px  y )  q( x  y )  r ( x  y )
5.
3. 4 x  5 y  x(4 x  5 y )
6. 6a  12ab 2  18a 3b3
Example
Sometimes you
will need to
change a sign or
the brackets
before you can
see the common
factors.
p 2 q q 4  p 3a 3
Changing the sign
a ( x  y )  b( y  x )
 a ( x  y )  b( x  y ) 
 ( x  y )( a  b)
Example
+ ( y  x )  ( x  y )
Using brackets to regroup factors
pq  pr  tq  tr
 p(q  r )  t (q  r )
Now you can see the

common factor
3.2 Now
Factorise
these
expressions
1.
p 2 (a  2b)  r 3 (2b  a)
2. a( x 2  x  1)  b( x 2  x  1)
3.
p 2 (a  b)  p(b  a)
4. 3 px  3 py  2 x  2 y
©PROTEC 2001
19
Difference of two squares
The difference of two squares is a
special expression that can be factorized
easily if you notice it.
Example
The difference of the
two squares ( x 2  y 2 )
If you multiply the expression
( x  y )( x  y ) = ( x 2  y 2 )
Since it doesn’t matter what the
values of x and y are we can
factorise any expression similar to
( x 2  y 2 ) , i.e.
a
You can check this for
yourself using real
numbers.
Is (25-9)=(5+3)(5-3)?
Is (36-4)=(6+2)(6-2)?
2

 b2  (a  b)(a  b)
(9  x )  (3  x)(3  x)
2
3.3 Now Factorise these
expressions. Look for the
difference of two squares but
you may have to rearrange some
of them first.
1. 16a 2  49b 2
6. 36a 4  49(a  b)2
2. 32a 2  2b 2
7. 36a 2 ( x  y)  49b2 ( y  x)
3. a 2b  16b3
8. a 2  b 2  a  b
4. a 4  16
9. ( x 2  y 2 )2  ( p 2  q 2 )2
5. 4(3a  b)2  25(a  b)2
10. (a  b  c)2  (a  b  c)2
3.4 Now factorise the mixed examples below
1.
2.
3.
4.
5.
1 2
x  8 y2
2
7 a 4  7c 4
4(3x  y)2  9(3x  y)2
a8  1
w2  x 2  w  x
6.
7.
8.
9.
(a  b  c)2  (2a  b  c)
9(a  b)2  16c 2
( x  y)4a 2  ( y  x)9b2
64(a  1)  81(a  1)2
10. ( x 2  x)2  ( y 2  y)
©PROTEC 2001
2
20
©PROTEC 2001
21