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Name: _____________________________ Date: ______________________ Color: __________ Unit 9: Systems of Linear Equations/Inequalities Study Guide Knowledge and Understanding Math 1. What are the possible solutions for a system of equations? A system of linear equations can have one solution, no solutions, or many solutions. 2. What are all methods you can use to solve a system of equations? Table Graph Substitution Linear Combinations Set Equal Multiply 1st 3. Is it possible for a system of inequalities to have no solution? Explain. 4. is possible of a system of linear inequalities to have no solution. If the two equations are parallel and are shaded away from each other the inequality has no solution. 5. Is (8, 5) the solution to this system of equations? 5x – 4y = 20 3y = 2x + 1 5x – 4y = 20 3y = 2x + 1 5(8) – 4(5) = 20 3(5) = 2(8) + 1 40 – 20 = 20 15 = 16 + 1 20 = 20 15 = 17 True False 5. Not a Solution 5. Graph the system of equations. From the graph, identify the solution. x>2 y<3 6. Solve this system of equations using any method you choose: 5y + 2x = 5x + 1 3x – 2y= 3 + 3y 5y + 2x = 5x + 1 - 5x – 5x 5y – 3x = 1 -3x + 5y = 1 3x – 2y = 3 + 3y - 3y - 3y 3x – 5y = 3 -3x + 5y = 1 3x – 5y = 3 0=4 No Solution 6. No Solution 7. Is (4, -2) a solution to the system of inequalities: x<5 x + 2y > 1 x<5 x + 2y > 1 4<5 4 + 2(-2) > 1 True 4–4>1 0>1 False 7. Not a Solution 8. Graph this system of inequalities: y>x–3 m=1 b = -3 x+y<2 -x -x y < -x + 2 m = -1 b=2 What is the solution? Anything in gray 9. You are painting the white lines around the perimeter of a tennis court. You measure and find that the perimeter is 228 feet and the length is 42 feet longer than the width. Write and solve a system of linear equations to find the length and width of the tennis court. Let w be the width of the tennis court and let ℓ be the length of the tennis court. 228 = 2L + 2W 2L + 2W = 228 L - 42 = W L - 42 = W 2L + 2(L - 42) = 228 78 - 42 = W 2L + 2L - 84 = 228 36 = W 4L - 84 = 228 + 84 + 84 4L = 312 L = 78 10. In an academic competition, scoring is based on a written examination and an oral presentation. The written examination cannot exceed 65 points and the oral presentation cannot exceed 35 points. Write and graph a system of inequalities for the school team can receive. Find 1 possible solution. x = Written y = Oral x < 65 y < 35 Graph counted by 10’s. No negatives are shaded since negative points cannot be earned. 11. Solve the system of equations: 5x = 1 – 3y + 3y + 3y 5x + 3y = 1 2x + 9y = 16 -3(5x + 3y = 1) 2x + 9y = 16 5x = 1 – 3y 2x + 9y = 16 -15x – 9y = -3 -13x = 13 x = -1 2x + 9y = 16 2(-1) + 9y = 16 -2 + 9y = 16 +2 +2 9y = 18 y=2 12. Tickets for a school play cost $4 for adults and $2 for students. At the end of the play, the school sold a total of 105 tickets and collect $360. a. Write a linear system. Let x be the number of adult tickets sold and let y be the number of student tickets sold. 4x + 2y = 360 x + y = 105 b. Find the number of adult tickets sold and the number of student tickets sold. 4x + 2y = 360 4x + 2y = 360 x + y = 105 -2(x + y) = 105 -2x -2y = -210 75 + y = 105 2x = 150 -75 -75 x = 75 y = 30 75 adult tickets and 30 student tickets 13. Write an equation for each cookie and cake then solve the system. After how many hours does the number of cookies equal the number of cakes? How many cookies and cakes will you have? x = hours y = total y = 1000x + 15500 y = 250x + 38000 1000x + 15500 = 250x +38000 - 250x - 250x 750x + 15500 = 38000 - 15500 - 15500 750x = 22500 x = 30 hours Sweet Number Started with Cookie 15,500 Cake 38,000 Baked per hour 1000 250 y = 1000x + 15500 y = 1000(30) + 15500 y = 30,000 + 15,500 y = 45,500 14. A hotel rents a double-occupancy room for $20 more than single-occupancy room. One night, the hotel took in $3115 after renting 15 double-occupancy rooms and 26 single-occupancy rooms. Write and solve a linear system to find the cost of renting a double-occupancy room and the cost of renting a single-occupancy room. x = single occupancy room 26x + 15(x + 20) = 3115 x + 20 = y y = double occupancy room 26x + 15x + 300 = 3115 68.66 + 20 = y x + 20 = y 41x + 300 = 3115 $88.66 = y 26x + 15y = 3115 41x = 2815 x = $68.66 15. For a system of linear equations to have no solutions what must be true? The system of linear equations must be parallel (have the same slope) in order to have no solution. 16. Describe the steps needed to solve the linear system below. 1. 2. 3. 4. 5. 3x - 5y = 8 2x + 4y = 6 Multiply the first equation through by 4. Multiply the second equation through by 5. Add the equations together causing the y’s to be eliminated. Solve for x. Plug your solution into one of the original equations and solve for y. 17. What would be the value of y in the first equation if you choose to solve the system of equations below by substitution? 4x – 2y = -3 8x + 6y = 48 4x – 2y = -3 - 4x - 4x -2y = -4x – 3 ÷-2 ÷ -2 y = 2x +3/2 20. A website allows users to download individual songs or an entire album. All individual songs cost the same to download, and all albums cost the same to download. Ryan pays $14.94 to download 5 individual songs and 1 album. Seth pays $22.95 to download 3 individual songs and 2 albums. How much does the website charge to download 7 individual songs and 3 albums? x = songs -2(5x + 1y = 14.94) -10x – 2y = -29.88 5x + y = 14.95 y = albums 3x + 2y = 22.95 3x + 2y = 22.95 5(.99) + y = 14.95 5x + 1y = 14.94 -7x = -6.93 4.95 + y = 14.95 3x + 2y = 22.95 x = 0.99 y = 10.00 7x + 3y = ? 7(.99) + 3(10) = 6.93 + 30 = $36.93