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Use the distributive property to factor each polynomial. 12mn + 80m2 Find the GCF for each term: 12mn = 2 2 3 m n 80 m2 = 2 2 2 2 5 m m So GCF = 4m Write each term as the product of the GCF and its remaining factors. 12mn + 80m2 = 4m(3n) + 4m(2 2 5 m) = 4m(3n) + 4m(20m) = 4m(3n + 20m) Check your answer by doing distributive Try again: 14c3 – 42c5 – 49c4 14c3 = 2 7 c c c 42c5 = 2 3 7 c c c c c 49c4 = 7 7 c c c c So GCF = 7c3 … take 7c3 “out” of each term 14c3 = 7c3 (2) 42c5 = 7c3(6c2) 49c4 = 7c3(7c) 7c3(2 – 6c – 7c) Check your answer by distributing! Factor by grouping: 6ax + 3ay + 2bx + by = (6ax + 3ay) + (2bx + by) = 3a(2x + y) + b(2x + y) parenthesis should turn out to be identical = (3a + b)(2x + y) Check by using the FOIL method!! Try again: 6xy – 8x + 15y – 20 = (6xy – 8x) + (15y – 20) = 2x(3y – 4) + 5(3y – 4) = (2x + 5)(3y – 4) You could also regroup the terms differently!! TRY (6xy + 15y) + (-8x – 20) = 3y(2x + 5) + -4(2x + 5) = (3y + -4)(2x + 5) or (3y – 4)(2x + 5) Check by using the FOIL method!! Solve equation by factoring: 9x2 + x = 0 factor out the GCF x(9x + 1) = 0 use the zero product property x=0 or 9x + 1 = 0 9x = -1 x = -1/9 check your answers, plug them in Try some more: (r – 3)(r + 2) = 0 use the zero product property r – 3 = 0 or r + 2 = 0 r=3 or r = -2 x2 = -3x move -3x over to left x2 + 3x = 0 factor out x x(x + 3) = 0 use zero product prop. x = 0 or x+3=0 x = -3 check your answers, plug them in Solve equation by factoring: 9x2 + x = 0 factor out the GCF x(9x + 1) = 0 use the zero product property x=0 or 9x + 1 = 0 9x = -1 x = -1/9 check your answers, plug them in Try some more: (r – 3)(r + 2) = 0 use the zero product property r – 3 = 0 or r + 2 = 0 r=3 or r = -2 x2 = -3x move -3x over to left x2 + 3x = 0 factor out x x(x + 3) = 0 use zero product prop. x = 0 or x+3=0 x = -3 check your answers, plug them in