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Newton’s Law of Universal Gravitation AP Physics C Mrs. Coyle Isaac Newton • 1666, England (45 years after Kepler). Questions • If the planets are orbiting the sun , what force is keeping them in orbit? • What force keeps the moon in its orbit? • Could the force of gravity be universal? Newton’s Law of Universal Gravitation • Any two objects attract each other with a gravitational force, proportional to the product of their masses and inversely proportional to the square of the distance between them. • The force acts in the direction of the line connecting the centers of the masses. Note • Newton’s Law is universal, it acts between any two masses regardless of how large (planets, stars) or how small (particles, atoms, neutrons) they are. • The gravitational force is weaker than the electrical force. • The gravitational force is one of the 4 fundamental forces in nature. Newton’s Law of Universal Gravitation http://scienceblogs.com/startswithabang/upload/2009/07/meet_our_second_moon/400px-NewtonsLawOfUniversalGravitation.svg.png The Value of G. G= 6.67 x 10-11 N m2 / kg2 Vector Form of Newton’s Law of Universal Gravitation m1m2 F12 G 2 rˆ12 r Note • F12 = -F21 Action-reaction pair. • Gravitation is a field force. • Masses are considered point masses. Henry Cavendish’s experiment determined the proportionality constant G in 1798. http://www.newscientist.com/data/images/archive/1639/16390101.jpg Change of Gravitational Force with Distance • Law of universal gravitation is known as an inverse square law. Why does the moon not fall straight down onto the earth? 2 The gravitational force place the role of the centripetal force. v FM rM Relate Weight and Fg Example Problem • Two spheres of equal mass m are a distance d apart. a)If the mass of one is doubled and the distance between them is reduced to ½d, how does the force change? b) If both masses are doubled and the distance is also doubled how does the force change? Example • An object that of mass 5kg is located at a planet that has 3 times the mass of the earth and half its radius. What is its weight on this planet. The Gravitational Force Inside the Earth • Varies linearly with the distance from the center of the Earth. geff = g r/ REarth Ex: #3 • A 200kg object and a 500kg object are separated by 0.400m. a) Find the net gravitational force exerted by these objects on a 50.0kg object placed midway between them. b) At what position (other than an infinitely remote one ) can the 50kg object be be placed so as to experience a zero force? Ans: a)2.50x10-5 N towards the 500kg object, b)0.245m Ex: #5 • Three uniform spheres are 2 kg, 4kg, 6 kg are located as shown: 2kg 3m 4kg 6kg 4m • Calculate the resultant gravitational force acting on the 4kg object. • Ans: (-10i + 5.93j) x10-11 N