Download MTH 156 Week 5 CheckPoint -- Due Day 5 (Friday

MTH 156 Week 5 CheckPoint -- Due Day 5 (Friday)
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NAME:__________________________________________
MTH 156 Week 5 CheckPoint -- Due Day 5 (Friday, September 26th )
Instructions: In order to complete your assignment in an organized and efficient
manner, please use this template to type your work and answers. Save this
template to your computer, complete the problems (showing all work), and post
as an attachment to your Individual forum.
No work = half credit for correct answers and no credit for incorrect answers
*Point may be deducted if Equation Editor is not used to format mathematical
sysmbols appropriately.
PROBLEM
Section 4.1 #24
TYPE YOUR SOLUTIONS
AND YOUR WORK HERE
(0,4), (1,0), (1,6), (2,2), (2,8), (3 4), (4,0), (4,6),
(5,2), (5,8), (6,4), (7,0), (7,6), (8,2), (8,8), (9,4)
Section 4.1 #32
(a) false, remainder =2
(b) false, 24 is a multiple of 8
(c) true, the answer = 1
(d) false, expression undefined
(e) true, every number divides 0
(f) false, remainder = 5
(g) true (provided n is an integer) The expression
simplifies to n^2
(h) true, if n^2 = m, m/n = n
Section 4.1 #46
(a) false: Only 25 integers are divisible by four.
Given n from 1 to 25, these integers are of the
form n*4.
(b) false, counterexample: 4
(c) true
(d) false, counterexample: 12
Section 4.1 #84
A number n divides m if m/n is an integer.
A number n is a multiple of m if n/m is an integer.
Also, finding common multiples is necessary to
find common denominators of fractions so that
they can be added and subtracted.
Section 4.2 #12
3, 7, 4, 13, 17
Section 4.2 #26
1078 = 2*7^2*11
3315 = 3*13*13*17
The two numbers do not share any prime factors.
MTH 156 Week 5 CheckPoint -- Due Day 5 (Friday)
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Section 4.2 #34
LCM of 18 and 30: 90
Chapter 4 Review #2
sqrt(841) = 29
Factor Test Theorem
Chapter 4 Review #4
(a) number is even
(b) sum of digits is divisible by 3
(c) last two digits are divisible by 4
(d) last digit is 0 or 5
(e) number is divisible by 2 and by 3
(a) false, counterexample: n=3
(b) true
(c) false, counterexample: n=4
Chapter 4 Review #6
Chapter 4 Review #8
97 and 223 (I used the chart)
Chapter 4 Review #10
48 = 2^4*3
So, the number of factors equals 5*2 = 10
Chapter 4 Review #12
Listing for 24: 24, 48, 72, 96
Listing for 32: 32, 64, 96 (96 is LCM)
Prime factorization for 24: 2^3*3
Prime factorization for 32: 2^5
So, LCM = 2^5*3 = 96
Chapter 4 Review #14
a*b = 180
Therefore, LCM(a,b)*GCF(a,b) = 180
So the GCF of a and b is 180/60 = 3
Chapter 4 Review #16
3 and 2 are relatively prime, whereas 2 and 4 are
not.
Chapter 4 Review #18
The first numbers in the first set all have exactly 4
distinct factors. Two more numbers with this
characteristic are 14 and 35.
Chapter 4 Review #20
No – I ran a computer program calculating the
prime numbers generated by 6*i+1 for i=1 to n,
with n = 1000. The answer was 454. I tried other
values for n as well, and the number of primes
was always less than 50%.
MTH 156 Week 5 CheckPoint -- Due Day 5 (Friday)

What are two standards
that relate to the content
addressed this week?

Discuss the ways in
which this series of
problems meets the
standards.
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Finished? I encourage you to go back and check each answer. Did you show all your
work? Did you label every answer?