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Problem #4 BZ of rectangular Lattice Phys. 555/342: Ch.6B(2007) Problem #4 BZ of rectangular Lattice Phys. 555/342: Ch.6B(2007) Shift in Chemical Potential 2-D Density of States in 2-D A 2m g(")d" = d" 2 2# h 1 f FD (") = exp[(" # µ) /kT] + 1 ! # N= $ g(") f FD (")d" 0 h2 2"n = 2m ! % & 0 d# exp[(# $ µ) /kT] + 1 h2 2"n = #F (T = 0) 2m Phys. 555/342: Ch.6B(2007) ! ! ! h2 2"n = 2m % & 0 d# exp[(# $ µ) /kT] + 1 Change variables x=(ε−µ)/kT $ 0 h2 kTdx kTdx 2"n = % x = % x + 2m # µ / kT e + 1 # µ / kT e + 1 0 $ 1 ' h 2 2"n = * & x #1)dx + 2m kT # µ / kT % e + 1 ( 0 h 2 2"n #dx = $ #x + 2m kT # µ / kT e + 1 % $ 0 + * 0 $ % 0 kTdx ex + 1 dx + µ /kT x e +1 dx + µ /kT x e +1 µ / kT % h 2 2"n # µ dx dx = # $ #x + $ x 2m kT +1 0 e +1 0 e h 2 2"n If kT<<µ = µ = #F 2m kT ! $ h 2 2"n # µ dx =+ % x 2m kT µ / kT e + 1 Phys. 555/342: Ch.6B(2007) Effective Mass m* me is “true” mass of an electron In a crystal we have an effective mass m* Apply a field E for time δt work = "eE#x "# = $eE • vG"t But"# $ % k#(k) • "k = hvG • "k ! # k%(k) with " "vG = # k$ (k) = ! ! ! So " "h#k = $eE#t h • h k = $eE Phys. 555/342: Ch.6B(2007) Effective Mass m*-Acceleration 2 dv i 1 d 1 $ # dk j ai = = (" k#(k)) i = % dt h dt h j $k i$k j dt 2 dv i 1 #$ Giving " " = 2% (&eE) dt h j #ki#k j ! ! dv #eE Classically " " = a = dt me 2 h " (me ) ij = 2 # $ /#ki#k j Phys. 555/342: Ch.6B(2007) Effective Mass m* 2 h (m ) = 2 # $ /#ki#k j " e ij • Acceleration is not in direction of E • flat bands have high effective mass • Effective mass can and is negative!! ! One Dimensional Spherical bands 2 h m = 2 2 # $ / #k " e Phys. 555/342: Ch.6B(2007) ! Warning! Different Effective Masses Specific Heat 2 2 B " Nk # $ V ' CV = mCV & 2 ) 2 % 3" N ( h 2/3 T 2 ! ! # 2 or " "CV = k B g($F )T 3 g(ε) is always positive the heat capacity is positive m*CV is different from m*--in fact mCV=|m*|1/3 Phys. 555/342: Ch.6B(2007) Metals, semiconductor, Insulators Phys. 555/342: Ch.6B(2007) Effective Mass m* 1-D Band Structure " k$(k) vG = " k# (k) = h Effective Mass m* What does a negative Effective mass mean? ! m* diverges m*<0 Phys. 555/342: Ch.6B(2007) Effective Mass m* Direct Gap Semiconductor We are going to talk about Holes! Phys. 555/342: Ch.6B(2007) Effective Mass m* Indirect Gap Semiconductor Direct excitation Indirect Excitation Needs momentum Phys. 555/342: Ch.6B(2007) Holes: Photoabsortpion Absorption of a photon of energy h" and negligible wavevector takes and electron from state ke with energy E from a valence band state to a conduction band state Q. Total wave vector of valence band after The valence band is treated excitaiton is -ke. as a hole with kh=-ke. This is ! the wavevector ascribed to the hole. The valence band is describe as occupied by one hole. Since ke=-kh this is the same as having an electron at G. For the entire system the total wavevector is zero, ke+kh=0. Phys. 555/342: Ch.6B(2007) Construction of a one-Dimensional Hole band The upper half of the figure shows thehole band that simulates the dynamics of a hole, constructed by inversion of the vlence band at the origin. The wavevector and energy of the hole are equal, butr opposite in sign, to the k and E of the empty electron orbital in the valence band. Phys. 555/342: Ch.6B(2007) Time evolution of a hole in the presence of a field E At t=0 (a) all states are filled except F at the top of the band. The velocity vx=0 . (b) A field is applied in x direction. The force is in the -k direction. All the electrons make a transition in the -k direction. (c) After another interval of time moves to D. Phys. 555/342: Ch.6B(2007) Time evolution of a hole in the presence of a field E Same picture except in the 1-D hole band picture Phys. 555/342: Ch.6B(2007) Hall Effect The Hall field EH is established due to the charge build-up on opposing faces in the dirfection normal to the applied magnetic and electric fields, resulting from the Lorentz force acting on the moving electrons or Holes. In steady state, the force -e EH balances the Lorentz force. Phys. 555/342: Ch.6B(2007) Hall Effect In Steady state Since vy=0 ! ! jx B E y = vx B = " ne E = "• j Ey B " xy = # " xy = = j x ne Hall Coefficient RH ! ! 0 = "e(E y " v x B) E H = R H Bxj Ey " xy 1 RH = = =# j x Bz Bz ne Phys. 555/342: Ch.6B(2007)