Download SCIE 0900 REVIEW FOR TEST 2

SCIE 0900 REVIEW FOR TEST 2
For the test be sure to know how to do everything listed below. Plan to able to show your work for
any problems.
Review for Mean, Mode, Median, Range and Standard Deviation
Know how to determine the
Mean
Median
Mode
Range
Standard deviation:
Range
Show your work:
Cheryl took 7 math tests in one marking period. Her grades were as follows:
89%, 73%, 84%, 91%, 87%, 77%, 94%
Mean ____ Mode ____ Median _____ Range ______ SD __________
You are given the following masses for some rocks.
22.3g 50.2g
24.0g 22.3 g 44.6g 19.7g
Calculate the :
Mean ____ Mode ____ Median _____ Range ______ SD ___________
Probability Review
Terms:
Probability
Sample Space
How can probability be expressed? What are the different ways?
An ice chest contains 14 cans of pop. To be precise, there are 3 cans of Coke, 5 cans of Pepsi, 4 cans of
Sprite, and 2 cans of Dr. Pepper. A can is selected at random.
Find the following probabilities. Give your answers as a fraction.
1. Favorable outcome = selecting a can of Dr. Pepper _____________
2.
Favorable outcome = The can selected is Coke __________
3.
Favorable outcome = The can selected is Sprite _________
4.
What is the sample space of this situation? ________________________________
5.
Situation: You select a Pepsi and then I select a Coke
What is the probability that I select a Pepsi first?
What is the probability that you select a Coke second?
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Scientific Method Review
What are the 4 steps?
Be prepared to answer questions from a similar problem as given below:
You are a scientist studying parakeets. Parakeets are birds without crests (decorative feathers on the tops of their
heads). You have noticed that in some other species of birds, the prettier the crest of the male, the more females the
male is able to attract. You wonder if a male parakeet with a crest would attract more female parakeets. You hypothesize
that since other male birds with impressive crests attract more females, that male parakeets with crests will attract more
female parakeets.
To test this hypothesis, you obtain 3 identical male parakeets. To the first male (male A), you attach a single
yellow feather on the top of his head. To the second male (male B), you attach a cluster of several yellow, fluffy feathers
on the top of his head. You do not attach a crest to the third male (male C), and he remains in his natural state.
You then place the males in 3 cages and show the males to 10 female parakeets. You record the amount of time
each female spends looking at each male. Male A received an average of 17 minutes of attention. Male B received an
average of 20 minutes of attention. Male C received an average of 12 minutes of attention.
1. What was your hypothesis (what led you to do this experiment)?________________________________
_____________________________________________________________________________________
2. What was the variable in your experiment? _________________________________________________
______________________________________________________________________________________
3. What was the control in your experiment? _________________________________________________
______________________________________________________________________________________
4. What can you conclude from this experiment? ______________________________________________
______________________________________________________________________________________
5. Does the data support your original hypothesis?_____________________________________________
Explain. _______________________________________________________________________________
Adding and Subtracting Figs
Answer will have the same number of decimal places as the least accurate measurement used in the
calculation.
84.3g + 12.3g + 36.3451g =
351L – 16.55L – 30.5L =
Multiplying and Dividing sig figs
Answer will be rounded to the same number of significant figures as the measurement with the fewest
significant figures
2003.22cm x 11.5cm =
0.334m x 1.39m =
2500L ÷ 3 =
635.45mm ÷ 15.3 =
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Making Solutions
% m/m = mass of solute (g) x 100%
mass of solution (g)
% m/m =
grams of solute
X 100%
units are % m/m or %v/v
(grams of solvent) + (grams of solute)
A 546 g solution is prepared by dissolving 35.0 g of sugar in sufficient water. What is the concentration?
A solution is prepared by dissolving 65.0 g of sucrose in 225.0 mL of water. What is the concentration of the
solution?
Dimensional Analysis –use chart of metric conversions1. Set up conversion factor
a. Place given unity as the denominator
b. Place desired unit as the numerator
c. Place a “1” in front of the large unit
d. Place a 10 in front of the smaller unit
e. Repeat b-d until reaching the final answer
2. Cancel Units – only the desired units should be left
3. Solve the problem
Use dimensional analysis to convert
2350 mg = __________ cg
0.25g = ____________ mg
Page 3
Know the definitions of the following are or what they refer to:
Mean
Aqueous solution
Mode
Solubility
Median
Saturated solution
Range
Rate of Dissolving – ways to do
Standard Deviation
Concentration
Probability
Dilute
Outcomes
Concentrated
Favorable outcome
Acid
Sample space
Base
Scientific Method
pH and pH scale
Hypothesis
Litmus paper
Quantitative
pH hydrion paper
Qualitative
Buffer
Theory
Osmosis
Law
Diffusion
Applied science
Hypertonic
Pure Science
Hypotonic
Matter
Isotonic
Potential energy
Physical Change
Kinetic energy
Chemical Change
Law of Conservation of Energy
3 states of matter
Chemical formula
Intensive properties
Element
Atom
Compound
Nucleus
Solution
Electron
Solute
Proton
Solvent
Neutron
Universal solvent
Molecule
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