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RattiSeattle & McWaters, College North Community College Algebra and Trigonometry and A Right T SpringPrecalculus: 2012 MATH 142, Section 03, 10 PRECALCULUS II Chapter Tests CHAPTER Form A9 1) y 11 2) ellipse; 2 4 11 x 4 4) parabol 5) hyperbo Ratti & McWaters, College Algebra and Trigonometry and Precalculus: A Right Triangle Appr 2 10(Tests metry and Precalculus: AChapter Right Triangle 2e2 Answers x 7)Approach, ( y 6) Form A 6) 5) 3) 5 2 2 (x 7) 2 ( y 3)2 circle; y 11 4 11 x 4 3) 1) 4) 2) 4 2 2 1 81 4 6 x 2 parabola; y 2 5 ( x 7) ( y 6) 2 ellipse; 1 42 ( x 2) 2 52 ( y 3)2 hyperbola; 1 2 32 2 52 ( y 3) 81 circle; ( x 7) 4) 5) 2 parabola; y 5 hyperbola; 2) 2 (x 32 Center: 1, 2 Foci: 1, 2 6) 5 Vertices: 1, 2 Center: 1, 2 Center: 1, 2 Foci: 1, 2 Foci: 1, 2 5 Vertices: 1, 2 5 Vertices: 1, 2 3 3 7) Center: Foci: 7) Center: Center: Foci: Foci: 2,3 2,3 Vertices: 34 2,3 3 2,3 2,3 Vertices: 2,3 Vertices: 2,3 34 2,3 3 2,3 7) Center: Foci: 2,3 2,3 Vertices: 34 2,3 3 Ratti and Precalculus: A Right Triangle Appro Ratti&&McWaters, McWaters,College CollegeAlgebra Algebraand andTrigonometry Trigonometry and Precalculus: A Right Triangle App Chapter Chapter1010Tests Tests 8)8) Vertex: Vertex:1, 41, 4 29 Focus: 29 Focus:1, 1, 8 8 35 Directrix: Directrix:y y 8 9) 9) 10) 10) 11) 11) 16) 16) y y 3 3 2 x 92 x 9 7 7 1 1feet 3 feet 3 3 b) 3feet 4 feet b) 4 2 x 2 4(1.5) y a) x 4(1.5) y a) b) 13.5 feet b) 13.5 feet ( y 10)2 2 ( x 12) 2 2 ( y 210) ( x 212) 1 ; Foci: 12,10 29 20 2 21 2 1 ; Foci: 12,10 29 20 21 a) a) Form B 12) 12) 13) 13) 14) 14) 15) 15) 35 8 4) 2 2 ( y 3) 2 2 ( x2 4) ( y 3) 7 2 122 2 7 12 2 2 x 2y 2 x y 1 52 2 4 2 2 1 5 4 2 ( x 2) 2 4 34 (3y 5 ( x 2) 4 4 (y 89.4 feet 89.4 feet (x 2,10 9) (x 12) 4) a) 7 10) x 13) 14) 11) 15) 29 32 y (y y 2 52 b) 42 (x 2)2 3) (y 4 2 5) 4(1.5) y a) x b) 13.5 feet ( y 10)2 ( x 12) 2 202 212 1 ; Foci: 12,10 4) 2 72 x2 y2 52 42 14) (x 2)2 15) 89.4 feet 13) 3 feet 4 3 4 (x 12) 1 1 89.4 feet 16) x2 7 1 122 feet 3 2 2 2 9 29 Ratti & McWaters, College Algebra and Trigonometry and Precalculus: A Right Trian Form BChapter 6 Tests CHAPTER 6 and 8 2 2 circle; ( x2 3) 4) 1) x 13 Form Aparabola; 5) 1)2) 2) 3)3) 2 sin x cos x ( y hyperbola; 5) 49 2 5) 2 4 7 y (x 54.5 n180 or 3 4)2 1 2n 1 180 2 7 11 19 23 31 35 43 47 , , , , , , , 24 24 24 24 24 24 24 24 6) 7) 8) 4 5 3 10 5 7 13 , , 6 6 6 6 , 1888 3737 circle; ( x 4) 4 32 22 Solutions will vary. 2 ( y 1)2 5 19 ( x 5) ellipse; 1 , 2 2 3 21 21 2 4) 5) x (y 4 20 y 9) 5) 10) 2 parabola; 3 119 169 11) 2 2 n 12) 3 2 2 13) 3 4 14) 3 cos143 15) 90 , 233.1 16) 17) cos 200 2 origin cot 5 x cot 258 Form B 1) sin x cos x 9) 2 6 nometry and Precalculus: A Right Triangle Approach, 2e 9) 2 10) 119 169 Answers 3 11) 2 n 2 12) 3 2 2 13) 3 4 cos 200 2 13) πΆππ 445 . πΆππ 115 = πΆππ 85 . πΆππ 115 β¦ since 84° is the reference angle for 445° 14) 3 cos143 15) 115 +A90 , 233.1 πΆππ 85 = Triangle πΆππ 85 . Approach, πΆππ 115 β2e πππ 85. πππ 115 onometry and Precalculus: Right Answers πΆππ 200 = πΆππ 85 . πΆππ 115 β πππ 85. πππ 115 β¦ equation (a) 16) 115 origin πΆππ β 85 = πΆππ 85 . πΆππ 115 + πππ 85. πππ 115 πΆππ 30 17) = πΆππ 85 . cot 5 xπΆππ 115 cot 2 x+ πππ 85. πππ 115 β¦ equation (b) 0 47 24 2 3(a) and equation (b) 9) adding equation 119 10) 115 + 85 + πΆππ (115 β 85) = 2 πΆππ 85 . πΆππ 115 πΆππ 169 πΆππ 200 + πΆππ 30 = 2 πΆππ 85 . πΆππ 115 πΆππ 200 πΆππ 30 2 62 n 11) + = πΆππ 85 . πΆππ 115 9) 2 224 240 12) 3 2 2 πΆππ 200 3 10) πΆππ 85 . πΆππ 115 = + 161 4 3 cos 200 2 13) 11) 22 n 4 14) 32cos143 2 15) 90 ,2233.1 12) 16) 13) 3 sin 310 origin 17) 4cot 5 x cot 2 2x 14) 3 sin 83 15) 36.9 , 270 16) 9) 17) 2 6 y-axis 4 8 x tan 3 x tan