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Warm-ups 12.4 Surface Areas of Cylinders Lateral Area of a Cylinder A fruit juice can is cylindrical with aluminum sides and bases. The can is 12 centimeters tall, and the diameter of the can is 6.3 centimeters. How many square centimeters of aluminum are used to make the sides of the can? The aluminum sides of the can represent the lateral area of the cylinder. If the diameter of the can is 6.3 centimeters, then the radius is 3.15 centimeters. The height is 12 centimeters. Use the formula to find the lateral area. Lateral area of a cylinder Use a calculator. Answer: About 237.5 square centimeters of aluminum are used to make the sides of the can. A set of toy blocks are sold in a cylindrical shape container. A product label wraps around all sides of the container without any overlaps or gaps. How much paper is used to make the label the appropriate size if the diameter of the container is 12 inches and the height is 18 inches? Answer: about 678.6 in2 Surface Area of a Cylinder Find the surface area of the cylinder. The radius of the base and the height of the cylinder are given. Substitute these values in the formula to find the surface area. Surface area of a cylinder Use a calculator. Answer: The surface area is approximately 2814.9 square feet. Find the surface area of the cylinder. Answer: about 1156.1 ft2 Find the radius of the base of a right cylinder if the surface area is and the height is 10 feet. square feet Use the formula for surface area to write and solve an equation for the radius. Surface area of a cylinder Substitution Simplify. Divide each side by Subtract 264 from each side. Factor. Solve. Since a radius of a circle cannot have a negative value, –22 is eliminated. Answer: The radius of the base is 12 feet. Find the radius of the base of a right cylinder if the surface area is inches and the height is 22 inches. Answer: 14 in. square 12.5 Surface Areas of Pyramids Lateral Area of a Regular Pyramid CANDLES A candle store offers a pyramidal candle that burns for 20 hours. The square base is 6 centimeters on a side and the slant height of the candle is 22 centimeters. Find the lateral area of the candle. We need to find the lateral area of the square pyramid. The sides of the base measure 6 centimeters, so the perimeter is Lateral area of a regular pyramid Multiply. Answer: The lateral area of the candle is 264 square centimeters. CAMPING A pyramidal shaped tent is put up by two campers. The square base is 7 feet on a side and the slant height of the tent is 7.4 feet. Find the lateral area of the tent. Answer: 103.6 ft2 Surface Area of a Regular Pyramid Find the surface area of the regular pyramid to the nearest tenth. To find the surface area, first find the slant height of the pyramid. The slant height is the hypotenuse of a right triangle with legs that are the altitude and a segment with a length that is one-half the side measure of the base. Pythagorean Theorem Use a calculator. Now find the surface area of a regular pyramid. The perimeter of the base is and the area of the base is Surface area of a regular pyramid Use a calculator. Answer: The surface area is 179.4 square meters to the nearest tenth. Find the surface area of the regular pyramid to the nearest tenth. Answer: 89.8 m2 Find the surface area of the regular pyramid. Round to the nearest tenth. The altitude, slant height, and apothem form a right triangle. Use the Pythagorean Theorem to find the apothem. Let x represent the length of the apothem. Pythagorean Theorem Simplify. Now find the length of the sides of the base. The central angle of the hexagon measures and the apothem. Let a represent the measure of the angle formed by a radius Use trigonometry to find the length of the sides. Multiply each side by 9. Multiply each side by 2. Use a calculator. Next, find the perimeter and area of the base. Finally, find the surface area. Surface area of a regular pyramid Simplify. Answer: The surface area is approximately 748.2 square centimeters. Find the surface area of the regular pyramid. Answer: about 298.2 cm2 Homework: p. 657 #10-20 evens p. 663-664 #8-24 evens