* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download i̇tü geli̇şti̇rme vakfi
Survey
Document related concepts
Transcript
İTÜ GELİŞTİRME VAKFI ÖZEL EKREM ELGİNKAN LİSESİ WORKSHEET LESSON: Physics NAME-SURNAME: UNIT: Force and Motion SUBJECT: Universal Gravitation CLASS:11 NUMBER: In this chapter, we study the law of universal gravitation. We emphasize a description of planetary motion because astronomical data provide an important test of this law’s validity. We then show that the laws of planetary motion developed by Johannes Kepler follow from the law of universal gravitation and the principle of conservation of angular momentum. We conclude by deriving a general expression for the gravitational potential energy of a system and examining the energetic of planetary and satellite motion. Newton’s law of universal gravitation states that every particle in the Universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. If the particles have masses m1 and m2 and are separated by a distance r, the magnitude of this gravitational force is where G is a constant, called the universal gravitational constant. Its value in SI units is G =6.674 x 10-21 Nm2/kg2 This force is directed toward the center of the Earth. Free-Fall Acceleration and the Gravitational Force We have called the magnitude of the gravitational force on an object near the Earth’s surface the weight of the object, where the weight is given by Equation ………………… Equation ……………….is another expression for this force. Therefore, we can set Equations equal to each other to obtain Now consider an object of mass m located a distance h above the Earth’s surface or a distance r from the Earth’s center, where r =RE + h. The magnitude of the gravitational force acting on this object is g decreases with increasing altitude. Because an object’s weight is mg, we see that as r →∞ the weight of the object approaches zero. 1) The gravitational force between two objects is proportional to A) the distance between the two objects. B) the square of the distance between the two objects. C) the product of the two objects. D) the square of the product of the two objects. 5) As a rocket moves away from the Earth's surface, the rocket's weight A) increases. B) decreases. C) remains the same. D) depends on how fast it is moving. 2) Two objects attract each other gravitationally. If the distance between their centers is cut in half, the gravitational force A) is cut to one fourth. B) is cut in half. C) doubles. D) quadruples 6) Suppose a satellite were orbiting the Earth just above the surface. What is its centripetal acceleration? A) smaller than g B) equal to g C) larger than g D) Impossible to say without knowing the mass. 3) Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the gravitational force between them is F. The masses are changed to 2m1 and 2m2, and the distance is changed to 4r. What is the magnitude of the new gravitational force? A) F/16 B) F/4 C) 16F D) 4F 4) The acceleration of gravity on the Moon is one-sixth what it is on Earth. An object of mass 72 kg is taken to the Moon. What is its mass there? A) 12 kg B) 72 kg C) 72 N D) 12 N 7) A hypothetical planet has a mass of half that of the Earth and a radius of twice that of the Earth. What is the acceleration due to gravity on the planet in terms of g, the acceleration due to gravity at the Earth? A) g B) g/2 C) g/4 D) g/8 8) The acceleration of gravity on the Moon is one-sixth what it is on Earth. The radius of the Moon is one-fourth that of the Earth. What is the Moon's mass compared to the Earth's? A) 1/6 B) 1/16 C) 1/24 D) 1/96 9) The gravitational attractive force between two masses is F. If the masses are moved to half of their initial distance, what is the gravitational attractive force? A) 4F B) 2F C) F/2 D) F/4 10) An astronaut goes out for a "spacewalk" at a distance above the Earth equal to the radius of the Earth. What is her acceleration due to gravity? A) zero B) g C) g/2 D) g/4 11) A satellite encircles Mars at a distance above its surface equal to 3 times the radius of Mars. The acceleration of gravity of the satellite, as compared to the acceleration of gravity on the surface of Mars, is A) zero. B) the same. C) one-third as much. D) one-sixteenth as much. 12) An object weighs 432 N on the surface of the Earth. The Earth has radius r. If the object is raised to a height of 3r above the Earth's surface, what is its weight? A) 432 N B) 48 N C) 27 N D) 0 N Homework 1) During a lunar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Earth between the Moon and the Sun. The Moon has a mass of 7.36 × 1022 kg; the Earth has a mass of 5.98 × 1024 kg; and the Sun has a mass of 1.99 × 1030 kg. The separation between the Moon and the Earth is given by 3.84 × 108 m; the separation between the Earth and the Sun is given by 1.496 × 1011 m. (a) Calculate the force exerted on the Earth by the Moon. (b) Calculate the force exerted on the Earth by the Sun. (c) Calculate the net force exerted on the Earth by the Moon and the Sun. Homework2) A 2.10-kg brass ball is transported to the Moon. (a) Calculate the acceleration due to gravity on the Moon. The radius of the Moon is 1.74 × 106 m and the mass of the Moon is 7.35 × 1022 kg. (b) Determine the mass of the brass ball on the Earth and on the Moon. (c) Determine the weight of the brass ball on the Earth. (d) Determine the weight of the brass ball on the Moon. Satellites and “Weightlessness” Satellites are routinely put into orbit around the Earth. The tangential speed must be high enough so that the satellite does not return to Earth, but not so high that it escapes Earth’s gravity altogether. The satellite is kept in orbit by its speed – it is continually falling, but the Earth curves from underneath it. Consider a satellite of mass m moving in a circular orbit around the Earth at a constant speed v and at an altitude h above the Earth’s surface as illustrated in Figure (A) Determine the speed of satellite in terms of G, h, RE (the radius of the Earth), and ME (the mass of the Earth). SOLUTION Conceptualize Imagine the satellite moving around the Earth in a circular orbit under the influence of the gravitational force. This motion is similar to that of the space shuttle, the Hubble Space Telescope, and other objects in orbit around the Earth. Categorize The satellite must have a centripetal acceleration. Therefore, we categorize the satellite as a particle under a net force and a particle in uniform circular motion. Analyze The only external force acting on the satellite is the gravitational force, which acts toward the center of the Earth and keeps the satellite in its circular orbit Apply the particle under a net force and particle in uniform circular motion models to the satellite: Solve for v, noting that the distance r from the center of the Earth to the satellite is r = RE +h 13) Consider a small satellite moving in a circular orbit (radius r) about a spherical planet (mass M). Which expression gives this satellite's orbital velocity? A) v = GM/r B) (GM/r)1/2 C) GM/r2 D) (GM/r2)1/2 14) Satellite A has twice the mass of satellite B, and rotates in the same orbit. Compare the two satellite's speeds. A) The speed of B is twice the speed of A. B) The speed of B is half the speed of A. C) The speed of B is one-fourth the speed of A. D) The speed of B is equal to the speed of A. 15) A person is standing on a scale in an elevator accelerating downward. Compare the reading on the scale to the person's true weight. A) greater than their true weight B) equal to their true weight C) less than their true weight D) zero 16) A satellite is in a low circular orbit about the Earth (i.e., it just skims the surface of the Earth). What is the speed of the satellite? (The mean radius of the Earth is 6.38 × 106 m.) A) 5.9 km/s B) 6.9 km/s C) 7.9 km/s D) 8.9 km/s 17) A satellite is in a low circular orbit about the Earth (i.e., it just skims the surface of the Earth). How long does it take to make one revolution around the Earth? (The mean radius of the Earth is 6.38 × 106 m.) A) 81 min B) 85 min C) 89 min D) 93 min Homework3) A satellite is in circular orbit 230 km above the surface of the Earth. It is observed to have a period of 89 min. What is the mass of the Earth? (The mean radius of the Earth is 6.38 × 106 m.) A) 5.0 × 1024 kg B) 5.5 × 1024 kg C) 6.0 × 1024 kg D) 6.5 × 1024 kg Objects in orbit are said to experience weightlessness. They do have a gravitational force acting on them, though! The satellite and all its contents are in free fall, so there is no normal force. This is what leads to the experience of weightlessness. Kepler’s Laws Kepler’s complete analysis of planetary motion is summarized in three statements known as Kepler’s laws: 1. All planets move in elliptical orbits with the Sun at one focus. 2. The radius vector drawn from the Sun to a planet sweeps out equal areas in equal time intervals. 3. The square of the orbital period of any planet is proportional to the cube of the semimajor axis of the elliptical orbit. Because the gravitational force provides the centripetal acceleration of the planet as it moves in a circle, we model the planet as a particle under a net force and as a particle in uniform circular motion and incorporate Newton’s law of universal gravitation, 18) Who was the first person to realize that the planets move in elliptical paths around the Sun? A) Kepler B) Brahe C) Einstein D) Copernicus 19) The speed of Halley's Comet, while traveling in its elliptical orbit around the Sun, A) is constant. B) increases as it nears the Sun. C) decreases as it nears the Sun. D) is zero at two points in the orbit. 20) Let the average orbital radius of a planet be r. Let the orbital period be T. What quantity is constant for all planets orbiting the Sun? A) T/R B) T/R2 C) T2/R3 D) T3/R2 21) A planet is discovered to orbit around a star in the galaxy Andromeda, with the same orbital diameter as the Earth around our Sun. If that star has 4 times the mass of our Sun, what will the period of revolution of that new planet be, compared to the Earth's orbital period? A) one-fourth as much B) one-half as much C) twice as much D) four times as much Homework 4) Two moons orbit a planet in nearly circular orbits. Moon A has orbital radius r, and moon B has orbital radius 4r. Moon A takes 20 days to complete one orbit. How long does it take moon B to complete an orbit? A) 20 days B) 80 days C) 160 days D) 320 days Gravitational Potential Energy the gravitational force between two particles varies as 1/r 2, we expect that a more general potential energy function—one that is valid without the restriction of having to be near the Earth’s surface—will be different from U = mgy. Gravitational potential energy of the Earth–particle system When two particles are at rest and separated by a distance r, an external agent has to supply energy at least equal to Gm1m2/r to separate the particles to an infinite distance. It is therefore convenient to think of the absolute value of the potential energy as the binding energy of the system. If the external agent supplies energy greater than the binding energy, the excess energy of the system is in the form of kinetic energy of the particles when the particles are at an infinite separation. Escape Speed Suppose an object of mass m is projected vertically upward from the Earth’s surface with an initial speed vi as illustrated in Figure .We can use energy considerations to find the minimum value of the initial speed needed to allow the object to move infinitely far away from the Earth As the object is projected upward from the surface of the Earth, v = vi and r = ri = RE. When the object reaches its maximum altitude, v = vf = 0 and r =rf = rmax. Because the total energy of the isolated object– Earth system is constant, Traveling at this minimum speed, the object continues to move farther and farther away from the Earth as its speed asymptotically approaches zero. Letting rmax →∞ ` and taking vi = vesc gives This expression for vesc is independent of the mass of the object. In other words, a spacecraft has the same escape speed as a molecule. Furthermore, the result is independent of the direction of the velocity and ignores air resistance. 22) a) What is the escape velocity on a planet radius 500 km and whose surface gravity is 3 m/s2? b) How high will a particle rise if it leaves the surface of the planet with a vertical velocity of 1000m/s? 23) A rocket ship takes off from the earth on a trip to Jupiter with a stopover on the moon. Find the amount of energy required to escape from these two bodies relative to that required escaping from Earth. Energy Considerations in Planetary and Satellite Motion Consider an object of mass m moving with a speed v in the vicinity of a massive object of mass M, where M >> m. The system might be a planet moving around the Sun, a satellite in orbit around the Earth, or a comet making a one-time flyby of the Sun. If we assume the object of mass M is at rest in an inertial reference frame, the total mechanical energy E of the two-object system when the objects are separated by a distance r is the sum of the kinetic energy of the object of mass m and the potential energy of the system, given by Equation Newton’s second law applied to the object of mass m gives the escape speed of an object in orbit around the Earth 24) a)Does it take more energy to get a satellite up to 1500 km above the earth surface than to put it in orbit once it is there? b) What about 3000 km? c) What about 4500 km? (radius of the earth is 6000km)