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Transcript
Cases in Subnetting
Case 1
1.
Suppose you are given the IP
address 195.5.5.0 and wish to
connect Springfield and
Bedrock to Southpark. Create
an IP addressing scheme that
will meet the following
requirements:
–
A: Each subnet must
support between 25 and
30 devices.
–
B: You must have enough
subnets to address each
network.
i.
What is the subnet mask for this network?
ii.
What is the broadcast address of the 3rd subnet?
iii.
On the diagram, assign a subnet address to each network and give each
router interface an appropriate IP address for that network.
List of networks
Case 1 Answer
for the 195.5.5.0 network with the subnet mask 255.255.255.224
192.5.5.33/27
Hosts
Network
from
195.5.5.0
195.5.5.1
192.5.5.65/27
Southpark
Broadcast Address
to
195.5.5.30 195.5.5.31
195.5.5.32 195.5.5.33 195.5.5.62 195.5.5.63
192.5.5.34/27
192.5.5.66/27
195.5.5.64 195.5.5.65 195.5.5.94 195.5.5.95
195.5.5.96 195.5.5.97 195.5.5.126 195.5.5.127
195.5.5.128 195.5.5.129 195.5.5.158 195.5.5.159
Springfield
192.5.5.97/27
Bedrock
192.5.5.129/27
195.5.5.160 195.5.5.161 195.5.5.190 195.5.5.191
195.5.5.192 195.5.5.193 195.5.5.222 195.5.5.223
195.5.5.224 195.5.5.225 195.5.5.254 195.5.5.255
-
IP:192.5.5.98/27
SM: 255.255.255.224
GW: 192.5.5.97
IP:192.5.5.130/27
SM: 255.255.255.224
GW: 192.5.5.129
Rules
1. Each router’s interface has to be on a separate network ( You can’t have two different
interfaces on the same network)
2. Each interface on the router has to be assigned an ip address and a subnet mask
3. Routers’ interfaces usually take the first available IP address on a network
4. Switches are layer 2 devices and do not need an IP address to work
5. Each PC on the network must be configured with the correct IP properties. Your PC will net
an IP address and a subnet mask to be able to communicate with other hosts on the same
network. Your PC will net a default gateway to be able to communicate with other hosts on a
different network
6. PCs and their Default Gateway must belong to the same network.
Case 2
•
a.
b.
c.
d.
e.
Given the IP address 199.199.199.172 with a subnet mask of
255.255.255.192. Answer the following:
How many bits were borrowed?
How many subnets have been created?
How many host address per subnet?
What is the subnet address of the network containing the
given IP address?
What is the broadcast address of the network containing the
given IP address?
Case 2 Answer
List of networks
for the 199.199.199.0 network with the subnet mask 255.255.255.192
Hosts
Network
from
Broadcast Address
to
199.199.199.0
199.199.199.1
199.199.199.62
199.199.199.63
199.199.199.64
199.199.199.65
199.199.199.126 199.199.199.127
199.199.199.128 199.199.199.129 199.199.199.190 199.199.199.191
199.199.199.192 199.199.199.193 199.199.199.254 199.199.199.255
A: 2
B: 4
C: 64
D: 199.199.199.128
E: 199.199.1299.191